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Test &AgNO (aq) + NaOH(aq) Observation: Equation: Net ionic equation Pb(NO;)(aq) NaOH(aq) Observalin: Equation: Net ionic equation Cu(NO )(aq) NaOH(aq) Observat...

Question

Test &AgNO (aq) + NaOH(aq) Observation: Equation: Net ionic equation Pb(NO;)(aq) NaOH(aq) Observalin: Equation: Net ionic equation Cu(NO )(aq) NaOH(aq) Observation: Equation: Net ionic equation Fe(NO ) (aq) + NaOH(aq) Observation: Equation: Net ionic equation KNO;(aq) NaOH(aq) Observation: Equation: Net ionic equation

Test & AgNO (aq) + NaOH(aq) Observation: Equation: Net ionic equation Pb(NO;)(aq) NaOH(aq) Observalin: Equation: Net ionic equation Cu(NO )(aq) NaOH(aq) Observation: Equation: Net ionic equation Fe(NO ) (aq) + NaOH(aq) Observation: Equation: Net ionic equation KNO;(aq) NaOH(aq) Observation: Equation: Net ionic equation



Answers

Write the net ionic equation and identify the spectator ion or ions in the reaction of nitric acid and magnesium hydroxide. What type of reaction is this? $$\begin{array}{r} 2 \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+2 \mathrm{NO}_{3}^{-}(\mathrm{aq})+\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s}) \rightarrow 4 \mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{Mg}^{2+}(\mathrm{aq})+2 \mathrm{NO}_{3}^{-}(\mathrm{aq}) \end{array}$$

This question wants us to identify the spectator ions in the given equation and then right, the balance net ionic equation. So the spectator ions are ions, which remained unchanged between the left hand side and right hand side of the equation, and we can see that they are the sodium ion, the calcium ion, and this is on both sides of the equation. So once we remove the spectator ions, the Net Ionic equation will be as follows. Um, and given this net ionic equation, when we start looking at the charge and number of Adam's on either side will notice that this equation is balanced as it is, eso no further changes need to be made.

So for this problem, we're gonna want to look at the diagrams in the book. But we do it. We want to write some balance equations am find what the Net ionic equations are so that we can identify any spectator ions. So let's start with a so first looking at the different Adams and compounds we have in this diagram, we're going to write a balanced chemical equation. So we know this to be see you is so fine, that is Equis. And we're just adding the states so that we can a little bit better see what the different components are that we're working with. So now that we have this falling balanced equation, we can look at the different parts and see what can be split into different ions. So we know that you split this up. He's put this up. You can't split this up, but we can also split this up, which means that we're going to see the this component cross out with this component and are so Diem's cross out in this component. So that being said, we can go ahead and write or net Ionic equation now going to do so in a different color student read. So we know, based on what we had left after we crossed now and expect Peter ions is our solid product. I am base on what we know that we crossed out. We know that we crossed out for Spectators. We crossed out in sodium, then in s 04 tu minus. And based on the corresponding colors, we know that the spheres for sodium or gray and the color spheres for this one are blue. Okay, so we're gonna work on our next problem now. And in order to do so, we're gonna look at the diagrams again because this is gonna be what we're balancing our equation off of and how writing the equation. So we're gonna go down a little bit so much so we have room to do be And four b looking at the diagram, we could make the following chemical equation Cool boat, chlorine. Aquarius. You know, show how I balance this as well, so you can understand what we're doing. Just kind of write it out so that we can see regard. So you know, chloride, which is just a table salt and is Aquarius. Okay? So when looking at balancing this. I knew that we were going to need a two because not only do we have to all Christians here and the products we also have to hydrogen and the O. H is together in sodium hydroxide or reactions. So by adding a coefficient of to here to match the O. H. On the product side, I had to Sodium is on the reactive side and only one on the product side. So that's where this second to came in from. So now that we have more fully balanced equation, what we can do next is go ahead and look at doing see net Ionic equation. So we know we have a seal on this side and on this side we have two on each side. So that means that the chlorine is going to inspect your eye on that. We can across out, and the sodium is going to be the same. We have two on each side. It's gonna be what we cross out. So writing what we haven't crossed out, we have cobalt two plus plus two hydroxide, and then we're gonna leave are solid because we couldn't break that up into ions and that's what stays. So we found our Spectators to be sodium again and the Corina, and based on the colors we know the sodium is gray Claure is going to be green First fears And now we can we want to do the last down a little bit more so much. Okay, so we're gonna look again of the diagrams so we can make our fully balanced equation Gonna right. The suasion itself equally is Tess, you IOD i e quiz and then looking, we have so her eye nine. And this is a solid which is important when we're looking at our net Ionic a second my Casio tricked And this is a quiz, and this is the three. So if we look, we know we're gonna be able to cross out Not only are nitrogen is but our oxygen's. So these are gonna be spectator ions, and then our potassium is also gonna be Spectators. So that means we can go ahead and do silver. It's the dine is gonna give us our solid product that we couldn't break up into its ions. And so when we're looking at spectator for this one, we saw that it was that potassium that we talked about talking out that are no. Three months. And we find that the past, um, is red and then we have blue here.

