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Water trcatment plant estimating the amount of HCI present in the various water samples collecting from differentirklustrinl areas by volumetric analysis. One ofthe...

Question

Water trcatment plant estimating the amount of HCI present in the various water samples collecting from differentirklustrinl areas by volumetric analysis. One ofthe sample analyses required 0.2016 of NaCO; for 14,5 ml samplecontain HCI with indicator correction of 0.5 ml with Bromo thymol blue Calculate the umount of HCI presentsumple in Tam per liter; (MMof NaCO,-06 Emol)(2 Maurks /

water trcatment plant estimating the amount of HCI present in the various water samples collecting from different irklustrinl areas by volumetric analysis. One ofthe sample analyses required 0.2016 of NaCO; for 14,5 ml sample contain HCI with indicator correction of 0.5 ml with Bromo thymol blue Calculate the umount of HCI present sumple in Tam per liter; (MMof NaCO,-06 Emol) (2 Maurks /



Answers

Calculate the concentration of $\mathrm{HCl}$ in mass percent of a 9.45 M HCl solution. (Assume a density of $1.149 \mathrm{~g} / \mathrm{mL}$ for the solution.

Question 96 is another solution. Stoke Yama Tree calculation. This one also will include the ideal gas law. So we need a balanced chemical reaction which was given to us in order to conduct the Stoke Yama tree. Part Magnus for oxide reacts with four moles of hydrochloric acid to produce one mole of manganese. Yeah, manganese to chloride and water and chlorine gas. So the first thing we'll do is we'll start with the reactant that we have. We have 50 million liters of the reactant HCL. We can cover it the 50 mL into leaders by dividing by 1000. Then when we have leaders of HCL, we can calculate the moles of HCL using the morality of HCL which is 1.2 now when we have moles HCL we could go to the store geometry of the balanced chemical reaction and we see that four moles HCL will produce one mole of chlorine gas so we get a chlorine gas amount of 0.2015 moles chlorine gas. We needed the most chlorine gas so that we could use the ideal gas law in order to calculate the volume of chlorine gas which is what is requested. Rearrangement of the equation gives us volume equal to NRT overpay. So we'll plug in our end that we just calculated our our value r t value. This is the STP. So that's standard temperature of 2 73.5 and a standard pressure of one atmosphere and we get 0.336 leaders of chlorine gas. Or we could have simply multiplied this by 22.4, which is the volume of any gas at STP per mole.

Yeah stood this question. That balanced equation. You have two hcl big quiz and magnesium carbonates solid. This will produce carbon dioxide gas H. Two a liquid. Yeah. Mhm. And make music for adequate in this question. Were given that we have a 21.4 million liter volume of the hydrochloric acid reacts completely with magnesium carbonate. The volume of carbon outside formed is 159 millimeters at 23 degrees Celsius and 731 millimeters of mercury. From this we can calculate the malls of carbon dioxide convert 159 mL which would be 159 times 10 to the minus three leaders. 23 degrees Celsius in the kelvin we 23 to 73. Yeah. Which is equal to 96 Calvin. Yeah. And 731 millimeters of mercury into atmospheres is equal 2.962 atmospheres assuming ideal gas behavior catholic malls. Carbon dioxide C. Called the T. V. Over artie pressure is 962 atmospheres. The volume 159 times 10 to the minus three leaders do gas constant. Mhm. Yeah. And our temperature in kelvin. Yeah. To put sulfur moles of carbon dioxide. Yeah. Mhm. This will give us 6.30 times 10 to the minus four moles of carbon dioxide. Now, using our site geometry 630 times 10 to the minus four moles of carbon dioxide, one mole of carbon dioxide. Okay, it's equivalent to two moles of hydrochloric acid. It gives us 1 to 6 times 10 to the minus three moles. Uh hydrochloric acid and the concentration of hydrochloric acid. Secret of number of moles over the volume of leaders. 0.26 times 10 to the minus three moles. Our volume it was 21.4 millimeters of 21.4 times 10 to the minus three leaders. This gives us a more clarity of H. C. O equals 2.589 Moeller 23 significant figures

This is question 109 from chapter 11. And we had to fund the polarity of this 30 of my drug size delish in. And we have a hygiene quick acid gas that is dissolved and they do not give us the most. So but that's first they're gonna be doing is solving for most that's gonna be the equation derived. Gonna be in ukuleles pressure terms, volume over the gas, constant eso. When you plug these numbers in, we're gonna have 100 8 no longer. It's Gregory crimes. You have 100 89 new leaders converting that readers gonna give you 890.189 leaders were the writing by 1000. Now we're gonna have over the gas Constant and for millimeters of mercury is 62.4 and now when you have 25 degree. So she is at 273 to convert the cove and for temperature. So 298 Children, I'm going to this the most come out to be all right, do you? Zero 109 Roques. Now that we have that, we consult for the polarity of sodium hydroxide. But before you do that. We have to look after coefficients for the equations, and as you see, they're all equal. They'll have a coefficient of one so we don't have to multiply. Multiply it by itself, basically, and now also a similarity. Similarity is most of Seoul loop over leaders of solution. So we have the most right here. And then they give us 15 0.7 no leaders. Now Malaria's leaders of salutes that we have to convert this 2.0 one by seven leaders, and when you do this, it should come out to be 0.0 seven moller of sodium hydroxide.

So continuing on in this podcast Siri's we're calculating the moles off H c l moles cause mass folks what I am Ah, fouls equals concentration multiplied by volume which is Theo equation that we need Not quite not 983 Most probably not, but not 1123 liters equals 1.1. There are 39 times 10 to the minus three moles. In the next part, we can cut the similarity off C a. O h two that is one point 2.208 times 10 to the minus two. Lastly, we can calculate the k SP, but IHS see a two plus oh H minus two equals 5.38 times chance minus six. That is our K SP. So the calculated K s P values 5.4 times 10 to minus six is less than the value in the given data. That is 6.5 times 10 to the minus six on the solution here is kept at 25 degrees C.


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