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An aralxucal camlzt = titretng 239.2 mL c 8 0.07J0 solulijno enene (CH,XH;) #th & 0 3800 anllann af HNO, The pKa" Anir 6937. Ciculue 78 Ph t2 dalatoluton J...

Question

An aralxucal camlzt = titretng 239.2 mL c 8 0.07J0 solulijno enene (CH,XH;) #th & 0 3800 anllann af HNO, The pKa" Anir 6937. Ciculue 78 Ph t2 dalatoluton JC Ommisl hal 0doco 49.2 IL oftha HNO , colialnNt_ advanerd eldthtz;hluenelungn eheinng colume rolnkIntealyclulnntlanachibu DUI the euluinn CHRO, eouIllon acdedAnlmaVennneJeonial Pacrt

An aralxucal camlzt = titretng 239.2 mL c 8 0.07J0 solulijno enene (CH,XH;) #th & 0 3800 anllann af HNO, The pKa" Anir 6937. Ciculue 78 Ph t2 dalatoluton JC Ommisl hal 0doco 49.2 IL oftha HNO , colialn Nt_ advanerd eldthtz; hluenelungn eheinng colume rolnk Intealyclulnntlanachibu DUI the euluinn CHRO, eouIllon acded Anlma Vennne Jeonial Pacrt



Answers

Calculate the $\mathrm{pH}$ of a buffer that is (a) $0.012 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\left(K_{\mathrm{a}}=6.3 \times 10^{-5}\right)$ and $0.033 \mathrm{M} \mathrm{NaC}_{6} \mathrm{H}_{5} \mathrm{COO}$ (b) $0.408 \mathrm{M} \mathrm{NH}_{3}$ and $0.153 \mathrm{M} \mathrm{NH}_{4} \mathrm{Cl}$

Question is at yet 4.5. Which of the foreign assets would be most dissociated? Okay, So at PS four Queen Hive nature of the molecule will be acidic. If nature of the molecule is the acidic then dissociation, meaning that which molecule will be acidic because it So the nature of STD then it should be dissociate into an iron or express, correct? So we know that the value of peak increase then the value of okay will be decreased and athletic restaurants will also decrease. So we have to identify which molecules will be most dissociated are most aesthetic. So most pathetic compound will be para nitro bandwidth asset because this morning you will have the lowest value and I'll just to have highest care. So it will be as strong as you. There's my it is molecule strong acid. So it will be dissociate in there. Highest quantity. So correct option will be better nitrobenzene yesterday. Okay, thank you.

Okay, so let's start by figure out how many moles of each substance we have here. Okay, so we have to moller And .355 L. So that's going to give us .0710 malls of the weak acid which is bicarbonate and 134 more and the same volume. Which will give us .04 76 moles of its conjugate base carbonate. Okay, so we have a weak acid and its conjugate base. So that is going to be a buffer. So our relationship for buffers is H plus is okay times the malls of acid provided by the malls of base. So that will be 47. I'm standing negative 11 some walls of acid over moles of base. So this will give us 7.0 I'm sounding negative 11 moller that's our H plus concentration. So if I take minus the log of that, we'll get the ph And that will be 10.15. In the second example we're adding some strong acid. That strong acid is going to react with the week based part of the buffer to make some more weak acid. So let's just do a table where we keep track of the strike geometry, initial change and final. So .03 Is what we're adding 2.04 76. and don't forget you have .071 of this to start the age plus is are limiting reactant. So we'll go ahead and subtract And add .03. She'll give a zero of that. .0176 moles and .101 moles. So we have a weak base and its conjugate weak acid. So that's a buffer. So let's go ahead and use our buffer equation H plus is a K a 47 times 10 to the negative 11 Acid over base. Which is our .101 Over .0176. So that's going to give us 2.7 Times 10 to the negative 10 more age plus. So We take minus or log of that. We'll get our ph which is nine 0.57. And then in this last example we're gonna add strong base. So the O H minus is going to react with the weak acid part of our buffer to make some water and some carbonate. So again we'll just keep track of this sort of in a store geometry table. So we're adding 0300 .0710. Don't care about the water. .0476. Okay. R O H minuses are limiting reactant so we'll subtract here and add over here So that will give us zero and zero for 10 And 0776. So this again is going to give us a week acid and its conjugate weak base so we have a buffer. So we'll do HPE plus is a K. A. Times acid over the base, Which is our .0410 over .07 76. So this gives us an h plus concentration of 25. I'm saying the -11 moller H plus. And then if we take minus or log of that, you've got your ph your ph becomes 10.60.

Let's determine the ph of this buffer solution. We'll find our polarity of ammonium chloride 3.172 Moller in the uh initially 38 mm and the total volume In the buffer it is 103.1 ml. Therefore this gives us zero 634 Molars and the concentration of Ammonia. This .142 Moller initially we have a volume of 65.1 mm over a total volume of 103.1 mm. And this gives us .0897 Mueller, calculate the P O. H. This is equal to the PkB plus the log of the concentration of the salt over the concentration of the base. And so that the pkB is the negative log KB is 1.8 times 10 to the negative five plus the log of the salt +0634 Mueller over the concentration of the base 6340.897 Mueller. And solving for the P O. H, we find the p o h Is equal to 4.59 and the ph is equal to 14 minus the p o h, Which is equal to 14 -459, which gives us a ph value equal to 9.41 Yeah.

This. The first one is yet three. Your poor is obvious. Plus it's too. Oh, I it was yes to your four. A que bless? Yes, 30 less a que so missed one yes. To your poor acquiesced. Plus yes to liquid is it was too. C 03 to a que plus There's 30 plus Thank you. And third one Yes. B o four do a que plus Yet toe it was too you for three. Thank you. Bless Yes 30 plus a que. So as the proper contains guinea is too pure for and you need to get here for that is just to appear for and fear for too. And because both these are present in the second reaction, the gay off second state that is gato is more significant. Respect traditional reaction. So stay plant is already um So first one eads best is it was toe your four to it was 20.4 p m thickened. It's acid. Okay yet CEO three is it closed toe 0.2 pm on the third one is Kato is it was too 6.3 then. Yet the next one be formally So the formally one is that we have uses Henderson, my nurse hassle. But the question palpable foot be It is. It was too Peek a bless. Look Going to get this. Do you ever go by? I suit so 71 is PK. It was toe minus log. Okay, so 30 on Thursday is the solution Solution First Pekingese was to look okay, so by putting the values law 6.3 in tow 10 it is. It was too. 7.20. You don't first one and the signal be It is. It was to be a less log going to get base. Do it by a suit. Is it closed toe by putting the values over here is so on 0.20 plus log or in 40 devoured by buying 50. So the little awkward here is 7.20 plus minus zero point. Then it was +27 point then and the last step over here is pains. Be it off the before it's 7.9. Great. And the last step is our answer. Okay, here is the beat of the puffer has calculated about is standpoint to deflate. I hope you understand This will thank you


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