5

Calcium in flour was analyzed by the following procedure. First; 0.1490 g of flour were dissolved by microwave digestion in 8 mL concentrated nitric acid + 2 mL 30%...

Question

Calcium in flour was analyzed by the following procedure. First; 0.1490 g of flour were dissolved by microwave digestion in 8 mL concentrated nitric acid + 2 mL 30% hydrogen peroxide The resulting solution was transferred to a 100.0 mL volumetric flask and diluted to the line with deionized water. From this, 20.00 mL were pipetted into each of four separate 50-mL volumetric flasks To these were added 0, 5.00, 10.00 and 15.00 mL of 8.17 mg/L calcium standard solution before diluting to the line w

Calcium in flour was analyzed by the following procedure. First; 0.1490 g of flour were dissolved by microwave digestion in 8 mL concentrated nitric acid + 2 mL 30% hydrogen peroxide The resulting solution was transferred to a 100.0 mL volumetric flask and diluted to the line with deionized water. From this, 20.00 mL were pipetted into each of four separate 50-mL volumetric flasks To these were added 0, 5.00, 10.00 and 15.00 mL of 8.17 mg/L calcium standard solution before diluting to the line with deionized water and mixing well. Atomic absorption of calcium was measured for all four of the resulting solutions, giving the data shown below: A blank measurement gave an absorption of zero_ Description of solution Atomic absorption Unspiked solution (50.00 mL) 0.125 Spiked with 5.00 mL 8.17 mgL Ca 0.246 Spiked with 10.00 mL 8.17 mgJL Ca 0.368 Spiked with 15.00 mL 8.17 mg/L Ca 0.490 What was the calcium content of the flour in mg/g (parts per thousand)? (Hint: remember to take dilution into account Use only the unspiked solution and the 5.00 mL spiked solution from the previous question with the single-spike method of standard additions to calculate the concentration of the unknown_



Answers

Both calcium chloride and sodium chloride are used to melt ice and snow on roads in the winter. A certain company was marketing a mixture of these two compounds for this purpose. A chemist, wanting to analyze the mixture, dissolved $2.463 \mathrm{~g}$ of it in water and precipitated calcium oxalate by adding sodium oxalate, $\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$ The calcium oxalate was carefully filtered from the solution, dissolved in sulfuric acid, and titrated with 0.1000 $M \mathrm{KMnO}_{4}$ solution. The reaction that occurred was $6 \mathrm{H}^{+}+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+2 \mathrm{MnO}_{4}^{-} \longrightarrow$ $$ 10 \mathrm{CO}_{2}+2 \mathrm{Mn}^{2+}+8 \mathrm{H}_{2} \mathrm{O} $$ The titration required $21.62 \mathrm{~mL}$ of the $\mathrm{KMnO}_{4}$ solution. (a) How many moles of $\mathrm{C}_{2} \mathrm{O}_{4}^{2-}$ were present in the calcium oxalate precipitate? (b) How many grams of calcium chloride were in the original $2.463 \mathrm{~g}$ sample? (c) What was the percentage by mass of calcium chloride in the sample?

