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Question 8 (1 point) The following pedigree shows the inheritance of colorblindness, an X-linked recessive trait Note that heterozygous individuals have not been i...

Question

Question 8 (1 point) The following pedigree shows the inheritance of colorblindness, an X-linked recessive trait Note that heterozygous individuals have not been identified, and that the phenotype of individual Ill-2 is unknown:Based on this pedigreethe probability that individual Il-4 is a carrier is 50%individual IlI-2 can only be colorblind if his mother also has colorblindness in her pedigreethe probability that individual Ill-5 is a carrier is 100%Oit is impossible to determine the genotyp

Question 8 (1 point) The following pedigree shows the inheritance of colorblindness, an X-linked recessive trait Note that heterozygous individuals have not been identified, and that the phenotype of individual Ill-2 is unknown: Based on this pedigree the probability that individual Il-4 is a carrier is 50% individual IlI-2 can only be colorblind if his mother also has colorblindness in her pedigree the probability that individual Ill-5 is a carrier is 100% Oit is impossible to determine the genotype of individual Il-6



Answers

Color blindness in humans is an X-linked recessive trait. Approximately $10 \%$ of the men in a particular population are color blind. a. If mating is random with respect to the color-blindness locus, what is the frequency of the color-blindness allele in this population? b. What proportion of the women in this population are expected to be color blind? c. What proportion of the women in this population are expected to be heterozygous carriers of the color-blindness allele?

Gin pedigree. Gen X question about, um, color blindness. So we have a woman who, with normal vision, so they're going to give her a big C. Leo. But she had a father who was color blind since he was color blind. Um, that means she had to have gotten a little seeing color blindness, a Leo from him, because that's the only Ekstrom Sony has together. She marries. As the story goes, a man who was color blind since he's a man, of course, is a Y chromosome, and he has a color by no Leo on the Moon X chromosome he has the first question is asking about the color blind man's mother, and it's basically saying, Mother, the posture possible. Gina types. Well, we know that she had to have an X with little C. Leo, but we don't know if she's color blind or not, so she could have been headers. I goes for the C Leo, which would be big, see little Sea or she Could Be Home is, I guess, and just had too little seal eels. And thus not only, but you have to see a little see Leal's. She would do anyone to him, but she also be colorblind herself. So that's the man's mother, um, were asked, What's the probability that ah ah boy will be born and that the first child born will be both of boy and colorblind? So let's just do the pundits where here, and try to make it big. I never make my opponent's where is big enough, all right. And this is the planet square between the relationship in between this man and this woman. Right? Um, so we'll put the woman here, so she has a big C. Leo. She has a little see Leo. I'm trying to put a little tail on my little seal eels. This is the man. He has a little See Leo for these color blind, and he has a Y chromosome. All right, so let's fill this in this upper box here, obviously is going to be a female says would be daughters, and they would have won big C and one little see Leo, because that's big Celia right there. And these would be daughters who have too little seal eels so they would be colorblind. Oops, My tailor. Then on the bottom roadway. That's where we're gonna have sons. Ah, and the sun would be big C. So each has normal color vision. And then this would be for sons who have color blindness and are nevertheless sons because they have a Y chromosome. All right, so now we can answer the question says so. What's the probability that the first child would be both a boy and fell applied? So this is the four possible Gina types of the Children, right? With respect to color blindness of the probability you trying to be a boy and color blind would be one out of four or 25%. The next question asked us. What is the probability that I think it's the second child is a girl in color blind And again, um, the probability that it's a girl ah would be 50% and the probability that the color blind girl would be 25% now if we're asked and I think that's what this question tackle its but proportional girls are colorblind. Well, half of them will be color blind, right? So 50% of the girls will be color blind, right? So they leave their normal vision or they'll be colored by, but those are the two options. Um, and then D access, Um, for all the kids. What port portion of them would have normal color vision? Well, if they had a big C Leo, they'll have normal vision. So this would have normal vision. This one. These would have normal vision. These would be color blind, and these would be color blind. So the answer is 50%. We'll have normal vision.

