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Which reagents_ when combined with an acyl chloride, form an alcohol? Select all that apply.CrOz H,SO4 H,oDIBAL H, tbcu H,oNaBH, & MeOHLiAlHy, tbe H,o...

Question

Which reagents_ when combined with an acyl chloride, form an alcohol? Select all that apply.CrOz H,SO4 H,oDIBAL H, tbcu H,oNaBH, & MeOHLiAlHy, tbe H,o

Which reagents_ when combined with an acyl chloride, form an alcohol? Select all that apply. CrOz H,SO4 H,o DIBAL H, tbcu H,o NaBH, & MeOH LiAlHy, tbe H,o



Answers

What reagents are needed to synthesize the following alcohols?

Okay, so we wanna get the products the following reactions with benzoyl chloride. 1st 1 is with sodium asked it. So the oxygen study mass state is going to attack the carbon carbon and we're gonna replace the chlorine with an ester. I'll get sodium chloride as side products. So for B we have water and we need a car box of acid with Hcl. It's the actions the oxygen of water is going to attack the carbon. Carbon and chlorine in the deeper water wants to attach to the carbon carbon. You see we have di ethyl immune or dimethyl immune. So I got an email and the second equivalents used to ensure that the um are doesn't deeper in Hcl. This can attack or deeper the hcl. Okay, the structure and this is only a side product. This is obviously the meat products for a day. We have acquiesced hcl. So this is gonna be hcl actually the water. And the key to his gonna first deeper donate hcl. We had a cartoon and the water is going to attack the carbon carbon explain chlorine. And we'll get a car box of acid and we'll get Hcl is high product to. Uh huh. I guess if we we have a quiz sitting hydroxide. So this is really just under basic conditions and this is acidic. So the O. H. On hydroxide the base and water is the acid. And for D. H. C. L. Was the acid water is this is the base first attack the carbon carbon. Expo chlorine will get the addition of of um the O. H. And then and the water is going to dip originate the hydrogen on the karaoke acid. So you got the ac oxide ion. Okay so for F we have cyclo hexane. All it's really an ester chlorine is going to leave and the oxygen on cycle externals can replace the korean. This is bound to six carbon ring and we'll get HcL x one is uh Benzoyl mean? So the next, you know, the means to attack the carbon carbon and we're gonna replace we can emerge with HDL to H is for chlor a funeral. It's the most important thing here is the O. H. On the benzene ring. This is going to form an ester, replacing the chlorine with the oxygen and dropping the hydrogen. And it should be key tonight here here for I. B as isopropyl alcohol. So yeah, we've been asked her again with Hcl sir. And lastly nothing. Okay, the next one is with aniline. So this is similar to Benzel mean, But we just have Do you mean directly bound to the ring or somebody in a mud? And again, it's probably going to equivalent to prevent the amid from deeper in the hcl

Sir. Call. If you have in Parkside, you react this way. Some type of organic metallic creation like this comm prayed can have nuclear feel like attack left impersonation. You can access this bring opened product in this case of primary alcohol. So how can we access this first primary alcohol from a pox. I'd bring opening. We'll finish this on the right hand side. We have this to carbon chain. All of buying off Paul. And that can come from Ari Parkside, your left side. Can you from a Quran, you'd say two for react. These two together, all that we've been acidic workup will access this product. The second case, we kind of have a more complicated molecule. Remember? Of disaffection happens during ascent to fashion. So if we were to have some type of Parkside such as this when we rack when we redact this the fennel corin yard Since it's going to rectum, Essam to fashion will prefer to react the last Erik Lee 100 side. In addition, it will attack from the top face because this needs to do the stereo chemistry, have inversion on our taxes. The product we can think along the same route for this last compound. If we were to start from this a Parkside. And of course, that agency, we can have some profile continued. And if this purple grenier inward to attack from this position, we can have the ring opening. Proceed there, access this product.

So we were looking at some reaction conditions to form different products. So our reaction conditions are very important. Are re agents very important as this determines the sort of products were forming and the sort of eliminations that are substitution that might be occurring. So our first example, we have the following materials to form our product, which is now keen. Second example, I was starting material or re agents, and then we form our product. Following this, we have a different starting material. You can see what we're doing here is reforming the same product. However, they all require different conditions because we have different starting materials, three equivalents of an A and H to and then we have a check A which forms an al kind. I'm gonna h two in one equivalent on and I to be p two, which transforms are out cane. So al kind down to Al Keen one from a single bond to a triple bond back down to a double bond. Last example here, starting off with our all kind triple bond, obviously. So all we have is the second step from the previous example. We have one equivalent of H two coming up and I to be p two. So for my product

Okay. This problem is asking this to start with a seal Corot in each of these examples and eventually get down to a product by using a neutral molecule as my nuclear file. Okay, so let's go ahead and analyze this first one, For example, we have a CDO card, as we do in all those examples and returning that into acetic acid in this particular case. Okay, So in order to form acetic acid from my acetyl chloride, all I really need is my neutral molecule of water. Okay. And that is simply because the electrons on the auction are gonna behave as the nuclear Philip source to move onto that Carbondale to eventually move the electron into this auction, which eventually gonna kick off that Korean. And eventually we're gonna get a permanent alcohol, which we just need to de protein eight in order to get my eventual car box look acid. Okay, so that's just a little bit into the mechanism. But basically, all we need is a neutral molecule of water to form that, Um um, ascetic acid. Okay. Next up, we have acetic acetic record, eventually forming my A mind right here. So all we really need for this is a neutral molecule of ammonia, okay. And very similar to my water. My nuclear filic source is the electrons on that estrogen. Those they're gonna go ahead and attack my Carbonell, which eventually gonna take off chlorine and eventually get my anedge to in that position. Okay, so that's just the neutral calculated. Okay, next up, we have this one. We just need to get this onto the position where my korean used to be. Okay, So all we really need to do is analyze at this compound to my substitute, and then we just need to make it neutral. So if we had this isolated, it'll be negatively charged on the auction. In order to make that neutral, we just need to add a hydrogen. So the Montreuil needed as a nuclear file to make that compound is my H. Oh, and then we have ch two ch two and stage three. So this would be pro panel because it has three carbons and then the alcohol. Okay, next up, we have this one suitable, right? It turning into this a might in which we have two ch three is attached. That nitrogen. Okay, So the trick is again isolate this substitution. Okay, if we just isolated that, that nitrogen will be negatively charged because it would just have Onley two substitutes on the nitrogen. So in order to make it neutral, all we need to do is add a hydrogen. Okay, so the neutral molecule needed would be h nitrogen. And then my two ch three groups attached to that entry just like that. OK, moving on to this one. Okay. So as we can see, we're replacing this Korean with this group right here. Okay. All we need to do is isolate this. If we're to isolate that by itself, the auction would be negatively charged to In order to make it neutral, we just need to add a hydrogen. Okay, So the molecule needed his h o. And then my cycle vaccine. It's a cycle axonal. Okay, next up is this one. So as you can see replacing that Korean with this group right here, OK, if we're to isolate that the auction will be negatively charged in order to make it neutral, we just need to add a hydrogen. So we're just adding a hydrogen to this multi right here. so h oh, benzene. And then my nitro group. It's that is the moment ill needed, and these are all the answers to this particular problem.


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