5

Solve.$$b+3=-3$$...

Question

Solve.$$b+3=-3$$

Solve. $$b+3=-3$$



Answers

Solve the equation. $$ a-3=-2 $$

Three into eight, plus B is 27. So first step here. Let's divide both sides by three. So we're gonna end up with a plus. B is 20 is nine. So let's subtract eight on both sides so we'll end up with B is equal to one.

All right, so we got blank. Tape's blank tape's blank equals zero. Doesn't matter what's in there. So we got three solutions here be could be equal to negative four. Because if I'm a negative for, uh, put that in for beer at your negative four plus 400 times, this would be 00 times. This would be zero or B could be positive. Three. Because three miles 30 and zero times anything is zero or B could be 1/2 Okay, two times 1/2 is one and one minus. One is zero. Maybe I'll come over here and do that one, though for you two times B minus one. If that zero, then the whole equation would be zero at wonderful sides. The Vibe. All sides by two There's your 1/2 so again X could be negative for X. Could be three or X could be 1/2

Trying to solve this equation for a We can do it one step, actually, just a viable sized by three B because then the threes would cancel out. The bees would cancel out. But whatever you do in the left, you have to do on the right. So there's our answer. A. It's always remains in the left and the right would get see over three b. There is the same equation, but so for A instead of C.

Well, right. We're going to solve this equation. B plus 1/2 minus three halves equals four over me. So I see that I have three terms with denominators, and within those denominators, I have a factor of two and a factor of be somebody. Multiply everything by to be, which would be the least common denominator. Okay, To write this out, I have to be times B plus one over to minus three times to be over to equals four times to be the over B. So I can look for factors of one to cancel out. I have a two in the numerator and denominator. So now I'm gonna go ahead and multiply this out. Be times B is B squared. B team's one is be so, plus B over in the next term, I have three times two times be over two. So my twos cancel out and I'm left with minus three b equals And over here I have a bee in both the numerator and denominator is with four times two is eight. So now I'm gonna combine like terms. Right here. Have B minus three B. So I have b squared minus to b equals eight gonna bring the eight over to this side of the equation. So I had B squared minus to B minus eight equals zero. And now I need to factor this. So I know I'm gonna have a factor of B. I have a negative eight year, which means I'm gonna have a positive, um, combination factor. And I'm also going to have a negative. And I need to numbers that multiply together to make eight. So I either have one and eight or two and four. And when I add them together, when one is negative and one is positive, I'll get negative, too. And so if I have negative for plus two, then I get negative, too. So, B minus for A and B plus two are my factors equal to zero. This tells me that B plus two equals zero four. Being minus four equals zero. So B equals negative, too, or B equals four, and I'm going to test both of them by plugging them back into the equation. So I'm gonna start using green with negative too. So negative two plus 1/2 minus three halves equals four over negative too. So negative. Two plus one is negative. One. So have negative. 1/2 minus three halves equals negative to four. Divided by negative. Two is negative. Two and negative one minus three is negative. Four over to and negative four. Divided by two is negative. Two. So negative two equals negative, too. So being minus two is a solution. Now I'm going to test the B equals four by doing the same. Process. Four plus 1/2 minus three halves is equal to 4/4. Four plus one is five. So five halves minus three halves and for over for his one five minus three is two. So I have to over two equals one and two. Divided by two is one. So yes, B equals for is a solution.


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