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Suppose you saw this step in a proof: Construct angle bisector $C D$ to the midpoint of side $A B$ in $ riangle A B C .$ What's wrong with that step? Explain. ...

Question

Suppose you saw this step in a proof: Construct angle bisector $C D$ to the midpoint of side $A B$ in $ riangle A B C .$ What's wrong with that step? Explain. (FIGURE CAN'T COPY)

Suppose you saw this step in a proof: Construct angle bisector $C D$ to the midpoint of side $A B$ in $\triangle A B C .$ What's wrong with that step? Explain. (FIGURE CAN'T COPY)



Answers

Suppose you saw this step in a proof: Construct angle bisector $C D$ to the midpoint of side $A B$ in $\triangle A B C .$ What's wrong with that step? Explain. (FIGURE CAN'T COPY)

Let's begin with it says the acute angles of the right trail a complimentary. So those who Adam to 90. You shouldn't be adding up to 19 right? Okay. I don't know. The given statement would be that it is a right angle triangle, because you see this 90 degree angle, so in that he's given a statement would be it is cargo move. And what we're hoping is rather prove use. Yeah, the acute angles. Complimentary. Okay, so there's over Tuesday events for party. No, for me. Your segment connecting the mid points off to slides of traveling His home is long as the outside William. So the giving statement here with me, that of course, Jim and the triangle isn't trying, huh? K is a big point off the loan J Yeah, on and isn't big point G. M. Okay. How come up with this is because the second their mid points therefore the main points by sect, the lines into two equal parts. So essentially what we would be a problem for him partly Is that Bill? End n Cay is Ah ha This m So that is what we would be profit given that J King do the same as K l

So far this problem using me given information and our hint, we're told to construct a line through point. See, that's perpendicular to segment A be absolute peak. And so let me do this. Um, we can label point p is going to be right here. And since we know that it is perpendicular to each of these, um, our last step is going to be proving that Point C is going to lie on the perpendicular by sector, um, or proving that C p is the perp particular by sector. So we already know that this is going to be true. Using are the converse of the perpendicular by sector zero. But we're going to be able to prove this amusing right, triangles. So since we know that these two segments are equal and, uh, these two angles are equal right here that tells us that this side length right here is also going to be equal. So, uh, the only possibility for a segment PP and uh, P A is that they are also going to be equal. So that tells us that, uh, this segment right here C p is the perp particular by sector of a B And so since our segment is a PC, that tells us that sea is definitely going to be all this line. So that means that point C does lie on the particular vice.

So we have circle. I mean start, we have Triangle ABC and we know that P is inside this triangle, so it's somewhere inside. It is equal distance from a so we want to know where it's located, so it can't be located on A and B because it is inside the perpendicular by sector of a B. That is true because if it's perpendicular, have a point. Is on the par particular by sector of a line than it. It means that it's equal distance from those two points. It can't be on a C because again it has to be inside and then the perpendicular by sector B. C. So since it needs to be equal distance from A and B, it's not gonna be on the perpendicular by sector of A C. So your answer choice has to be bi

So we have circle. I mean start, we have Triangle ABC and we know that P is inside this triangle, so it's somewhere inside. It is equal distance from a so we want to know where it's located, so it can't be located on A and B because it is inside the perpendicular by sector of a B. That is true because if it's perpendicular, have a point. Is on the par particular by sector of a line than it. It means that it's equal distance from those two points. It can't be on a C because again it has to be inside and then the perpendicular by sector B. C. So since it needs to be equal distance from A and B, it's not gonna be on the perpendicular by sector of A C. So your answer choice has to be bi


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