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At coostaot tEmpcrature the pressure on :4.2 L sample of gas is increascd volume of the gas samplc? front atm to 5.9 atm What Is thc DcwOustO230L0.33 L...

Question

At coostaot tEmpcrature the pressure on :4.2 L sample of gas is increascd volume of the gas samplc? front atm to 5.9 atm What Is thc DcwOustO230L0.33 L

At coostaot tEmpcrature the pressure on :4.2 L sample of gas is increascd volume of the gas samplc? front atm to 5.9 atm What Is thc Dcw Oust O2 30L 0.33 L



Answers

At $46^{\circ} \mathrm{C}$ a sample of ammonia gas exerts a pressure of $5.3 \mathrm{atm}$. What is the pressure when the volume of the gas is reduced to one-fourth of the original value at the same temperature?

This is Problem 65 we will use Boyle's law in the wanted to calculate pressure in this problem. And the Boyle's law looks like this. It's p one times by we won equals p two times by the tooth. So letters, right? Everything we know from this problem so far me now our initial pressure, which is 4.62 atmospheres. We know our initial William, which is two points 33 liters. Then we know are firing the William, which is 1.0 three liters. And we also know phone. And we need to find our final pressure in the end. And we have to write it down in tours as well. So let us rearrange Boyle's law. So this equation right here for P two on If you rearranged this, you'll get Pete too, equals p. One times we be one divided by the tape. Add Just put the values in P one waas 4.62. At this fears times of by anyone, which is 2.33 liters on, divided by 1.3 features. And if you put these into your calculator, you'll get 10.45 atmosphere. But don't forget that we were asked to express our final pressure and tours on. In order to do it, we will have to do this 10.45 atmospheres. We need to time to buy seven 160 tour in one atmosphere and we will get 7943 tour, which is the same as 7.94 times by 10 to the power of free toward at this is your answer for problem 65.

Higher events in this question. They've given sample for one has a volume of 5.40 liter with an unknown of pressure. The gas is a volume of 9.73 liter when the pressure is 3.62 atmosphere with no change in the temperature or amount of gas for it was the initial pressure in the atmosphere of the gas. So but they've given 1st 1st weights, given data, you know, even five points 40 leader then people question mark. We too 9.73 leader. Then we too 3.62 atmosphere. Then according to Boyle's Law, the scalding two. Boyle's Law, we know that we know bye. Even if even is equal to two weeks and therefore The one is equal to Yeah, we do feed to upon revision And that is equal to 3.62 In 2 9.73 divided by 5.4. And that is equal to 6.5- three. Yeah. and therefore P one is equal to 6.5- three. It was mm. Yeah, that's right.

All right. So when you did this question, you have to understand this guy he want everyone is equals two p to be to you. So it is given you the 5.3 asked or regional pressure and last take a random number because it didn't say what is the volume of the original. So let's let's take one is easier. And you have to find out the pressure to when it drops to 1 10 So once you do the cross multiplication, you scat. 15. 30. So this problem is pretty easy once you know you have to apply this equation.

Okay, so we will be using that I don't. Gasol PV equals in our tea Pressure is what we're trying to find. We know the volume 12.8 leaders to find number animals were going to do grams that it gave us, which is 35.8 grams of 02 looking divided by its natural gas, which is 32 clams for more go to now for our which is the constant it is 0.8 to 1 leaders times a team over mold tons, Kelvin. So they gave us a temperature in 46 degrees Celsius. So Dio 46 plus 2 73 you're going to get 319 Kelvin, which is the unit that we need. So once we plug all this in, we're going to get pressure equals 2.29 eighteens. But we want it and kill it. Pascal's. So we're gonna need to Finberg 2.29 you teens into Kill Pascal's. The conversions that one a team is 101.3 to 5 k p I. So we multiply those and we get 232 killing Pascal's for our answer


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