In this problem, we're going to calculate the concentration of calcium in a blood sample and units of milligrams of calcium per mil, A leader of blood. We are told that we have a 10 millimeter sample of blood, so we need to calculate the mass of calcium in units of milligrams and then divided by that volume of blood which is already in millet leaders. We use the equation from the previous problem and from that problem, once we balance it, this is the overall reaction that is taking police. We are told that we're told the volume and the polarity of a came in a for a solution that is required for Ty Trish in of the ox elite Ion. And we know that since the compound C a C 204 has see a with a charge of two plus cancelling out with CTO for the charges three minus that, if we calculate the number of moles of C two for minus that were used in this tie Trish in and that would relate to you and be equal to the number of moles of calcium which we can then convert through its more mass into milligrams of calcium. So that is how we're going to approach this problem. And we know that polarity is equal to moles per leader. And so that means that the moles of K m n O. For that we have is equal to its malaria t times, its volume and leaders and were given both of those. So we can start by calculating in the number of moles of K m N 04 that were required for the Thai tradition and somewhere to see a sea. 204 came in. 04 has equal and opposite charges cancelling out. So the number of moles of Canada four is equal to the number of moles of M N 04 minus ions and that is equal to nine point 56 times 10 to the negative Fourth Moeller times when we convert the volume into leader 0.0 242 leaders and when we want to play, there's together that comes out to about 2.31 times 10. Do you the power of negative five moles of M N 04 minus Now, based on the overall balanced reaction, we can relate this to the number of moles of the Oxlade ion CTO for Tu minus, using the ratio of two moles of M. N 04 minus. Reacting with five moles of C 24 Tu minus Again, we said that one more of C 204 to minus responds to one mole of calcium, since it has a charge of two plus, and they're in a 1 to 1 ratio in that formula for that compound. And now we can convert this into a mass of see a two plus. So one more of calcium is equal to 40 0.8 grams of calcium from the periodic table. Then we convert grams two milligrams. We know that one gram is equal to 1000 milligrams. So now when we want to play all those ratios together, we get the mass of calcium in milligrams, and that comes out to you about 2.32 milligrams of calcium. And remember that we were told this is in a 10.0 Miller liter sample of blood. And so these are the units that we want. So when we take 2.32 divided by 10 that comes out to zero point 232 milligrams of calcium. Her Miller liter of blood

The purpose of this problem is we want to find the calcium content in a calcium tablet. Uh, we dissolve it in Houston illustration, um, to find the content of calcium. Um, So, um, here is the the information we have. Yeah, soon see a C 03 tablet. Uh, it's one point 24 by zero. Graham, we don't really need that number because we just want to find a the milligram of calcium two plus in the public it and we don't need the percent. How do we find it out? So as we're doing penetration, so we dissolve calcium company with hydrochloric acid. So here's the equation. The balanced chemical equation and carbon dioxide. So the hydrochloric acid we used is 50 millimeter and more. Clarity is point through 5000 0.500 Mona Ah, but we don't use all of them. So there is some left over. So the access of hydrochloric assets, we're gonna used sodium hydroxide too. Uh, patriot. And then the reaction neutralization reaction is this equation. And then we know we use 40.20 new leader, and the concentration is zero point 2184 mullah. And so, since we know, uh, the volume and more clarity, uh, show them high drug sign. And we should also know, um, the amount of hydrogen core, right? So hydrochloric acid. So, uh, since it's 1 to 1 ratio, So what we have for sodium hydroxide, So it's is also the amount for hydrochloric acids. So this is the access among the project coral acid. It will subtract from the total amount. We will know how much hydrochloric acid is actually use. So this is a total This the access we subtract will be able to know the amount of a hydrate coral asset that is used to neutralize calcium carbonate. So here is our set up. We can we can do the dimensional analysis. The milligram of calcium ion is echo two. So we find out the most, uh, hydrochloric see the total amount. So we need to convert the milligram, too, to convert the new leader to leader divided by 1000. So it's 0.0 fine. 00 leader comes 0.5000 mole police officer and subject. Ah, the amount of bird. Uh, so the hydroxide, which is also the amount of hydrogen Hydrogen correct acid. Oh, so it's 0.0 40 to 0. Leader palms 0.2184 Small for leader. Okay, put it in the princesses. That way, we'll get leader. Council's leader will have moles. That is the mold of, uh, hydrochloric acid. Okay, uh, and then that's hydrochloric acid. And then we're gonna convert it to calcium company. So and then one mole, two more hydrochloric acid versus one more calcium company, and we want to solve for calcium ion. So we know in one more calcium company, there is one more calcium ion, and then we're going to calculate the mass of calcium. Ion is one more is calcium. Ion is 40.8 g. Okay? And then, uh, we're going to convert Ram, too milligram. So that way we have a long set up, and then we'll do the calculation. Ah, look at, um, 300 25.1 milligram. That's the answer. Yeah,

