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CiCPart Four: Sketch = your model (CsHCH) and indicate the geometry about the carbon atoms:Is it possible t0 construct difierent structure using these atoms?Sketch ...

Question

CiCPart Four: Sketch = your model (CsHCH) and indicate the geometry about the carbon atoms:Is it possible t0 construct difierent structure using these atoms?Sketch the three structures that can be constructed from C H-ClzExplain how these structures are different from each other:

CiC Part Four: Sketch = your model (CsHCH) and indicate the geometry about the carbon atoms: Is it possible t0 construct difierent structure using these atoms? Sketch the three structures that can be constructed from C H-Clz Explain how these structures are different from each other:



Answers

Formulate Models Starting with a single carbon atom, draw two different optical isomers by attaching the following atoms or groups to the carbon: $-H_{1}-C H_{3} ;-C H_{2} C H_{3} ;-C H_{2} C H_{2} C H_{3}.$

I do. Okay, so we have a molecule which is ch full. This is McCain before starting. What we need to know is about vest Volturi. Okay. Best patootie sees that for a molecule to be stable, the electron pairs should be very fun over here from each other. OK, so we have two options for CS four. The 1st 1 is a square cleaner. DiMucci. So in the square planners imagery, we have carbon and the four hydrogen are like corners off a square on this angle is supposed to be 90 degrees for it to be square planner. The 2nd 1 that we have is a tetra headroom sheep. So the tetrahedron shape looks somewhat like you have a carbon hydrogen and then the one healed. This one is in the front, off the plane, and this is far behind Andi. The angle between every born or electron pale is 109.5 dignities. So what? We can conclude from here. According to West Party unity, the angry floor square cleaner is smaller than the angle for Detroit Federal raid. So this means the electron pair would be far Ovie in Central Hegel geometry as the angle his large. So from this we can write hints. Detroit Headroom ch four would be four stable, then square plan.

Given the ah ball and stick model. We see that carbon does not have eight electrons around. It only has six. Therefore, when we draw the Louis structure, we need to make sure that there are eight which is going to require us to put some double bonds between a couple pairs of carbon atoms. This would then be the Louis structure. So are all the atoms in the single plane? Yes, because each of these RSP three hybridized all carbons or SP three hybridized. All carpets are tribunal plainer. There, for the entire molecule is plainer are the Are there d localized pie electrons? Yes, there are these pie electrons could be moved between two different pairs of carbons and their resonate between these two Lewis structures. So these pie electrons are d localized.

Are there in this problem? We are given the molecular formula for four different molecules and were asked to draw the structural formula. And it's mirror image. And from that information determine which ones are going to be a mirror image. I summers so let's go ahead and get started withdrawing our structural formulas. Our first compound, a ch four. So it's structural formula will be carbon and carbon in the center, surrounded by four hydrogen. It's I am going to use a blue line here to represent my mirror. And I'm gonna draw the mirror image on the other side of that line. Yeah, okay, Alright. As we look at these two, we see they are the same on either side of the mirror mirror Image is the same. So this is not considered a mirror image, Isom. Er let's go on and look it. Let her be. Let her be. We have C f h three putting carbon in the middle if on one side and h on three of the other sides Um, trying our mirror in Let me draw my mirror image now. Okay, Right again as we look at this one, the original molecule and its mirror image are the same. So this is not a mirror image. I summer. Let's go on to let her see and let her see. We have C c l f H two right there is my image. It's draw my mirror and I'm your image notice this carbon has three different groups attached to it. It has a floor in a chlorine and then each of the hydrogen zehr the same groups there, three different groups. But notice now that I've drawn it, that's the mirror image and the original are the same. So again, we do not have mirror image. I summers letter d. We have c br c l f h right again putting carbon in the center. Keep my other things in the same places that I've been putting them. Not that that matters. All right, so there's the original structure. Here's my mirror. Let's see what we get. Now. Notice that this carbon has four different groups attached to it as flooring. It has hydrogen. Poopsie. Wait a minute. I messed up. One of these should be br All right. Sorry about that. That should be our. So it has flooring. Hydrogen bro. Mean and flooring. All right, so there's the structure and it's mirror image Notice. These two are different. These two are not the same thing. Therefore, this molecule does have a mirror image, Isom Er and that is because there are four different groups attached to it. There's a flooring group of bro mean hydrogen and a chlorine. Okay, Thank you so much for watching.

Todo question 1 70 years Talks about going the other structure first. If you go for so you would have it like this B would be No, Because oxygen minus charge she? Yes, here is where the carbons from it.


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