5

Calculate the volume you need to take.7 from a solution contains 44.000 g of KOH (56.11 g/mol) in ml distilled water to prepare a 150.00 250.00 ml of 0.150 M KOH so...

Question

Calculate the volume you need to take.7 from a solution contains 44.000 g of KOH (56.11 g/mol) in ml distilled water to prepare a 150.00 250.00 ml of 0.150 M KOH solution? (KOH 56.11 g/mol) abii 5)mL 2.27mL 34.22mL 7.17mL 13.25

Calculate the volume you need to take.7 from a solution contains 44.000 g of KOH (56.11 g/mol) in ml distilled water to prepare a 150.00 250.00 ml of 0.150 M KOH solution? (KOH 56.11 g/mol) abii 5) mL 2.27 mL 34.22 mL 7.17 mL 13.25



Answers

Calculate the volume of a $0.157 M$ solution of potassium hydroxide, $\mathrm{KOH},$ required to react with $0.385 \mathrm{~g}$ of acetic acid, $\mathrm{CH}_{3} \mathrm{COOH}$, according to the following reaction. $$ \mathrm{KOH}+\mathrm{CH}_{3} \mathrm{COOH} \longrightarrow \mathrm{KCH}_{3} \mathrm{COO}+\mathrm{H}_{2} \mathrm{O} $$

Let's am hydrating killer. Age versus age I and I have the concentration of H I, which is one more. The concentration of carriage is unknown. I have the volume off H I, which is 50 millimeter and have the volume off Cayo age, which is 35 on 41 millimeter. To find the more clarity of carriage, we have to use the formula and one we want equals two and do V one. Um, I always put the names off. Um, the compounds of the chemicals that I'm using, so the source to make it easier. So this is our unknown quantity. And to figure that out, we merely need to plug in the values which in this case is one more into 50 milliliters, divided by volume off kill it, which is 35.41 milliliters. Missile Give us morality off 1.412 What

This question is a multiple titillation calculation question. Mhm. Anytime you perform a titillation calculation, you need to make sure that you have a balanced chemical reaction. There are no chemical reactions provided in this question. So you need to right the chemical reactions yourself. The first problem is the reaction of h two S. 04 sulfuric acid with the base potassium hydroxide. When this asset reacts with this base, the product will be water and assault the salt or ionic compound will have the cat eye on from the base and the anti on from the acid sulfate has a tu minus charged, potassium has a one plus charge. So we're going to need to, potassium is for every sulfate. Now we'll recognize we have two potassium and only one potassium, so we need to put a two in front of the K. O. H. This then gave us two oxygen's outside of sulphate. So we need to put a two there, so we have to oxygen's outside of sulphate. We have now four hydrogen and we have 1234 hydrogen ins. Now that we have a balanced chemical reaction. We can continue with the calculation, we'll start with the volume of the sulfuric acid solution, 2.5 mL. We'll convert that into leaders by dividing by 1000. So that we can use more clarity to go from leaders of the sulfuric acid solution. Two moles of sulfuric acid. We can do this by multiplying by the polarity of sulfuric acid. Then when we have moles sulfuric acid, the leader units canceling the mill leader units canceling. We can convert moles H two S 04 the moles K O H, recognizing the two to one more relationship with moles K O H. We can use the polarity of ko age to convert to leaders, ko wage solution by dividing by the polarity the mole scale, which will cancel and we'll have leaders of the K. O. H. Solution. This question however wants the answer in mill leaders. So we will multiply by 1000 to convert the leaders into mill leaders and we get 19.2 mill leaders K. O. H. Solution required to neutralize 2.5 mil leaders of the sulfuric acid solution. Next we have nitric acid reacting with K. O. H. To produce water and potassium nitrate. It is balanced as is so the coefficients are all one well. Then go to the volume of the nitric acid solution. We are attempting to neutralize convert the mill leaders to leaders by dividing by 1000. Once we are in units of leaders of the nitric acid solution we can use the polarity of the nitric acid solution to convert those leaders into moles nitric acid. We do this by multiplying by the polarity of the nitric acid solution. Then when we have moles nitric acid we'll go to moles K. O H. Recognizing the 2 to 1 relationship. When we have moles K O H. We can convert it into leaders K. O. H solution by dividing by the polarity of the K. O. H solution. This way the molds K wage council and we'll be left with leaders. Kluh solution. But the question wants are answering mill leaders so we'll multiply by 1000 to convert the leaders into mill leaders and we get 48.2 mill leaders K. O H solution required to neutralize the 18.5 mL of the nitric acid solution. The last one is hydrochloric acid reacting with K. O. H. To produce water and the salt potassium chloride and it is balanced as is where all the coefficients are one as before. We'll start with the mill leaders of the acid convert the mill leaders into leaders by multiply by dividing by 1000. Then we have leaders of the HcL solution will multiply by the polarity of the Hcl solution to convert those leaders into molds Hcl then with moles hcl using the stock geometry and the 1 to 1 relationship. We can calculate malls K O H. With moles K O H. We can use the polarity of the K. O. H solution to convert the moles K O H into Leaders K. O. H solution. We do this by dividing by the polarity. Then when we have leaders K. O H solution to get mill leaders will simply multiply by 1000 and we get 74.0 mil leaders K. O H solution that is required to neutralize five mL of the Hcl solution.