So let me start by writing the equation for the removal of calcium to positive by using off the late iron on duh C A C two go full. Catch him too. Positive. US C two or four, too negative. The amount of cash into positive in a blood can be calculated as followed. So we know that 100 ml serum contains about nine point for you. Milligram of culture. Too positive. So when Emma will contain 9.5 divided by 100 catch him. Don't bother. Do therefore the mass off calcium in 5.5 Emily off serum can be calculated US zero point 52 9.5 Do I did my 100 5.5 milligram. So 5.5? Yeah, we know the molar mass for cash in positive is 40 gram per mole. So from this, we can calculate the number off moles off culture. So number off moles, which is m equal toe muss divided by Mama's mass calculated was 0.52 Then this double negative three. Using that 0.52 gentry. Stupid negative three. Graham divided by mama's 40 grounds. Number off mold of calcium will be 1.3 10 days to one negative five morals In order to prevent coagulation 99% off the cash into positive is removed the 1% of cash into positive mine in the equilibrium with oxygen. So how 99 so 99% off number off mold of calcium are 1.3 okay to 99% of 1.3 multiply 10 days to plan negative five moles Give this 1.29 Henry's to one negative five more since one mole of culture into positive will be needed. One more off obsolete for removal hands the mole off Obsolete for 99% of calcium removal are 1.29 10 days to plan negative five moles. So more off culture off Jochem equal toe total catching positive minus ITI. Moved Will be equal to 1.3 10 days to one negative five minus one point to 9 10 days. To prove a negative, waves will be equal to zero point 01 10 days to plan negative five, which is also equal to 10 days to one negative seven moods. We know the expression formal aridity is acquittal. Number off moles divided by pyre. Leader off solution. So substituting 10 days, Tobar. Negative seven for a number of moves. And for volume we have 0.1 Similarity equals 10 days to plan. Negative seven divided by zero point 010 later will be equal to 10 days to but negative for you. We already know the expression for Saul ability. KSB So he s B is acquittal. Concentration of calcium to positive with C two for two negative I in concentration. Substituting in the values we have C two or for two negative equals 1.96 month supply 10 days to our negative eight four K s people do. And for can Shinto positive ID concentration. It will be 10 days to plan. Negative five sold. Wing it. We have 1.96 10 days to our negative. Hey, sorry. Sorry. Kindest of a negative three for the mold off. See toe photo negative and equally brim with calcium to positive in a solution. So moles Oh C two awful to negative will be equal to 1.96 10 days to one negative three. Multiply it every super negative too. Really, Quinto 1.96 10 Based upon negative five moons, the total auxiliary it I am used can be calculated as so. Total morning will be equal off the lead for 99% off calcium to positive, less orders late for one person cash into positive, which gives us 1.9 multiple identities by negative five plus 1.96 Then they stop our negative five equal 3.25 I want to play it in just one negative five. Moz, moving on. Okay to C 24 Okay. To see two or 41 mole off the sold gives one mole off obsolete. So we have three point 25 10 days to point negative. Five so and number off more will be Quinto Maas. This is for Kato. C 24 Do I did buy more Dumas, so we need to determine the months. So massively beacon too. 3.25 10 days to one negative for you while deployed with Willow moss off 166. Give this 5.39 milligrams

