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You are to prepare 150 mL of Medication "8" in a 1/4 strength solution with water to dilute it How much inactive ingredient should you add? Round to neare...

Question

You are to prepare 150 mL of Medication "8" in a 1/4 strength solution with water to dilute it How much inactive ingredient should you add? Round to nearest 1OthDO NOT put units in your answerQuestion 651 ptsYou are t0 prepare 200 mL of Medication B"ina 1;2 strength solution with water to dilute itWhat is the fractional strength?

You are to prepare 150 mL of Medication "8" in a 1/4 strength solution with water to dilute it How much inactive ingredient should you add? Round to nearest 1Oth DO NOT put units in your answer Question 65 1 pts You are t0 prepare 200 mL of Medication B"ina 1;2 strength solution with water to dilute it What is the fractional strength?



Answers

A solution strength of 8 mg of medicine in 1 ml of solution is available. If a patient needs $10 \mathrm{mg}$ of medicine, how many $\mathrm{ml}$ do you administer?

Question 54. To what volume should you dilute? 100 in 25 Mill leader of and 8.0 Mueller Comfort chloride solutions so that 50,000,000 er of the dye looses diluted solution contains 4.67 grams of comfort. Chlorine Alright tio Calculate the polarity. First find the amount of copper chloride and most from the mass and moral master. So the mole's of comfort chloride is equal to the mass of copper chloride divided by the Moler Mass, and this is equal to 4.67 grounds. The writer by the Moral maths of copper chloride is 134.25 Graham's promote and this will give you zero porn 034 seven Most of comfort chlorate and therefore the mill arat e is to calculate by using the formula similarity equal to most ofthe salute. Divide if i volume of thie solution and this is equal to their own 0.347 more two about Abi, 50 times 10 to the minus three leader. This is equal to through a 0.694 Moler. So that's the Moler similarity. This is the molar ity, not the solution Couple of chlorine then we know that and long we want equal to and to re too. So we will have me to equal to m one. Be want to gratify him too? So we have m one is it to aid Mueller Times we won? That is 125 mil ater you've abided by EMP to that. Is there a point 694 Mueller? So we got a lead, Teo equal to 1004 140.9 mil leader and convert that into leader We'll get one point about 1.44 Leader So the answer to this question is the desired volume. We'll be equal to one point for a for Lee.

Let's first figure out the polarity of the solution that contains 5.9 grams copper to chloride in 50 mil. Leaders to do that will take the 5.9 g copper to chloride divide by the molar mass copper to chloride to get moles, copper to chloride within divide that by the leaders of solution. The solution was 50 mil. Leaders were 500.50 leaders, and we get a polarity of 0.8776 Mohler should be rounded to two significant figures because of the two right here. But I won't round yet. Then I'll take the 125 mL multiplied by the eight Moeller in the Delusion equation and set that equal, toothy, unknown volume of delusion with the desired target polarity of Now what I just calculated. 0.88 of 7.8776 Mohler and the volume then, just to two significant figures, cause this number really should just have two significant figures is 1100 mL

If we want to prepare 1.75 Mueller Solution from a tenant Mueller solution starting with 75 mL of this 10 Mueller solution, we can use the delusion equation to calculate the Volume two, which it needs. The volume to which the 75 mL need to be diluted in order to achieve a 1.75 Mueller solution, and it's 430 mL.

We have been asked to find out how much pure acid is in 250 Miller leaders of a 14% solution. To do this, we're going to multiply by 14% written as a decimal, so 140.14 and 250 times 2500.14 is 35 milliliters of pure acid.


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