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SelectHaC H 8 select H~ Tt C F OHCH3Delect...

Question

SelectHaC H 8 select H~ Tt C F OHCH3Delect

select HaC H 8 select H~ Tt C F OH CH3 Delect



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Choose specific acid-base conjugate pairs to make the following buffers: (a) $\left[\mathrm{OH}^{-}\right] \approx 1 \times 10^{-6} M ;$ (b) $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right] \approx$ $4 \times 10^{-4} M .$ (See Appendix $\mathrm{C} . )$

In this problem, we are trying to find the specific asset base Contra gate pairs to make the following buffers where a H 30 plus is approximately equal to one times 10 to the negative night molars and D O H minus is approximately equal to three times 10 to the negative. Five Molik's for a were given h 30 plus. So all we need to do is to find a K a value that is approximately equal to one times 10 to the negative. Nine smolders as we looked through Appendix C, the closest value would be hyper Burma's acid, where the K A value is 2.3 times since the negative nice and ecology and acid and base pair is given below for B, were given the polarity of O H minus, which is three times 10 to the negative five. In this case, since we're given the polarity of O H minus, we can look for a K B value as closest to the information given from Appendix C. We can see that ethanol amine, with a K B of 3.2 times since in native five, is the closest to this value, and the Contra kit based the acid base contradict pairs are shown below

In this problem, CS three plus and CLO two plus has CLCS three plus and CNO two plus had dragon triangular try angular plainer said Wrangler cleaner sit so according to the options here, option C and option the correct and for this problem, option C and option D R, correct answer for this problem.

Yeah In this video we're going to draw the Lewis structures for these uh five organic compounds. So let me start High up so there's room. So for c. three h. 8 we have three carbons And then 123 45 678 hydrants. It's a fully saturated compound made of entirely single bonds. Okay. Okay. For part B. We have a siege three group And then oxygen in the middle and another CH three. So this is either yeah. Okay. Each of the carbons has a completed Octa just from the bonding. But the oxygen is going to need to lone pairs there. Okay. Yeah part C. We have a siege three group and then we have a carbon connected to an oxygen and then to another siege through group. The double bond is to satisfy the octet for carbon so that it can form four box. And then oxygen is going to need to lone pairs. For part D. We have a carb oxalic acid. So that's another siege through group. Yeah. And then we have a second carbon double bonded to an oxygen and then and so bonded to an age. And each of the oxygen's needs to lone pairs. Mm. I'll say for part E. We have our CH3 group. Mm. Okay. Yeah. And we have carbon honestly an oxygen and a hydrogen, so it's an alga hide.

When choosing a correct conjugated as base pair. To prepare a buffer, we want to find the acid in the conjugate acid base pair that has a K. A value close to the desired hydrogen ion concentration or a P. K. A value close to the desired ph So if we know the hydroxide concentration we need to calculate the hydro knee um concentration by dividing the hydroxide concentration into KW And we get a desired hydro knee um concentration of one times 10 to the -8. We then look for a weak acid with a K. Value close to one times 10 to the negative eight. And H. O. C. L. Has a K. Value of 1.9. I'm sorry 2.9 times 10 to the negative eight. So it should work H. O. C. L. With its conjugate base O. C. L minus Next. If we know the hydro knee um concentration desired of four times 10 to the -4. Then we want to find a weak acid with a K. A value close to four times 10 to the negative four. And there are many choices all this too. So we could use acetyl salicylic acid with its conjugate base. The acid having a K. Value of 36 times 10 to the negative four. Or black silic acid with and its conjugate base with a K. Value of 35 times 10 to the negative four


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