CH:OHonly 2 only 3 only 4 only and 21 and 3 and2 and 2 and 3 and...

$$\left[\begin{array}{ll} 3 & 2 \\ 3 & 3 \end{array}\right]\left[\begin{array}{rr} 1 & -\frac{2}{3} \\ -1 & 1 \end{array}\right]$$

Hi everyone. So in this question they have given like that's uh, so option. Yeah, These correct We is correct. The structure CH three CH 20 CH two CH three shots. Okay, my time. There is some thanks.

Hello, everyone. This is Ricky and they're working on a problem 28 diagnostic. And so we need to identify all of the US and totes or this equation White was extroverts. And so we have a vertical ass in tow at X equals negative one. Because if we plug negative one into this equation, we, uh we get zero dominator, then also have horizontal. That's until at why equals one. And that's because if you take the limit of this problem of this equation from next to infinity oh, we get the answer one. So it's fitting was hopeful, Cnners.

Okay. In order to figure this out in the desert, a scientific calculator. We're going to start with the base, which is 13. And then to get an exponents, I'm gonna quit eight to the beef power. And that lets me pick any exponents. My exponent is five 13 to the fifth. Power is 371,293.

To solve this problem, I'm going to use pen desk. So first I'm gonna look for parentheses, then exponents, then multiplication and division in order from left to right and then addition and subtraction. So if I scan through, I do not see any parentheses to move back to the start. I'm gonna look for exponents. I don't see that. So now I'm gonna look for multiplication or division in order, whichever one comes first. So the first thing that I see is 1/2 times forfeits, so that's gonna be the operation that I perform first. Now, this is a great thing to do off to the side on scrap paper somewhere where you don't want it to clog up. You're nice work in a vertical format. So off to the side, I'm going to multiply 1/2 times forfeits. So one option is you could just multiply straight across. So one times for us for two times five is 10. But then you'd have to reduce that fraction by dividing top and bottom by two. And you get 2/5. Or what you could have done at the start is you could notice that two and four, both have a common factor of to suit. Could cross. Cancel two divided by two is one four divided by two is too. And now, if I multiply across one times two is 21 times five is five. So you could do it Either way, you just have to make sure that when you're done, you remember to reduce your fraction. So 1/2 times 4/5 became too fits minus. Now, at the same time, I can also multiply 2/5 by three. Tense because I know that this multiplication is gonna happen before that subtraction. If you want to do it more than one step, you could also do that. So again, I'm gonna do this after the side 2/5 times, 3/10. So again I could multiply straight across, which would be two times three is six and five times 10 is 50. But then I would again have to remember to divide top and bottom to reduce the fraction by two, which would give me 3 25th Or, if I go back to the original fraction multiplying. I can recognize that two in 10 have a common factor of two. And so what? That means is I could divide them both. So two divided by two is one 10 Divided by two is five. Now it could multiply across one times three is 35 times five is 25. Either way is fine as long as you remember to reduce your fraction. And so this is going to become two fists. Times 3/10 is going to be three 25th. Now I need to subtract 2/5 and 3 25th But in order to do that, I'm going to need a common denominator. So I'm going to change 2/5 to have a nominator of 25. And to do that, I'm in a multiply five by five. But the golden rule of fractions, whatever you do, the bottom you have through the top. So if I multiply five by five, I also need to multiply two by fat. And so that means 2/5 is going to become 10 25th minus 3 25th Know what I'm subtracting fractions. My denominator stays the same and I subtract the numerator 10 minus three is seven for final answer of 7 25