For the following reaction, provide the rate lawOH...

Given these data for the reaction $\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{C}$, write the rate-law expression.

Okay. So for the first part to understand this, if you look at the concentration of cielo too, if this is increased by factor three. Do you read? Yeah increases By a factor of nine. Yeah. Okay. So what does this mean Is for the first part of it is equal to twice married and then for wage negative men read. Mm not dispensary. Which negative concentration? Good news is my three late also increases by this afternoon to the right. So this means this will be quite negative. We go on to the next spot. We use this data from experiment number two to calculate key. He stood by the way Created a frenzy of u. knows per second to the point of view to view. Square finds you things you don't notice this is equally to find me tend to be powered too. Just well because I'm more more square second years. Everyone did. The c fall weight is included 2.3. Then you come back to this much and then the new concentration. Yeah after calculation this is north Korea comes out to be yes.

Problem 34 party from their data given when concentration up CLO two increased by Pachter three. In experiment two. To experiment one. That rate is increased by a factor nine Increased word factor nine. And when concentration of which negative Increased by a factor three. an experiment to to experiment three, the rate is increased by By a factor three. The reaction in second the reaction, it's second order in concentration of C L 02 And first ordering always therefore really equals two came to concentration of cl or to the power to into concentration of which negative this is. And support party. No, in part B. Using data from experiments too, K equals two. Rate divided by concentration of cielo too. To the power to into concentration of which negative. Now put the values rate given in question. That is 0.0 0276. And per second. And concentration of Cielo to it's 0.020 mm. To the power to multiply by zero Jiro 30 And after calculating we get 2.3 into 10 to the power To into empty. The power -2. And as to the power -1 this is answer part Part B. No in part C. Red equals to use this formula. Okay, value calculated here that is 2.3 into 10. to the power to I. M. To the power minus two. And as to the power minus one into Concentration of cl or two to the power to that is 0.100 M. To the power to into 0.0 pipe zero M. After calculating we get 0.115 30 approximately equals two 0.12 M per second. This answer part part C.

Yeah one this question uh we know that the rate. Is he going to K. Multiplying by uh i minus concentration of uh and applied by the concentration based on the power of montblanc, Jose l minus raised to the power of N. Where M and N. Are the orders with respect to each of them. And key is the great conflict and we have to find M and K. So we have to use this data. So first we're going to use the data where the O C l minus is the same. That is, we can use the data points one and two. And as far as two is concerned, the rate to its 6.2 and then we simply plug it in into the situation. Is he going to K concentration of iodine is going to pleased to the power of him consultation of Oocl is point oh five raised to the power of and now the reason I chose this is because the OOCl is going to cancel out and I can get the value of them. It's the same way. Right? This one now three point oh 510 days to power minus four equals K. And the concentration of uh hi minus is 0.1 please. To the power of them 0.5 raised to the power of end. If you divide the two can eliminate the K. And the U. C. L minus. And you end up with something like uh this is to buy no three and this is to to the power of M. And from here you can say that M. Is equal to one approximately. So now we know the order with respect to the uh you died ion. And to find the next one we are going to use. Actually you can use any two of these because you know the iodide is changing. So you can't really eliminate the Aphrodite but you would have to use uh let's say two and three in this case. So I'm gonna use three first and then to I can use to first and then three. Let's do that. So see I can write the same thing six point to entertain, inspire minus forward. Yeah. Is he going to K in 2.2? I know I am as one raised to the power one went applied by use point right 1st 12. And hey man can use the the third data 0.1183 to 10 days to follow minus four. Is it okay? Multiplied by instead of 0.2. And when you use 0.3 and that's the point oh five. You're going to use something like find or what. And then you can choose to divide the two. You notice that on one side to get uh 6.2. Yeah which is 6.2 divided by 1.3. Come close to uh Yeah come close to uh key point 39 equals his cancels out. I get two divided by three since I'm dividing 30.2 and 0.3 I want to play by and or five divided my 50.15 raised to the power of N. And then I manipulate this and you had 25 by three. Do an invite to take approximately fine here equals five years to the power of end and from there and get anyone's wants. So now I hope that it is first order of respect about the reactions and I can write the equation finally. As rate was it? Cool. Okay concentration of are you doing is the power of one and concentration of We'll see and raised to the power of month and therefore I can calculate okay. As rate divided by the concentration of iodine, multiplied by the concentration of all cr minus. And I can use any of these three data points. So let's say I used the last one which is 1.83 into 10 years of power minus four. Do I did buy consultation of what you're doing in this case was 0.3 in 0.1. Some of the divided by 0.3 multiplied by point of one since both are raised to the same part. Uh Let's see what I get 2.3 when he played the 0.1. He loves that in multiply that by 1.83 Oh yeah I get one oh 61 and that is going to be my K. And therefore I can say that the rate is equal to Uh huh. The K point oh 61 multiplied by the concentration of the iodine iron, multiplied by the IOC and mines. And that is the red situation from the experimental data

For the given reaction have to Cielo too. A quiz plus two H minus produce seal of free minus, uh, Cielo to minus and h 20 mhm for part A for us to use the given information and determine the rate law. So the rate sequel to A which is a constant the l 02 x corporate always minus why so to calculate X, the rate one overrate two is equal to okay. 20060 Thanks. Over. Uh huh. All right, 0.30 Why? 0 to 0 x 0.30 y okay would cancel. This would cancel, and we would find that the rate here Mm. This would be equal 2.248 over 0.276 And so this would yield 0.60 x 4.20 x yeah. 0.248 over 0.276 33 X is equal to 8.98 We take the log of both sides The X log three over or equal Salak 898 to find a bi log three. Mhm. We find that X is equal to two no itself for why will go great. Three over rates two. This is equal to k 0.20 x 0.90 Mhm wine over k 1020 x 0.30 Why this would be equal to 0.828 over 0.276 Okay, councils, Clinton's lawyers or 20 X councils and this would give us 0.90 y over 0.30 y It's equal 2.828 over 0.276 three y is equal to three and therefore y is equal to one and our rate law here the rates equals K cielo to excess, too. And why we found was one And there is our rate law for B were asked to calculate the value of K So let's use experiment one. So our rate people K c l 02 oh h minus. And from one, we get 10.0 248 Yeah, I am over s equals K 0.60 I am squared over 0.30 I am solving for K we find that it is equal to 2.30 10 of the two one over M squared s and for C mhm last to calculate the rate when c l 02 and O H are given. So rates it's equal to 2.30 times 10 to 14 g. Yes. And say hello to is 0.1. Yeah, and this would be point 050 Moeller and solving here for the rate we see that the rate will be equal to 0.115 mm over s.