I want their students on today. We're gonna be talking about the following pedigree described in 1937 by c. l. Bridge shows the inheritance of excellent colour blindness and hemophilia in the family. What is the general type of two oh 202. So that's right. This and do any of her Children provide evidence of recombination between the genes for color blindness and hemophilia? Well um Camp in image shows. Uh huh. Pedigree personally analysis. Okay. Floor she ophelia. Okay. Also mm. And colour blindness. Sure. Yeah. Um. Mhm. Okay. Both these that's when workers. Yeah our capes blake. Right. Yes that's his this quarter. Mhm. Yeah we scroll down for extra room. So the, okay. Mhm relevant. Yes she, mm. Okay. Are separated. Yeah by 10. Yeah So yeah possible genotype. Yeah. Yeah maybe uh 12 to if he pixie will H. L. C. Deck age. Yeah. So she is a repulsion head to road. I do it for both two genes. Go with that. Yeah. Come on. All right. Her Children better. I agree continent. Oh yeah the given four years and that's it. I hope you find this very helpful and please feel free to look at the content from other creators that go over and explain what the tractor questions you need extra help with. Okay.

It stands fever going to be talking about the following progeny described In 1938 by B. Right crap shows that the inheritance of excellent colour blindness and hemophilia family. And then one that was a possibility for channel type two L. One. Um Hope I read that right. I hope I would tip. Right. And for each possible genotype evaluate the Children achieve one for evidence of recombination between colour blindness and hemophilia jeans. So. Mhm. Mhm. Given images shows cool. Yeah, pedigree. Which Okay. Can you this yeah. Great alien. Okay. Green colored bones. Both please disorder uh kicks right? Recessive disorders. Okay. Yeah. Very good. So yeah. Rose jeans. Mhm. Mhm. Really? Very yeah. Mhm. For two years? Mm hmm. Yeah. Mhm. Mhm. So yes she's tight. Yeah. Oh for um yeah 2001 and two this one. Um Let me see if I have to write it below because this is gonna be a lot. So let me just scroll this down. Okay so her part flips So they're part one. It would be um Hello See Little H. Over 60. Big Age. Um General type you can either lessons of four sons where uh one and four. Mhm. Yeah. Her name. Thank you. Yeah. Yeah. We tell unit. Okay. And two three plum. Great. Are you ready? I wonder wins? Yeah. Yeah. And then when it comes down to part two scroll down, picture Room two it would be a big see little bitch. Never seen big H. Yeah. Can you type of four cents. Especially where I was fine. See oh my God two C. Big C. H. Also, once Little So Little H and um three is a big H. Mhm. And for a big see Big H. And, yep, that is it. I hope you find this very helpful and please fulfill you look at other content creators that go over and explain what attracted questions we need extra help with. Okay, bye.

Being asked about how any hetero zygotes there are female headers I got's there are in this population. That's what's meant by a carrier. Right carrier is an individual who carries the recess of a wheel, um, but doesn't actually have signs or symptoms of the disorder. In this case, we're looking at color. Blame this and remember that the color blame. This is an X linked A Leo. Right? And so males, of course. Um, only need to have the one copy of the little see recessive Leo on their excrement. Someone they'll be color blind of females. If they have one or two copies of the Big C Leo, then of course, they will be normal in terms of their vision. All right. And so are being asked how we can calculate headers. I goes Well, um, so que were given que He was the frequency of the what? I'm calling the little CIA Leo in the population. And incidentally, that's also the frequency of males in the population. Uh, it's gonna be 0.8 on. That's because they only need one copy of the illegal toe. Have the disorder. Uh, what's the frequency of females well, Females, of course, need to copies, and we can use the Hardy Weinberg equation. Remember that two p. Q stands for the frequency of the Gina types. Uh, headers. I go Gina type in the population, so we just have to calculate to peak you. So that's two. Of course, P is going to be one minus 10.8 Right? So sorry. P equals one minus 10.8 which is 0.92 So we have two times 20.92 times 0.8 and that gives us 0.147 if I did my math correctly. So that's the frequency of carriers or headers. I gets in the population other all female, cause they can't be any email headers I goats. And it also doesn't really matter if the population is 50 50 because that doesn't really come into play here. We're just concerning ourselves. With few new


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