Multiply. Cross the bar by the water and it gives you 0.3 2396 And I like to keep sick figs until the end. Like I like to do 16 weeks at the end and then run the numbers a second. Keep it in your calculator possible. But this is for sick. Pigs should be four sick fixed and this is 46 Thinks there should be 466 So if you want to keep your sick sticks again But in your calculator wait until you know, keep it on. Run that until the end. So now we're gonna find how much a CEO reacted with Carson Carbon e and we find out by subtracting those two, right? So then that's gonna be point, which is what you have. So really, you have because that's gonna be your biggest number. Mine is how much did not react with the constant carbonate and that will give you how much actually react that with the 1000 carbonated, which is 0.2 372 moles of HCL. And now we convert this to causing company to causing wine. So first week number 2000 carbon and then to the house of mine. So we're gonna do so. I have 0.2372 moles o hydro court Cassa Someone's oh hcl two malls 0 1000 carbon e moles 0 1000 carbon e two moles of Cassie, Mayan most Oh Qassam Iron Two grams of calcium iron on the grams of calcium iron, two milligrams of calcium mine. So we know most of hydrochloric acid to most of cause and carbonate. Based on this equation up here it's a wanted to more racial, most of causing Mayan to most because it carbonate you look at the cause in carbonate There's only one calcium iron, says the Oneto. One more Asia, most of Gramm's Acosta Mayan that isn't lower mass of calcium. So this is one and this is 40.8 and then in one gram of anything there's 1000 milligrams of that anything and then then we can sell units. Moles of HCL cancel almost 1000 carbonate. Cancel most of calcium ion console Caroms Acosta Mine Cancel leaving you milligrams of calcium iron well to black cross. If I buy the bottom and you get your answer which is 400 and 75.3 milligrams. Oh Qasem Bayan


