Find the value of the discriminant. Then, determine the number and type of solutions of each equation. Do not solve.$$4 y^{2}+49=-28 y$$...

Find the value of the discriminant. Then, determine the number and type of solutions of each equation. Do not solve. $$4 y^{2}+49=-28 y$$

We have to solve the given equation to find the discriminative and the nature of flutes. So the given equation iss four X square plus seven x equals 11. So we will take 11 on the other side, so this equation will become four X square plus seven x minus 11 is equal to zero now on comparing with standard form off Radic Equation, which has given us X squared plus B X plus C is equal to zero. We'll get is value is four. These value as seven on sees value s minus 11 Indiscriminate was given by B squared minus four d. C. Putting the values off, baby and see that we have found out we'll put the value so we'll get seven square minus four times four times minus 11. That becomes 49 plus 176 that is 225. So therefore our discriminative equal to 225. Which means that the discriminative is greater than zero. Which means that boat, the roots since it's 1/4 of the equation. So it has two roads so bored the roots are really on. Dhe the roots. Oh, unequal

The formula for the discriminating B squared minus for a C we know is negative to be is one c is negative 28 giving us negative 223 because the discriminative less than zero there are two imaginary solutions.

Okay. This problem wants us to find indiscriminate of a quadratic equation. Let's start. I'm just writing in the equation. Gave this so negative axe equal seven X squared plus four in order to find the discriminating impersonated. Put this in standard for someone who had access to both sides and then just kind of rearrange ums. That's gonna give us seven X square plus X plus four equal zero care indiscriminate and pose the formula B squared minus for a C when it's in standard form. My be value now is one. So one squared minus four time seven many times for it's just gonna equal one minus 16 times seven. Uh, which is 112. One medicine 112 is negative. 111. Okay, that's our discriminate for this quadratic equation. Thank you. Very

Yeah. Problem Number 42 wit vented to find the A number and the type of solutions. So let us write it as excess quiet. Place zero X bless minus seven equal to zero and compare with general quantity Question excess squad, SPX plus equals zero. If you compare these two were getting equal to one. Be equal to zero and sequel to minus seven. So we have disc amount day equal toe be a squad minus 40 c and in our case, they will be mistress Cannot will be the real Esquire minus four into one in tow minus seven. That is 28 which is good and zero. So we have two solutions we have to distinct solutions solutions which air to yell because days got into is greater than zero. So we have to distance for reasons which area Thank you so much