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J02. Calculate Mean and Mode for the following data:Classes 0-1010 - 20 20 - 30 30 -40 40 50 50 -60 12 16 16 2550 - 7018...

Question

J02. Calculate Mean and Mode for the following data:Classes 0-1010 - 20 20 - 30 30 -40 40 50 50 -60 12 16 16 2550 - 7018

J02. Calculate Mean and Mode for the following data: Classes 0-10 10 - 20 20 - 30 30 -40 40 50 50 -60 12 16 16 25 50 - 70 18



Answers

Find the mean, median, and mode of the data set 10 12 20 15 20

Hell in this problem we have to find main invariance by using the given data. So here we have given the following table. First of all, we will find the mid values that is X I. So we get five 15, 25 35 and 45. Let assumed mean as equals two 25. So in order to find the mean, first of all, we will find you Y which is equal to X I minus assumed mean Upon 10. So we get EYS minus two minus one 01 two. Now we will find a fi you Y it would be five into -2 is -10 18 to -1 is -8, 15 in 2, 0 is zero 16 into one is 16 and six into 2 is 12. Similarly, we will find similarly, we will find a fire you a square. So we get 20 seat zero 16 and 24. The submission of F i U I is then and The submission of FIUS Square is 68. Now we know that Mean as equals two assumed mean plus sigma, F I U Y. Upon submission of F I into age here edges the height of the class interval by substituting the known will use we get Mean as equals two 25 plus 10 appoints stay into 10 by simplifying it. We get 25 Plus two which is equals to 27. Now we will find variance. We know that variances equals two hide square a bone and square and do and into sigma. F I U I square minus sigma. F I U Y who square by substituting the known will use we get penn square are born 50 square into 15: 68 -10 sq. By simplifying it. We get 100 upon 2500 Into 30 400 0. It would be equals two. Run upon 25 into 3300, Which is equals two, 132. Hence we get me as equals two. Mhm. 27 variances equals two 132.

So if you put that list in your calculator, so stat at it, taping all the numbers, then stack count number 11 very stats that will give you the mean, which is 600 0.29 If you scroll down, it will give you also the median 535 0.5 and just looking at the list. Or if you need to put him in order, you can find the mode with one that appears the most to be 499.

Okay, let's say we start off with the data set as shown, and we want to find the mean to find the means. I'm gonna take the sum meaning add all the numbers together and then divide by how many numbers there are. They are 1234567 numbers. So once I add these together, and I'm just gonna quickly put in a plus sign between them when you add all of these together and it's not a bad idea to use a calculator, I get 46.1. So 46.1, divided by seven rounding to the nearest 10th gives me 6.6, which is the mean of this data set. If I want to find the median, there's something I have to take care of. First, these numbers have to be in order because the median is the middle number when the numbers are ordered from least a greatest. So I have to put these numbers in order. Let's go ahead and quickly do that. When we put the numbers in order. You just want to make sure that you include every number that was in the original data set and that each one is from least a greatest now, looking at the numbers from least a greatest. I'm looking for that middle number, so I'll have three to the left and three to the right. The middle number is 6.1 6.1 is my media for the mode. That's the number of the data in the data said that occurs the most okay and which one occurs the most? Why, that would be the 1.5 It occurs twice. All the other numbers occur once, so the motor of the data set is one.

Hello students. And this question we have given this data and we are also given that more of this data is given to be 22. Okay, now we need to find the value of Y. Okay, so for uh this data for this is a group data. Okay, so for that first of all we need the formula of more. Okay, The formula of mode is given by L plus f minus F. One divided by two. F minus f one minus f. Two. Multiplied by edge. Okay, so for all these values, F F one, F two, H and L. For these values. Masterful. The leader model class. Okay. Model class is nothing but the class with the highest frequency. Okay, so if you look here we are given that X&Y are less than 10. Okay, so our model class will be 20-30. Okay, because 10 is the highest frequency. So model class, Model class is 20-30. Okay, so for that the value of l comes out over 20. Right? The value of f comes out to be 10. That is a frequency. Then everyone is the frequency of lower class which will become eight. Okay. And F two will be the frequency of upper class which will be X. Okay. And the edge is the interval intervals 10? Okay. So here we have all the values. So if I put it to the formula of mod mod is given already given 2 22 22 is it was true 20 plus 10 minus eight, divided by 20 minus eight minus X. And 2 10. Okay, so that's it. Now we can find um X easily. So from here to is equal to 20 divided by 12 -1. Okay, so from here X comes out of it too late now for finding a relation of X rayed by. We are given that there are 30 children's. Okay? So some of the frequency comes out of the 30, Right? So Some of the frequency that is five, let's eat plus 10 less X. Plus. Why? These all add up to 30? Okay, So X plus Y comes out to be seven. Now the value of X is already too, so the value of Y comes out to be five. Okay, that's it. Thank you.


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