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Complete Assignment MZZUse a sheet of paper to answer the following question. When complete, take a picture of your answer and attach the ffile to this assignment]D...

Question

Complete Assignment MZZUse a sheet of paper to answer the following question. When complete, take a picture of your answer and attach the ffile to this assignment]Draw the products obtained in each of the following reactions; assuming that only one equivalent of each reagent is lused in each case;HBrBr2

Complete Assignment MZZ Use a sheet of paper to answer the following question. When complete, take a picture of your answer and attach the ffile to this assignment] Draw the products obtained in each of the following reactions; assuming that only one equivalent of each reagent is lused in each case; HBr Br2



Answers

Write the equation for each reaction described. Follow your instructor's advice about whether state symbols should be included. Pure bromine trifluoride decomposes to its elements.

In problem 13 Right? The occasion when calcium combined with Brahman to form calcium bromide. So this question is taken from the topic Chemical reaction And this is the case off the combination action in which calcium combined with Ramin toe form calcium bromide see a BR to and this is the combination reaction. This is, ah, combination reaction because in the combination direction is the reaction in which two or more elements a combination direction is the reaction in which two or more elements or compounds or compounds reactant combined to form reluctance. Combine no form a single compound, single compound product so like X. That's why that will form x way. So this is the general representation off combination direction I saw. So this is the reaction. This is the balance reaction in which calcium, which is in a solid form, combined with bombing which is in liquid form toe form calcium bromide CRB arto, which is in solid form. So this is the combination reaction

And this question. We were asked to draw the major products from the reaction of one equivalent of HBR witchy with each of these compounds and then to indicate the kinetic and thermodynamic products. So these are both going to give us 12 and 14 addition products, since both of these compounds are dying's, And so to figure out what those air gonna look like, we're going to start by numbering the dying. So numbering just the four carbons that are participating in those double bonds. Um, and we're gonna number them to get the most stable carbo cat lions on each side. So we can either go. 1234 or 1234 Our car broke a tie ins will always be on carbons two and four, So we'll take a look at what those would be. So if we went from the left on this top one here, that would be, uh, a secondary four, number two and tertiary for number four. If we went from the top, it would be tertiary for number two and tertiary for number four. So we're gonna go with the way that gives us to tertiary carbo cat Ryan's still number like this. And the first stop is always to take that one to double bond and grab the hydrogen with it and kick that bro me in a way. And that gives us a carbo cat. I an intermediate. So that will look like this for this structure. So the three and four double bond hasn't moved. We have a carbo cat, I and a number two since that's the Elik position. And that hydrogen went on the carbon one to make it to give it that fourth bottom that it needed. And then we have a broom ing nuclear file leftover. Now, this also has a resident structure to tell me it to the 14 product. So we move this double bond like this, we get a second residence contributor for that carpet, can I? And it looks like this. So now the double bond is their car broke. Iodine is there. So then we'll get to products here. Um, on those occurred just from the brahmi nuclear file attacking each of the carbo cat ions. So from that first car broke out, Ryan that I drew will get the 12 products and that will look like this. So this double bond is still here, and our bro Ming is on that carbon. And then from the second one that I drew, um, we'll get the bro mean over here. Um and so that will be our product there. So this is our 12 witnesses are 14 and then as far as kinetic and thermodynamic products, the kinetic product is always the one to products. This is kinetic, and that's because of the proximity effect to me effect. So the proximity effect just means that if we're under kinetic conditions, we don't have a whole lot of energy to spend. Um, the Carbo catalon is right there when the bro mean is detached from the Kardashian. So when the broken becomes that nuclear file, that carbo Catalan is right there ready to be attacked. So it was just the closest thing. So just due to proximity, as it's named for, that will be that product left the kinetic product. And then the thermodynamic product is always just the most stable double bond on DSO here. We're gonna look for the double bond that is the most substituted. Now here we have three substitution on each side, which means that the double bonds are pretty much the same stability. Um And so, um, for here we can't determine which one is the thermodynamic products because they're the same stability. We don't have anything else to go off of, um, to figure that so we don't know what's around, and I'm a product is here, or they're both of their mother. Never brought it. Um, more likely. If you're under thermodynamic conditions, you'll get equal amounts of both Bronx and then for part B will do the same thing. So well, number our carbon. So if we were to go from the left here, um, we would get tertiary for carbon to and primary for Harvard four if we went the other direction. We get secondary for two and tertiary for force. That's what we're gonna do. 1234 We'll use that one to bond a grappa, hydrogen and kicked the Bruning off. Leave us with a nuclear file, and then we'll get our first, um, carbo cat on intermediate bond number two and we can resonate that to get a car broke out. I in on number four as well so I would look like this. And then we'll get our two products from those intermediates by just attacking them with Ebro mean? So this would be the first one. This is the one to product, and then the 14 product would be this one. So then, like I said before, the kinetic product is always the one to product because of the proximity effect. And the thermodynamic product is which everyone has the more stable double bond, a k a. The more substituted out king. And so here that is going to be the one to product as well. Since one of substituted on all four sides, this one is only on three sides. So this will also be the thermal products because the al peen is more stability more stable, So that is part B.

