5

Write as equivalent fractions with the LCD.$$ rac{1}{8} ext { and } rac{15}{32}$$...

Question

Write as equivalent fractions with the LCD.$$ rac{1}{8} ext { and } rac{15}{32}$$

Write as equivalent fractions with the LCD. $$\frac{1}{8} \text { and } \frac{15}{32}$$



Answers

Write as equivalent fractions with the LCD. $$\frac{1}{8} \text { and } \frac{15}{32}$$

Question 99 were given. One eats, and they want three equivalent fractions. So what you could do is most public, two on the bottom and two on the top. So this is a total. Or you could multiply, let's say, by three on the bottom and three on the top. So this is a clear line, or you could multiply. Let's say that four on the bottom and then four on the top, and that is a cooler as well.

From this question. One or one it wants us to write. Threequel infractions just multiplied denominator and the numerator by a set number. So, for instance, with the most public too of the bottom two on the top. This is a good one for once. Say you multiple E three on the bottom. We'll get for years. Stay in the top 40 listening, multiply by four Bottom your sperm 15 of the 16 with multiply by Ford. 60 Cooler or multiply for on the top. Get 60. So that's it. Those are three equivalent fractions.

In this question. It wants us to rate three caloric reactions. Train grateful infractions. We need to re write What's a denominator? That's a multiple off the original denominator. So its able to probably two on the bottom. We've multiplied by two on top or let's save multiply by three On the bottom, we get 96 most public, three in the top or let's say we multiply by four on the bottom. There are two new times for not using a calculator 20 and by four numerator, and those three fractions are quote.

In this next question, they want us to write a given fraction in three additional leads. Thes air cold equivalent fractions. So what we dio is enrolled supply. It's a nominated winning most of it to first, so I get 64 two in the top, which is 15. That's a cool take the same fraction. Multiply quite three in the bomb. I get 96 3 in the top get 75. That's when a little infraction or when you could dio, is you can multiply. So here I must call by to hear and multiplied by three here in a multiple bit or I get 1 28 and then I moved by, formed the top I get Hunter. So these three, are you ordering fractions?


