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Bhat is Uhe product t 0f chis reaciion?FCC (ercess)cRChOHOh...

Question

Bhat is Uhe product t 0f chis reaciion?FCC (ercess)cRChOHOh

Bhat is Uhe product t 0f chis reaciion? FCC (ercess) cR Ch OH Oh



Answers

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHI} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$ $\stackrel{\text { alc } \mathrm{KOH} / \Delta}{\longrightarrow}(\mathrm{A})$. The product $(\mathrm{A})$ is (a) $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH} \mathrm{CH}_{3}$ (b) $\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}$ (d)

In this problem from organic chemistry, we are given a reaction that is Bruno detail is reacted with silver star made followed by the reaction with markers and a nickel and the product is formed. We have to identify the product form out of these given options A B, C and D. So we will see the reactions and then identify the product formed. Yeah. Since in this reaction remote routine is first reacted with silver sign night. That is a G. C. M. Silver cyanide is mainly cooling compound where the reaction occurs between nitrogen of the Sinai pack with the carpet of this broom within. And this forms CH three CH two N. C. That is isocyanate threat. This substance is further reacted with hydrogen that is glucose hydrogenation in the presence of nickel acting as a catalyst. And both the carbon in the nitrogen part of this molecule are reduced My hydrogen and the product form will be CH three C H do NHLH three. That is a secondary I mean known as a tile the time I mean, so we can see this represents the structure deep, so structure the is the product after given reaction.

Okay, So this problem just has this going through several processes of converting money R A says convert $100 to bought. Um so we're gonna use our t function Syrian? Plenty of 100. I was just just gonna be 41.6 times. 100 which is Ah, 4160. But okay, Part of being says Cumber convert the result from part A two ringgit SA really is thea our function and plug in our 4160 number so that our function says to multiple about 10.9 if we multiply that about 4160. So put that in our calculator, we have 10.9 times 4160 which is 45,344. Uh, and that's ringgit. Okay. Um parte si as says, to write, they function to convert dollars two ringgit by doing a composition of functions. Uh, and you are of tea of X. Okay, so we're gonna plug t of X in tow are so I'm gonna have 10.9 times 41.6 x in 10.9 times 41.6 is gonna be 453. The conversion factor be 453.44 ringgit's per dollar and then it says plug it in, plug in 100 to convert it directly. So am of 100 people again. 100. We're just gonna get 453. 45,344. Which does match. Exactly. Okay, So parts of the ANSI do agree. Thank you very much.

In this problem I can write DDX and just look at it carefully here it is double one oh yeah you did you or C two edge fight In this side. Suitable 10 Or C2 H five in presidential. This will rearrange to give this compound fastest will rearrange to give this compound here it is C double one oh and here in this side it is suitable one oh Or C2 H five And this component in Potenza as 30 plus as well as our heat. We'll give this ad final component here. It is suitable. Born. Who? According to the option of sin siege, correct option, C correct answer.

In this problem, the reaction will happen. Something like this. Just look at it carefully. C H I. T. In pageants of three Ko edge, it will give CH Oh edge well three on further reaction. It will give at C. O at and it on for the reaction with K O reg. It will give the product ID h c O. Mhm. So according to the of sending this problem, option B. It correct answer option B. H. Correct answer for this problem.


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