To write the balanced formula and that Ionic equation. The first thing you need to do is I is right, the balanced formula equation and then from there, identify the spectator ions. Eliminate them and what's left is theme net ionic equation. So if we have a beaker with sodium sulfide and a beaker with sodium sulfate and we mix them together, I'm sorry. Sodium sulfide and copper to sulfate, and we mix them together. The copper to sulfate and sodium sulfide will potentially react with each other, forming a precipitate if there is an insoluble product. The insoluble product according to sell ability rules, is copper to sulfide, while sodium sulfate is still soluble. So the complete Ionic equation is where we take everything that's soluble. That's not a solid and separated into their corresponding ions. When we do this, we still have the calcium. I'm sorry. The copper to sulfide together is a solid. We find sodium on both sides to sodium zahn both sides of the equation. This is one of the spectator ions, and in the figure it's gray in color, and sulfate is another spectator ion, which in the figure is green. Once eliminating the spectator ions. What's left is the Net Ionic equation. Copper two plus reacts with sulfide producing copper to sulfide. The next problem shows a beaker with sodium hydroxide and copper to sorry. Cobalt to glow ride so cobalt to chloride and sodium hydroxide. Servas the reactant. When the cat ion switch places, we end up with cobalt to hydroxide, which, according to sell ability rules, is insoluble, so it's a solid and sodium chloride. To balance it, we need to put a two in front of the sodium hydroxide and a two in front of the sodium chloride. Then, to get the complete Ionic equation will separate everything that is soluble into its ions. Cobalt to chloride will produce one cobalt two plus and two chlorides to sodium hydroxide will produce to sodium XYZ and to hydroxide. The copper to hydroxide will stay together is a solid, and the two sodium chlorides will produce to sodium zand to chlorides. We see the sodium XYZ. Two of them are comment herbal sides, these air spectator ions, which in the picture are gray, and then the chlorides are spectator ions, which in the picture are green, removing thes spectator ions. We have copper two plus reacting with two hydroxide is producing. Like I said, copper again. Cobalt two plus reacted with two hydroxide producing cobalt to hydroxide solid for the next one, we have silver nitrate and potassium iodide. If we were to mix the contents of these two beakers together the silver nitrate and the potassium iodide could servas react INTs when the cat ion switch places will potentially produce potassium nitrate and silver iodide. If one of these is insoluble and according to the soluble ity rules, silver iodide is insoluble. So this is our solid precipitate Well, then separate everything that is soluble into its ions and get one potassium. When I died, one silver, one nitrate and then on the product side one potassium, one nitrate and then our silver iodide solid so you can see that potassium is common to both sides. This is a spectator ion, which in the picture is red and then the nitrates, which are common to both sides in the picture. They are blue, eliminating the spectator ions, then gives us the balance net Ionic equation of one silver acquis reacting with one iodide, acquis producing, producing silver iodide. It's solid

Okay, So this question is having us to look at different equations, acid base reactions and finding a balanced ionic equation. Dynamic equation, syringes. Look at the first reaction, which is caesium hydroxide and sulfuric acid. And we want to split this up to find the balance an equation. We want it split up based on eye on. So she's going to take this apart. So we have cesium you that you had rocks sign two hydrogen, and we have so s 04 Those are reactant. What we get is products as we have caesium. It is so four. And actually the Ha jin and the O. H the hydroxide come together to form water. So this is our balanced, this equation, their balance, an equation, which is what they're looking for. And then our net on equation we find by cancelling the products reaction so we have to see is plus canceled as a 40 miles canceled. And what we're left with is we're left with hydroxide and hydrogen. Since this is net, the choose don't matter and we care about this. Simplified. This is our net Ionic equation hydroxide plus hydrogen Nichols water. This is our first This is cesium hydroxide and sulfuric acid. Then our next equation will be calcium hydroxide with acetic acid. Once this is all raised will go through. That one is very similar process. So in calcium hydroxide plus acetic acid sweets for this in part based on ion, speak it. We'll see em hydroxide see the gas it their products are actually calcium. I think you're it on the products in here. Calcium two ch three c 02 minus. We actually take that hydrogen away and combine it with the hydroxide to form. You guessed it water. So then this is our balanced balance. An equation that are non ionic equation we actually take See a cancels out, and what we're left with is we're left with C h greasy, no to age. Hey, Chris. Plus I drop side ch three c o to minus member. The Haitian gets taken off finding the hydroxide to form water cistern. Net Ionic equation


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