Similar Solved Questions

5 answers
Cnapeatatdalen0elsIn te r pure- creese lics Ehn ncan Cla Lo elevator cab that Is belng Fulled upward by cabt Ihrough distarte 01 2.7 m nd tnen through dlstancs 116m. (D) Through 01, If the normal (orce on the blck from the Ilour has constant maoritude Fx Fov mucn Far the cab tne force Irom the cable? (6) Tnrouah d7 the WDA done Kte Ca Itne (constant} Yorce Iron 07 14 maonitude C Fa7(0) Number(D) RumberCllct #you wculd EICnol Hork tor tnit ouequonzOoln snnm woc
Cnapeat atdalen0els In te r pure- creese lics Ehn ncan Cla Lo elevator cab that Is belng Fulled upward by cabt Ihrough distarte 01 2.7 m nd tnen through dlstancs 116m. (D) Through 01, If the normal (orce on the blck from the Ilour has constant maoritude Fx Fov mucn Far the cab tne force Irom the cab...
5 answers
3O Eja ly"j Susluate lucte 4 ketueen 6 4-/ $ 3" 1 8 13 8 jzo 0 6" 7 7 6F 0 1 Jo 2 4
3O Eja ly"j Susluate lucte 4 ketueen 6 4-/ $ 3" 1 8 13 8 jzo 0 6" 7 7 6F 0 1 Jo 2 4...
5 answers
According Kepler'$ Third Law; the period (in days) of satellite moving earth given bycircuizorbit _ mi above the surface the05883959Suppose that communications satclllte moving circular orbit 26,000 mi above the earth $ surface_ Because of (riction; tnc satcllitc drops down to ncw orbit 25,500 above the carth's surface . EstImate the decrease In the period the satellite to the nearest one-hundredth hour hours
According Kepler'$ Third Law; the period (in days) of satellite moving earth given by circuiz orbit _ mi above the surface the 0588 3959 Suppose that communications satclllte moving circular orbit 26,000 mi above the earth $ surface_ Because of (riction; tnc satcllitc drops down to ncw orbit 25...
5 answers
Problem 3In Fig. 3,a long rectangular conducting loop, of width L, resistance R; and mass m, is hung in a horizontal , uniform magnetic field B that is directed into the page and that exists only above line aa. The loop is then dropped; during its fall, it accelerates until it reaches a B certain terminal speed Vz Ignoring air drag find an expression for Vp
Problem 3 In Fig. 3,a long rectangular conducting loop, of width L, resistance R; and mass m, is hung in a horizontal , uniform magnetic field B that is directed into the page and that exists only above line aa. The loop is then dropped; during its fall, it accelerates until it reaches a B certain t...
5 answers
8 Qetermine 8 8 1 3
8 Qetermine 8 8 1 3...
5 answers
Show Ilcvll = Iclllvll for any scalar and vector v Prove Cosine formula in RR2 from def. of vector norm, i.e;, VW1 + VzWz cos 0 IlvIllwll Prove Cauchy-Schwarz inequality And show when it can be equality
Show Ilcvll = Iclllvll for any scalar and vector v Prove Cosine formula in RR2 from def. of vector norm, i.e;, VW1 + VzWz cos 0 IlvIllwll Prove Cauchy-Schwarz inequality And show when it can be equality...
4 answers
1 1 = ~14 has eigenvalues Aqhelp (matrices) andpuiy the corresponding elgenvectors;
1 1 = ~14 has eigenvalues Aq help (matrices) and puiy the corresponding elgenvectors;...
5 answers
Question 3€ + 3 € + 6Let f(c) = 26f' (2)Submit Question
Question 3 € + 3 € + 6 Let f(c) = 26 f' (2) Submit Question...
5 answers
2. 0 (or Problem 1 67 1 B = Fun 1 Addv 7 2 lbc 7 (18 1 bt 1 Gmtu WD Ielo = 1 points) ulrb Shule [ 7 1 2 R' 8 } 1 | 1 1 ad } and lo oblua 30 1 6 3 L 1 [
2. 0 (or Problem 1 67 1 B = Fun 1 Addv 7 2 lbc 7 (18 1 bt 1 Gmtu WD Ielo = 1 points) ulrb Shule [ 7 1 2 R' 8 } 1 | 1 1 ad } and lo oblua 30 1 6 3 L 1 [...
5 answers
2 (4 points) Find the values of A and B for which the function f(x) is continuous everywhere: JAr?_ ~Br + 3 if x21: fW) = 2-7 if 8<1.
2 (4 points) Find the values of A and B for which the function f(x) is continuous everywhere: JAr?_ ~Br + 3 if x21: fW) = 2-7 if 8<1....
5 answers
A 13.5 nC charge is at x = 0cm and a -1.4 nC charge is at x = 4cm .At what points on the x-axis is the electric potential zero?
A 13.5 nC charge is at x = 0cm and a -1.4 nC charge is at x = 4 cm . At what points on the x-axis is the electric potential zero?...
5 answers
Give an example of one type of stored energy transformedinto something else (even more stored energy). What happens to theenergy?
Give an example of one type of stored energy transformed into something else (even more stored energy). What happens to the energy?...
5 answers
Question 3 (4 marks)Show that there is a root of the cquation 3x5 + 26x* + 4x? _ 30 = 0 between 0 and 1.
Question 3 (4 marks) Show that there is a root of the cquation 3x5 + 26x* + 4x? _ 30 = 0 between 0 and 1....
5 answers
A uniform rod of length L and mass M is free to rotate about fixed, frictionless axle passing through the center of mass, a8 shown in the figure below _ A vertical spring is attached one-fourth of the way from one end. Show that for small amplitude oscillations, the system executes simple harmonic motion and determine the angular frequency.trod tnctonicna nrlo
A uniform rod of length L and mass M is free to rotate about fixed, frictionless axle passing through the center of mass, a8 shown in the figure below _ A vertical spring is attached one-fourth of the way from one end. Show that for small amplitude oscillations, the system executes simple harmonic m...
5 answers
Find area of region enclosed by the parabola y=x2 and y=x+92
find area of region enclosed by the parabola y=x2 and y=x+92...
5 answers
A wind turbine is initially spinning at constant angular speed. As the wind'$ strength gradually increases, the turbine experiences constant angular acceleration 0.128 rad/s?. After making 2870 revolutions,its angular speed is 157 rad/s. (a) What is the initial angular velocity of the turbine? (b) How much time elapses while the turbine is speeding up?(a) NumberUnits(b) NumberUnits
A wind turbine is initially spinning at constant angular speed. As the wind'$ strength gradually increases, the turbine experiences constant angular acceleration 0.128 rad/s?. After making 2870 revolutions,its angular speed is 157 rad/s. (a) What is the initial angular velocity of the turbine? ...

-- 0.021031--