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I-PolntalDETATSMER CilcinatnCHOatAYour TEACHERPkicncCINOMSFOen Anon, 1070,5 Meedts Me ttieg ned Ihe Ulo e duma & Utolne 07Fnattann [Tal AiuttCrnNeed Help?A-M1 PatnluDAAIaeDalcnictUy NomACiA Lchig3#IDTIQ ARotakiFFad Ft ) Faneaaeedetmee[e|tdUt Keehfel-ExA eneoteti Ahe [lheeTI |atn MeI-MFouliDETALSLACALciic0::F[AlQU MAcALTHCE AMOTHEpehsctocukth

I-Polntal DETATS MER Cilcinatn CHOat AYour TEACHER PkicncCINOMSF Oen Anon, 1070,5 Meedts Me ttieg ned Ihe Ulo e duma & Utolne 07 Fnattan n [Tal Aiutt Crn Need Help? A-M1 Patnlu DAAI aeDalcnict Uy Nom ACiA Lchig3 #IDTIQ ARotaki FFad Ft ) Faneaaeedetmee[e|td Ut Keehfel-ExA eneoteti Ahe [lheeTI |atn Me I-MFouli DETALS LACALciic0:: F[ AlQU MAcAL THCE AMOTHE pehsctocukth



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Ilcrc, whire precipirare $\{\mathbb{R})$ obraincd on rrcarment wirh aqucous solurion of $\mathrm{BaCl}_{2}$ is of (a) $\mathrm{AgC}$. (b) $\mathrm{CaCl}_{2}$ (c) $\mathrm{BaSO}_{4}$ (d) $\mathrm{PbC}^{\prime} \mathrm{I}_{2}$

Chinese solution when directed with stool and avoided give some right sector own additional access this compound. So could you inform general which hard place here's the correct terms.

Okay, So the first part of the question asked the graph for labor demand. To make this Brown puts first broad axes out, and we also label them so the horizontal axis should be labeled as number of workers, and the vertical axis should be labeled as wait three. This is because we're trying to figure out how many workers wonder can hire, becomes big, pull it before it becomes and no longer becomes profitable. So the problem says, is that the wage rate is 7 50 per hour. I wonder. Wants to make profit should hire all the workers who create a value marginal product that is equal to or greater than the wage rate. This is at that point, wonders making the maximum profit and can no longer make anymore by hiring any workers. You. In the last one, we found that all the value marginal profits, or BMPs for each worker and up into the seventh worker that the V M P is greater than or equal to the wage of 7 50 per hour. So, using the V MP for the seventh worker, we make a board between the six and the seventh worker about to do here, so the bar should look something like that. So now you want to draw that die to make this graph right in the middle of the more. Because remember, we calculate the V M P between workers as we go from the 6th 7th Worker. The value marginal profit created is 7 50 Finally, we had to draw a downward sloping line. The reason we droid downward sloping line is because I was wonder, hires more workers. She won't be able to pay as much. The second part of the problem is asking the ideal number of workers Wonder should hire. And this is where the graph or this is what the graph shows us. Because it's seven workers, the V M P is equal to the wage re, which means that one is making the maximum profit at seven workers and can no longer make anymore. So, ideally,

A student wants to dissolve the maximum amount of calcium fluoride to make one leader of a quick solution, so into which of the following solvents should she dissolve the salt. Well, fluoride is a weak base. Therefore we can consume the weak base. Getting rid of the fluoride, allowing the equilibrium to shift more towards the I. On side according to lay shot, Ailey's principal, if we decrease this than more of the solid will dissolve so we can react the fluoride with hcl to produce HF, decreasing the fluoride concentration and allowing more calcium fluoride to dissolve. So she should dilute it with .01 Moller Hcl, which is solution for the calcium fluoride, however, is going to be leased soluble in a solution that introduces fluoride due to the common ion effect. Increasing the fluoride concentration is going to decrease the amount of calcium fluoride that can dissolve and will increase the fluoride concentration by adding a a solution of HF that provides fluoride as a source

The main concept in this problem is soluble ity of calcium fluoride and the common ion effect. Um, that's what we're going to discuss in this video. Um, the Celje bility reaction of calcium fluoride is shown here a top, Um and so we'll take a look. What we know is that this the fluoride ion is a weak base. Okay, so we'll just take a look at, um, the different solutions, and I will find which one is the would dissolve the most and which one would dissolve the least. So this 1st 1 we have florid as a common I on. And so since it's a common eye on it, uh um, it will only slightly dissolve. Get okay. Now for this one, the sodium hydroxide, the psyllium is just a spectator ion, so we don't really care about it, But the hydroxide is a base. It's ah, strong base, in fact, And so the floor rides, actually, um, this will actually push the equilibrium backwards, and so we will produce more. Um Ah. Sorry. We will produce more florid ions. Okay, Now for the 0.1 Mueller hcl This one, Um when you add an acidic solution. The H plus the hydrogen ions removed the hydroxide ions from the solution. So the base equilibrium reaction moves toward the right side and by consuming fluoride ions and on this indicates that more will dissolve. And so the answer for which one dissolves the most is the HCL right here. It's this one, um, and this one right here as a common ion of calcium, and it has a hydroxide. And so this one actually dissolves the least the I'll just right up here most and least, okay?


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