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20If the electric field is 12 VIm in the positive X-direction, what is the potential difference between the origin and the point (3 m; 4 m)? (2 Points)36 V with the...

Question

20If the electric field is 12 VIm in the positive X-direction, what is the potential difference between the origin and the point (3 m; 4 m)? (2 Points)36 V with the origin at the hilmer potential48 V with the origin at the lower potential36 V with the origin at tne lower potential48 V with the origin at tne higher potential

20 If the electric field is 12 VIm in the positive X-direction, what is the potential difference between the origin and the point (3 m; 4 m)? (2 Points) 36 V with the origin at the hilmer potential 48 V with the origin at the lower potential 36 V with the origin at tne lower potential 48 V with the origin at tne higher potential



Answers

Consider a particle with charge $q=1.0 \mu \mathrm{C},$ point $A$ at distance
$d_{1}=2.0 \mathrm{m}$ from $q,$ and point $B$ at distance $d_{2}=1.0 \mathrm{m} .$ (a) If $A$ and $B$
are diametrically opposite each other, as in Fig. $24-36 a$ , what is the
electric potential difference $V_{A}-V_{B} ?$ (b) What is that electric
potential difference if $A$ and $B$ are located as in Fig. $24-36 b$ ?

In this problem we have to find the potential at a given point Where the electric field is given and the potential at origin is zero. So the potential difference is given by delta vehicle to minus E delta out. So potential at point B minus potential at origin is equal to minus E. And delta. Are is the displacement from origin to the given point, which is the position vector of the given point. So this is simply proportion, looked it up. Point B. Mhm. Now VP is unknown. Origin potential is given as zero minus 20. I plus 30 J is electric field dot do I plus, don't you Data? Yeah, position vector of point B. So this gives us VP equal to minus 20 into My next 30, into two Equal to -100 involved. Is it a potential actor required point? This complete solution?

In this question, we are given the uh, electric potential on the Xy team to be um, to towards per metre X square. This tree was planted uh, Y square. Okay. We want to find out electric fuel at uh, X. Y. That is the coordinate three m to this. Okay, so to do this problem, okay, you'll be using E exit goes through negative should be partial X. And the Y is negative. I should be I should Y. Okay. So E X is equal to negative for X. And then E Y. Is equal to negative six Y. Then at uh, thanks. Why? It was 23 m two m, E X. Is minus 12 m. E. Y. Is uh negative 12. Probably the. Okay, so the answer for this question is a plus. So yeah, it's negative by square. So you have six wine. Okay, then, uh, director, he is Uh negative 12. I had us 12 jihad uh, words for me to king. So this is the answer for this question. King. And that's all.

This question given uh yes. A function of Y to be two X squared minus tree wide square. So we want to find a we actually feel better at position. Uh huh. three m to me that's okay. So to solve this problem, Okay, you'll be using E X equals two minus partial partial X. And E Y is equal to minus partial V, partial Y. Okay, so E X. We just differentiate respect to X and you get minus for X. And then E Y. Just differentiate respect to why you get uh positive six white. Okay. And then at the point X. Y. He goes to three m, 2 m. We have e. x equals two trials negative childhood per meter. And you wanted to be a child towards kilometer. Okay. And so the electric field vector, you'll be E X. I had passed E Y. Jihad and we get negative trials. I had last 12 jihad. What's for me to Okay, so this is the answer for this question and that's all.

He ever given a charge with a value of minus 2.1 times 10 to the minus nine cool arms and two points The first point. A 20.0.25 meters away from the charge in the second point B, which is double the distance 0.0.50 meters away. The charge are asked to find the potential difference between the two points. So the potential at a given point from a point charge is cake you over our so to find the potential difference V b minus V A. All we need to do is find the potential at each spot and compare them and we can just plug in from there. So okay and cue, we can pull out their constant here. Oops, Just noticed. This should be a que sorry if that confused anyone. So here we have que being the constant 9.0 times. 10 to the nine times are que what? Supplied by one over 0.5 meters, minus 1/0 0.25 meters and we get VB minus. The A is equal to 38 thoughts. That's it was a friend of answer


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