Similar Solved Questions

5 answers
An isolated charged capacitor has energy U stored in it: If a dielectric of constant K is inserted into the empty space of this capacitor; the energy of the in the capacitor changes to2KUOukU/(2k)KU
An isolated charged capacitor has energy U stored in it: If a dielectric of constant K is inserted into the empty space of this capacitor; the energy of the in the capacitor changes to 2KU Ouk U/(2k) KU...
5 answers
Section 5.4b: Problem 3 Previous Problem Problem List Next Problempoint)Let s(t) denote the posi ition of a particle at time t, and let and a be the velocity and acceleration respectively: The particle is moving according t0 (he dala a(t) 10 sin(t) + 3cos(t) , s(0) = 6, s(2r) = -8. Find a function describing the position of the particle;s(t)Preview My AnswersSubmit AnswersYou have attempled this problem 0 times You have 10 attempts remaining:
Section 5.4b: Problem 3 Previous Problem Problem List Next Problem point) Let s(t) denote the posi ition of a particle at time t, and let and a be the velocity and acceleration respectively: The particle is moving according t0 (he dala a(t) 10 sin(t) + 3cos(t) , s(0) = 6, s(2r) = -8. Find a function...
5 answers
0 hydrugcn utom has J single proton %f Its rnter J sinzle elcctmoa 4i dsance 0i ap[ximatels UQ-' nt um i Molin Whal is Ihc elecbri: nrrnti:l encry in joules" (b} Whzl is Iha significaxe 'thc sign of the answer?
0 hydrugcn utom has J single proton %f Its rnter J sinzle elcctmoa 4i dsance 0i ap[ximatels UQ-' nt um i Molin Whal is Ihc elecbri: nrrnti:l encry in joules" (b} Whzl is Iha significaxe 'thc sign of the answer?...
5 answers
Consider the function f(r) = 223 32 on the closed interval | = 1, 4].Find the exact value of the slope of the secant line connecting ( ~ 1,f( ~ 1)) and (4, f(4)).By the Mean Value Theorem there exists € in ( = 1, 4) so that m = f' (c). Find all values of such € in 1,4) . Enter exact values_ If there is more than one solution_ separate them by a comma
Consider the function f(r) = 223 32 on the closed interval | = 1, 4]. Find the exact value of the slope of the secant line connecting ( ~ 1,f( ~ 1)) and (4, f(4)). By the Mean Value Theorem there exists € in ( = 1, 4) so that m = f' (c). Find all values of such € in 1,4) . Enter exa...
5 answers
9-x2 2 0 x2_2x+1 x2_8 <0 x2 ~4 2 2 2x-3 2-X 6 9_ <2x - 1 4-X x2_2 10. 2 0 2x+7 x+6 11. <=4 2 X 12. x <- x+2
9-x2 2 0 x2_2x+1 x2_8 <0 x2 ~4 2 2 2x-3 2-X 6 9_ <2x - 1 4-X x2_2 10. 2 0 2x+7 x+6 11. <=4 2 X 12. x <- x+2...
5 answers
Question 20What is the IUPAC name of the following compound?3-chloro 1-methyl 3-phenyl propane aldehyde B 3-chloro 1-methyl 3-phenyl propanal 4-chloro 2-methyl 5-phenyl pentanal 4-chloro 2-methyl butan benzenal 4-chloro 2-methyl 4-phenyl butanalCick Submit to complete ths assessment
Question 20 What is the IUPAC name of the following compound? 3-chloro 1-methyl 3-phenyl propane aldehyde B 3-chloro 1-methyl 3-phenyl propanal 4-chloro 2-methyl 5-phenyl pentanal 4-chloro 2-methyl butan benzenal 4-chloro 2-methyl 4-phenyl butanal Cick Submit to complete ths assessment...
5 answers
(2) Prove that every HOn-zero ideal of Z[V2] contains a non-zero integer: (Please note that You have to prove that the element YOu construct is nOn-zero.) points
(2) Prove that every HOn-zero ideal of Z[V2] contains a non-zero integer: (Please note that You have to prove that the element YOu construct is nOn-zero.) points...
5 answers
Consiaer tne angle snown below WIth An1 Intial Ty pointing in the 3-o'clock direction that measures € radians (where 20) . The terminal point is (1.78_ 1,45) .78,-145)What is the angle's measure (in radians)?Previcw
consiaer tne angle snown below WIth An1 Intial Ty pointing in the 3-o'clock direction that measures € radians (where 20) . The terminal point is (1.78_ 1,45) . 78,-145) What is the angle's measure (in radians)? Previcw...
5 answers
3 Cto Eoes the E Select | sclect | 1 Select | ] detector object Ue detector obiect MH standingstithe 1 suwnioj Htalicoti Re 1 iL 2 USE Use Ecl | speeding Up, THE TAB dchnitions 1 1 1 KEY 1 1 1 for vclocity and acccleration L complete [ Select | [ The object > {xoq the table . 3 cceleration naaWinaunVelocity
3 Cto Eoes the E Select | sclect | 1 Select | ] detector object Ue detector obiect MH standingstithe 1 suwnioj Htalicoti Re 1 iL 2 USE Use Ecl | speeding Up, THE TAB dchnitions 1 1 1 KEY 1 1 1 for vclocity and acccleration L complete [ Select | [ The object > {xoq the table . 3 cceleration naaWin...
5 answers
QUESTION 10How many Allylic halogens including stereoisomers can be made using 1-Butene and NBS?
QUESTION 10 How many Allylic halogens including stereoisomers can be made using 1-Butene and NBS?...
5 answers
The Ien Jpplicd wnen 1 fcmale itests MOmlooucroncdIOrtthc ouAnmnet
The Ien Jpplicd wnen 1 fcmale itests MOm looucr oncd IOrt thc ou Anmnet...
3 answers
D fle) = f(0) + 9'F'(0) - +8 ;"(0)+ @ f"(0) 21 316.9 Using Maclaurin's Series, the expansion of e3z up to the first 4 terms is:Select one: A. flz) = e3r =1_ 32 + !22 323+B. flz) = e&r = 1 + 32 + {2? + 9x*+c. f(z) = eSr = 1 _ 32 + g22 = 9x3 +.D; flz) = e3r =1 + 30 + gz2 + 2 83+ Ptetn
D fle) = f(0) + 9'F'(0) - +8 ;"(0)+ @ f"(0) 21 31 6.9 Using Maclaurin's Series, the expansion of e3z up to the first 4 terms is: Select one: A. flz) = e3r =1_ 32 + !22 323+ B. flz) = e&r = 1 + 32 + {2? + 9x*+ c. f(z) = eSr = 1 _ 32 + g22 = 9x3 +. D; flz) = e3r =1 + 30 + ...
5 answers
Fracliccthingie that holds a cutting " (the center bit) is rotating at 20.000 #1 tool*s arbor angular velocity in radians per second? rpm_ What is the
Fraclicc thingie that holds a cutting " (the center bit) is rotating at 20.000 #1 tool*s arbor angular velocity in radians per second? rpm_ What is the...

-- 0.020570--