5

Ifl determinant of A10.25 then determinant of A= 5Selectilone; 0 HTrueFallse...

Question

Ifl determinant of A10.25 then determinant of A= 5Selectilone; 0 HTrueFallse

Ifl determinant of A 10.25 then determinant of A= 5 Selectilone; 0 HTrue Fallse



Answers

Evaluate the determinant of $A$. $$A=\left[\begin{array}{rr} 5 & -\frac{2}{5} \\ 10 & 2 \end{array}\right]$$

Hi, guys. In this video, I'm going to show you how to find the determinant of the Matrix in red in black. I have already written out the generic formula for how to find that the determinant of any three by three matrix and the way in which we do that is we simply follow this equation. And we used the generic setup of this matrix over here that we call a. So I want to do is we're going to substitute these values of this matrix into the sum equation based on their corresponding position to matrix A. So they start off of the lower case A in the top left corner. We see that in the Red Matrix. That number is, in fact, five. They were going to buy that by e times I, which is 25 minus f times H, which is just zero. And then we're going to take B, which is just zero, and we're not gonna worry about We're putting in here for now, because anything times zero is just zero, and then we would look at sea. Well, you see that? That's also zero. So regardless of whatever is in there, this term will also equal zero. And so, basically what we have here, the end is just five times 25 and that is equal to 125. And so therefore, the determinant of this matrix is 100 and 25. Okay, guys, thank you so much for watching. Feel free to go back and positive video and replay anything you need.

To find a terminate here across most law, and it's brought again because that's the general form. Said would be zero do bond minus minus two into five. That's what base zero minus minus two five that should be two in too far in terms of 10 determinant a week.

Okay. Here. In this case, we simply need to find out the dominant of a three by three order matrix The Matrix has given minus that, despite this matrix. Clear. Uh, this is given minus one minus 20 This is three years. Five on this is 40 and minus one. So let's name this metrics as eso is minus one minus 20 385 on this is 40 in minus one, right to the remnant off by simply expand along. Route one is minus one. Right on. This will be simply We just waited in a bracket Women's that This rule when this quite humble Burim operates eight times of minus when it's minus it, and this is zero three becomes ministry. So I do in this particular role on this particular column, so minus two times of minus one is to again, this part is gone. And then plus four, because this position is +13 right, one plus trees for which is a one number. This position was one plus two, which is three. That's why it was minus a hard number. So this ford, if I just expand removing this particular row and this column It is minus 10. I minus two times if I was minus 10. And again, this it is gone so that I lose eight over here, Right, minus six on, then minus off. What? So what is this? Now? This is simply eat minus, um 46 right? Eight minus 46. So we just subtracting for the six or the final answer that is a determinant of a is. It was to minus ondas values carry it by 38 it is 46. That's what this is minus idea, all right.

In this question. We have to find a determinant off the Matrix then. So this means that we are to find matrix off 10. It should be equal toe 10.


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