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If the measurements of a metal block are:Height = 5.00 cm; Length 1.20 cm; Width = 1.25 cmWhat is the volume of the metal block; expressed with both the correct num...

Question

If the measurements of a metal block are:Height = 5.00 cm; Length 1.20 cm; Width = 1.25 cmWhat is the volume of the metal block; expressed with both the correct number of significant figures & the correct unit?HTML Editoca]4 - A - I E 3440 * * 0 E 0 0 & 12pt Paragraph

If the measurements of a metal block are: Height = 5.00 cm; Length 1.20 cm; Width = 1.25 cm What is the volume of the metal block; expressed with both the correct number of significant figures & the correct unit? HTML Editoca] 4 - A - I E 3440 * * 0 E 0 0 & 12pt Paragraph



Answers

Block A of an unknown metal has a volume of $125 \mathrm{cm}^{3}$. Block $\mathrm{B}$ of a different metal has a volume of $105 \mathrm{cm}^{3} .$ If block A has a greater mass than block $\mathrm{B}$, what can be said of the relative densities of the two metals? (Assume that both blocks are solid.)

In their problem. 1 17 Block a up on. No matter has a volume off one unified cubic centimeter bluff be over a different matter Has a volume off one for the fact cubits and the media, ifl okay has a rate of master lock B. What can be set off the related densities off the tomatoes? Assume that both block a solace. So when I see, we have what I has the a high you go one identify sending me that you e Oh, no, I'm Bill. So Volume II and Block B has a vb equal. 145 senti, meet a few. No. And now we're muzzle block. I should be ego 12 If I send the middle Q Tai for the density I must applaud be must be equal one for five Senti Mitac, You Taif? Oh baby, I and they know So wait! It's land here they and they be he's density. Oh, no A and look be ok And now we have must a equal big the a d a and must want toe Find time the I'm asked me, baby DBC So eagle one for five. The baby. Hi, Davey. Right and Now they say, Look, I has writer Muslim lobby Langley. So therefore, one do if I the a greater done one for five, the base in the And now we have from this work that the A over the greater than one for five divided one do. If I and this eagle one boy wants it and now we see the density off the clock. A is rated, and that's it about me. Doesn't mean that Locke a necessity more than lesser than not be. You see, it's had this this the volume smaller but the musk a greater that's mean, the density higher.

This question in this question. We have a black asked me, um, ask me, um has a necessity off 22.57 cramp cubic centimeter of the mass of the plot is one kilogram the two dimension off the blocks Ah, 4.0 centimeter and 4.0 centimeter. And so they asked us one is the dimension off? Ah ah, the other dimension of the bluff. So let's call them X. So we have volume because three dimensions for going 00 turn 4.0 Tom X. We also know that density equals mass over bowling. So volume ecause must over necessity. And so post this to a question. Together we have 4.0 time 4.0 time ex Eco's and overly so ex Eco's and over D 10 1 over 16.0 and substitute these value over here. Ah, with one key. Oh, Graham converted to Graham and 22 fifties seven Time 16.0 Sorry brother's hand the product ace to buying 77. Sandy Media

So in this question, we have to try to find the missing dimension of the Osby in metal, rectangular block. So we have a rectangular block of the metal and then we know that density is able to mass over volume. So we can draw this tribe with vehicles M over V. And were given the Destiny E As 22.57 g per centers cube. So we can flip that and use it as a conversion factor. So we want to know that what the last dimension of this one kg block is. So we convert kilograms two g because we have the density and grants three centimeters cubed. We need units to match. So when we do that, we hit 1000 g now we're going to flip the density. Used it as a conversion factor, will multiply that by 1000 g. So 1000 divided by 22.54 And then we get the volume of the block. So once we have the volume of block, we know that volume is equal to length, times width, times height. So we can solve for the missing side algebraic lee. So therefore if we solve this, We find that the missing side is 2.77 cm, and we have to make sure you it's match. So we end up with the answer in center.

Uh so for part a we can find the product between the length and the width. This would be equal to the length of five 62 cm. multiplied by the width of six 35 centimeters. And this is giving us 35 .7 cm squared of course rounded to three significant digits. For part B. Uh The product of the length and the width of the block are equal to the area of the face. And when that's multiplied by the height we can find the volume. And so we can say that then for part B, the volume would simply be equal two length with height. And this would be equal to 35.7 centimetres squared, Multiplied by the height of 2.78 centimetres. And this is giving us then 99 0.2 centimeters square. For part C we can find the area of the other face. This would be the with times the height. This would be then equal to 6.35 cm, multiplied by 2.78 cm. And this is giving us of course 17 point seven centimetres squared. Of course, surrounded 23 significant digits. And so for a part rather continuing for the volume, whether this would be then the length times the base times the height. In this case simply 5.62 Centim multiplied by 17.7 cm two. And this is giving us then 99.5 cm two. The difference in 0.3 is because of our rounding errors. So we'll have rounding errors because again we're only using three significant digits. So uh rather that would be your answer for part D rounding errors. So that's why We have the difference of .3 between 99.2 and 99.5 we've rounded all of our answers. So when we use the rounded answer in the subsequent calculation, the final answer maybe a little bit off than what we had calculated in part B. That is the end of the solution. Thank you for watching.


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