So begin with .385g of acetic acid, Divided by its more its molar mass, which is 65g per mole, Then do a mole ratio from the acetic acid, so the coefficient of one in front of it to the potassium hydroxide, which is which has a coalition of one as well. Then use the polarity As .247 moles per leader, used it as a fraction To cancel moles to give you leaders and you'll end up with .0-60 leaders a potassium hydroxide.

In this question, I need to determine the volume of sulphuric assets of 0.344 molar concentration sulphuric acid that will be able to neutralize a certain concentration and volume of potassium hydroxide for this purpose. I will need to make use of stoking geometry. Therefore I need to make sure that my reaction equation is balanced at this stage. It is not balanced because these, for instance, is to potassium ions on the right hand side, one on the left hand side. So let's put it to in front of the k O. H. And then I also needed to in front of the water. Now the reaction equation is balanced and I can go and calculate my number of malls of potassium hydroxide from the clarity and the volume so that I can use this together with this to psychometric mole ratio to calculate the number of moles of sulphuric acid. And from there it's going to be easy to calculate the volume because I have the concentration available right? So as I've mentioned in my first step, I will need to calculate the number of moles off potassium hydroxide. And this is going to be the volume of potassium hydroxide in terms of liters, not milliliters has given times similarity. Reason why it needs to be in liters is because more clarity his moles a leader in this case it's 0.10 point 255 miles per one liter. So once I have the number of moles of potassium hydroxide, I can check what my more ratio is that I need to use to calculate the number of moles of sulphuric acid. So the number of moles of sulphuric acid, over the number of moles off potassium hydroxide is 1/2 according to the story geometric coefficients. In my balanced equation. From here, I can then determined the number of moles of so freak acid in terms of the number of moles off potassium hydroxide. So this is half times the number of malls off potassium hydroxide. I need to calculate the volume of sulphuric acid in the end. So once I have the number of moles off so freak asset, I can just divide this by the molar itty of sulphuric acid in order to determine the volume. So now I can do all my calculations in one step. Once I've substituted all the values here, so the number of moles of sulphuric acid, I've shown that I can calculate this by saying it half of the number of moles off potassium hydroxide, which I can calculate by multiplying the volume of potassium hydroxide with the more clarity Of 0.255 moles per one L. So this is how I calculate the mess. Certainly the number of moles of myself for gas it and then I need to divide by the polarity of sulphuric assets. I'm gonna, instead of dividing, I'm going to multiply with the reciprocal of the clarity of sulphuric acid so that I can show how they make sure that the units without to be in terms of liters. So the polarity is zero 344 moles per liter. So therefore I'm not going to divide by this, but I'm going to divide by The reciprocal, which is one leader over 0.344 moles. One side. I've subsided all these values. It's easy to see leaders cancel out moles, cancel out and I'm left with a value in terms of leaders And this value works out to be 0.0128 leaders, which I can convert you milliliters by multiplying with 1000 And then it's 12.8 mm. So this is the volume of sulphuric acid will be able to neutralize the potassium hydroxide in this question. It's quickly, quickly recap what I've done to answer this question. First of all, it was necessary to balance the reaction equation then determine the number of moles of potassium hydroxide. Because once I've yeah Calculated the number of moles of potassium hydroxide. I could use the stock geometric ratio of potassium hydroxide or um of sulphuric acid to um potassium hydroxide, which is 1-2. To then calculate the number of moles of sulphuric assets. And then it was just easy way forward to then divide the number of moles of sulphuric acid by its polarity And I ended up with the volume in terms of leaders, which I was then able to convert two ml.