Part A here asks us to draw the products of each of these reactions. So starting with number one, um, this any an issue is going to deep protein. Ate this al kind here. So we will get, um, a C minus and then in the second step, this is no nuclear file will come and attack this carbon and kicked burning off in an s and two reaction on that will give us this product and then for number two, Um, now hear the n a. H is going to deport Nate this oxygen, just like it did above with E l kind. So now we have a nuclear file and that will come in and attack in the second step and kick off the roaming in another s end to So this, um, reaction will give us this product, which is an ether. Um, and then part B assets were two sets of reactant that could be used to synthesize this Al Qaeda. So each set is going to have an alcohol allied and a nuclear file. So we can either split it right here, or we can split it right here. And we're gonna do basically what we did in number one up here. So if we split it, um, on the left side over here, that means that our calculus allied would be, um, that to carbon chain right there, apple chain. And then the other side is going to be the, um, nuclear file. So the negative, um, I on the satellite, I on that we had appear. So that would just be the rest of the chain there, So that would look like this. And then the second set would be splitting it on the other side. So now we could have this as our, um, nuclear file. And this is our calculus Allied. So that would look like this. So this would be our nuclear file in our oak Johar lied would be the rest of that chain like that. And then part c asked for two sets of reacting again using an alcohol highlight and the nuclear file that could make this ether. So again, we're going to split it on both sides. So if I split it here first or alcohol, I will be that left side. So it would look like this. And then our nuclear fire would be that um, oak oxide I And on the other side with the rest of the chain like that Or the other option would be to split it on the right side. So are Alcock Side would be on, uh, this side here. That would be our Nikolay file and our alcohol. It could be the rest of the changes that would look like this. So that's like an option or part C.

Waiting to draw the product that each of these nuclear Felix substitution react. The first step is going to be identify whether it's going to react by an S and two Rs and one. This is a strong nuclear file s. So it's going to favor us into reactions. And this is a second, uh, yeah, secondary alcohol light so I can react either s and one arrest into. But since the nuclear file a strong, it's going to be in Essen Turia. Our product is going to be there. And, B, you need to identify whether it's a strong nuclear file. Fist is a strong clear file because it bears the negative charge. And this is a primary alcohol allied, which means it can only react by s and two mechanism start product or B is gonna be the night instead of in alcohol or C. Our substrate is this. Yeah, and our nuclear file is water. So in this reaction, the nuclear file is weak. Meeting that it favors s into s and one reactions. Sorry. And the alcohol light is tertiary, meaning it can only react finding us in one. So our product for sea is going to be, uh, receiving mixture of products being this and this and we are substrate. Is this okay? In our nuclear file is ethanol. So once again, our nuclear file is weak. Which favors and Essen One reaction, and it's once again at a tertiary Alfa Hey, light, so it could only reacted by innocent one. So our product in this case is going to be another ischemic mixture. And it's going to be this for e our substrate business and our nuclear files. Is this so this is a strong nuclear file, meaning that it favours us into reactions in its That's a secondary awful. Hey, life. So I could be there s and one arrest into, but favors s into because technically, a file. So our product for this reaction going to be this for out our substrate is this and our nuclear file is this. Now, this is a weak nuclear file because it doesn't marinated charge. It's neutral, But this is a primary awful Hey, life so it can only be s into. So our reaction is going to proceed. Inform this product and it bears a positive charge. So you need to You can include the Orions as it's counter ayan


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