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Provide an appropriale responseIx +y = 9and dxldt = ~3,then what is dyldt when x = 1 andy = 22Select one:A. 3B.C.D. 2...

Question

Provide an appropriale responseIx +y = 9and dxldt = ~3,then what is dyldt when x = 1 andy = 22Select one:A. 3B.C.D. 2

Provide an appropriale response Ix +y = 9and dxldt = ~3,then what is dyldt when x = 1 andy = 22 Select one: A. 3 B. C. D. 2



Answers

Check Choose the letter(s) of the correct response. If $x=2$ and $y=1,$ then the value of $x y$ is A. $\frac{1}{2}$ $\mathbf{B} .1$ C. 2 D. 3

So do so for the ex hand. We bring the the Georgian Uh right. And they would have monastery about minus x Iko Do do once Germans wanna go of your ministry So means that isn't will be my one. So because I have the same base, Mr McManus. Thanks, Molly. Could you want X equal to minus one and listen, we correspond you? Ah, be

So for this problem, we want to pick which one of these equations we could determine our A, B and C immediately. So, of course, our are quadratic equation. Baseline is a X squared plus B x plus C equals zero. Uh, so we want the equation that's in this format already, and we can pick out our A, B and C immediately. Our option here is our equation. A. It's already in that format. You don't have to do anything else. And so that's the one we're going to solve for. So three X squared minus 17 X minus six equals zero. So the convenient way that I don't think the book teaches you here is I'm a fan of the box method. So we're gonna use that, so we're gonna factor it, and the traditional way to factor is to try things until it works. Uh, I'm not offended that so I'm going to draw a box here, just four squares a section box. We're gonna put our first term in this corner three x squared. We're gonna put R C term in this corner. What, and we're gonna multiply a and C together. So three times six is 18. And now we want a factor. 18 Until we get to factors that weaken some together and get 17 r b value. We don't have to go very far. We have one and 18. And if we dio negative 18 and a positive one, we get negative. 17. Uh, they'll also both multiply together and get us a negative for our see value. So we're gonna take these. Two factors are one in our 18 and we're gonna put them in these boxes, and it doesn't matter which box you put them in. We're gonna put them in on. We're gonna add an X. Okay, Now look at the top two boxes. We're gonna factor out common terms from this box. Ah, in the top row weaken. Factor out a three x in the bottom row. Well, we can factor out is a one in the top column. The three x squared in the one X we can factor out an X. And in the second column, we can factor out a negative six. These become your parentheses, so we're gonna have a nex minus six times a three X plus. One equals zero. Let's confirm that we did this right? We're gonna foil so x Times three x is three x squared x Times one is x negative six times three x is negative 18 x and negative six times one is negative. Six. Combine the one X and the negative 18 x, and we get negative 17 x so have confirmed these There are two factors, and now we can use the zero factor method to find our X values. So we have X minus six. Equal zero and three x plus one equals zero. So for a first term exes six. Because we simply had six to both sides. Our 2nd 1 will subtract one from both sides and divide by three. Getting us X equals negative 1/3 and these are two x values.

Okay. We know we can use the quotient rule as well as the chain rule. For this question, this is a little long because, like I said, when we're using not only the question roll words to X to the fifth, minus one on the bottom. That's squared. But we also do the chain rule. Which is why we've got this on the outside. Okay, If we substitute X is one, we end up with negative 52.

You guys in this problem, you're given one minus one over X is equal to minus two. Over. Rex has to find what, three minus three over access to. So basically, get this problem out. When we do this problem Mountain, the way that we're gonna do this is we're going to solve the first system of equation. So first, let's subtract one on both sides and you'll get subtracting one on both sides will get negative. One over X equals one equals one minus two over acts. If you add one over if you add the two over X of both sides, you'll get one over X is equal to one. And from this you can easily see that X equals one is the answer. Plug in X equals one into 303 miles. Three. Over action, you'll get three minus three, which is equal to zero. So the answer is to this problem is going to be choice See, which says that three minus three over acts is equivalent to


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