Similar Solved Questions

5 answers
Manufacturer of electronic calculators takes random sample of 1200 calculators and finds defective units_ Construct 959 confidence intervathe population proportion_Round your answersdecima places_P <
manufacturer of electronic calculators takes random sample of 1200 calculators and finds defective units_ Construct 959 confidence interva the population proportion_ Round your answers decima places_ P <...
5 answers
So Lve the following Qrob b uvg alegragervl typlia max22x A 6LL4 5+ 2 4X,+ YXs `4 302 J1+8x1 +641 4 }0 X+ Yo+x5 AYubz in6292
So Lve the following Qrob b uvg alegragervl typlia max22x A 6LL4 5+ 2 4X,+ YXs `4 30 2 J1+8x1 +641 4 }0 X+ Yo+x5 AYubz in6292...
5 answers
1 1 1 1 18 1
1 1 1 1 1 8 1...
5 answers
Ixi:AxiZx.ilu;#XeOGuopElplank: <reskX9+XIL36 .1NN :Tie:3X ,
ixi: Axi Zx.ilu; #Xe OGuop Elplank: <resk X9+XIL 36 .1 NN :Tie: 3X ,...
5 answers
Wrich of the following Is the correct chemical equation that represents JHf of Ba503(s)Ba2t(g) + 56+(8) 02-(g) - Ba503(s)Ba2t(aq) + SO32-(aq) Ba503(s)2 Ba(s) 2 Ss}02(g) ~ > 2 BaS03(s)Baso3(s) ~> 2 Ba(s) 2 S(S) + 3 02(g)BaSO3(s) Ba2-(g) + 503?*(g)
Wrich of the following Is the correct chemical equation that represents JHf of Ba503(s) Ba2t(g) + 56+(8) 02-(g) - Ba503(s) Ba2t(aq) + SO32-(aq) Ba503(s) 2 Ba(s) 2 Ss} 02(g) ~ > 2 BaS03(s) Baso3(s) ~> 2 Ba(s) 2 S(S) + 3 02(g) BaSO3(s) Ba2-(g) + 503?*(g)...
5 answers
Evaluate the integral. (Use C for the constant of integration.)arctan(6t) dtarctan(6t)t - Kzln(l36/2 + 1/) + €
Evaluate the integral. (Use C for the constant of integration.) arctan(6t) dt arctan(6t)t - Kzln(l36/2 + 1/) + €...
5 answers
Chapter 02, Problem 09 tourist bcing chased an angn running straight line toward his cr # 0 pecu behind the tourist and running 08 nvs 80 DVs The car % 8 distance Ihc tounx mcaches awoy salely: What the maximutn possible value for d?pcaris 31Numcethc toleraniceVeroClicwould Iike Show Work Ior this question: OpeuSmewadLA
chapter 02, Problem 09 tourist bcing chased an angn running straight line toward his cr # 0 pecu behind the tourist and running 08 nvs 80 DVs The car % 8 distance Ihc tounx mcaches awoy salely: What the maximutn possible value for d? pcaris 31 Numce thc toleranice Vero Clic would Iike Show Work Ior...
4 answers
Ss4i (SJsc JykajIn solving IVP numerically, Euler method gives high accuracy with large step-size h Select one: TrueFaise
Ss4i (SJsc Jykaj In solving IVP numerically, Euler method gives high accuracy with large step-size h Select one: True Faise...
5 answers
The graph ofy=f (~) Is shown below, Graph y={({: F
The graph ofy=f (~) Is shown below, Graph y={({: F...
5 answers
Question 24 (1 point) Test scores on a statewide standardized test for a large population of students are normally distributed with mean 9.44 and standard deviation 1.75. Certificates are given to students who score in the top 2.5% of those who took the test: Fred, a student who took the test; finds out that he earned a score of 13.1 on the test: He will not get a certificateTrueFalsePrevious PageNext PagePage 24 of 25
Question 24 (1 point) Test scores on a statewide standardized test for a large population of students are normally distributed with mean 9.44 and standard deviation 1.75. Certificates are given to students who score in the top 2.5% of those who took the test: Fred, a student who took the test; finds...
4 answers
Completion Seaelt;quextiooStudy the convergence or divergence of the series 2n (cos &)2n n2 n=[ depending on the parameter &.
Completion Seaelt; quextioo Study the convergence or divergence of the series 2n (cos &)2n n2 n=[ depending on the parameter &....
5 answers
C L 7Y p 6- 7Iq
c L 7 Y p 6- 7Iq...
5 answers
Consider f (r)J + 4 Determine all values of wliere is discOntinuous.For each value of stated in part determine whether the discontinuity is removable . infinitc, jup discontinuity Explain YOur reason by calculating lim _+a + f(r) and linl_ ' f(c) for cnch point of discontinuity
Consider f (r) J + 4 Determine all values of wliere is discOntinuous. For each value of stated in part determine whether the discontinuity is removable . infinitc, jup discontinuity Explain YOur reason by calculating lim _+a + f(r) and linl_ ' f(c) for cnch point of discontinuity...

-- 0.027905--