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Which of the following product(s) form in this reaction?Hz, Pd-CDraw the structure of products formed in the following reactions.Hz, Lindlar's catalystNa, NH3...

Question

Which of the following product(s) form in this reaction?Hz, Pd-CDraw the structure of products formed in the following reactions.Hz, Lindlar's catalystNa, NH3

Which of the following product(s) form in this reaction? Hz, Pd-C Draw the structure of products formed in the following reactions. Hz, Lindlar's catalyst Na, NH3



Answers

Give the products that would be obtained from the reaction of the following compounds with sodium amide in liquid ammonia:

So this question we're talking about predicting major products from your action off HBR with different Al Keane's. So soon with eight, we're gonna start with this structure, right? So is god something that looks like this. I'm reading HBO to this. Um, the product is actually gonna be a little different than what would seem obvious you're actually going, Teoh produce. This is a product. And the reason for that is because as an intermediate obs draw this over here and read, I'm gonna form this car broke, and I now this has a spare hydrogen off here which can then to draw in blue kind of shift over causing, uh, the car behind on to move the tertiary carbon in a one to hydride shift, making our my major products be on that tertiary carbon. Right? So moving on to ah, to be eso this time we have a slightly different, uh, thing Looks like this HBR this time were a little too far away to do any of those fancy 1 200 shifts. Oh, or even a metal shift. So in this case, you'd expect just a normal reaction. All right, part C, we're going to start with, get this product and there's no need to do any sort of shifting for this one. I simply due to the fact that they're already conform a church here. Carver Cod, eso weaken. Just I expect this to be in a stable product. Uh, D is gonna be a very similar structure where we have the double bond one single way and again you conform a tertiary cardboard cut on here. So there's no need to do any sort of shifting or changing its stability. Uh, so you're actually going to form the same product? Uh, which is kind of exciting, So to move onto Parky eso. Now we've got something that, um he's gonna have another four carbons this time to muffles and then a guy right there. So we're actually going to form a metal shift on this one with addition of HPR eso. What that means is when I add HBR, my final product is actually going to look like come this. And the reason for that is I have Ah, this is an intermedia. And what can happen is since there's no available hydrants to move to a tertiary car back on this whole methyl group can actually shift over, causing the car behind on to be on a metal, but also armature sharing site, but also moving the methyl group completely, which causes are major product to be for him to the way it is. All right, then. Lastly, moving on to f We have something that looks like this. Ah, And again, there's not really a good way to shift this or change this, so we can just expected to add kind of on the edge like that.

Which one of the foreign compounds will give such a product And you do reaction. So we are going to discuss which of that reactant will give some. Then in the molecule during is added, then it will give a man a product. Because feeling is that who are living group that's even sending mechanism here takes place. But in the first option, in the first option we have running good looking group. When we take a strong base like C2 as five woman's then what can we get the ar minus With gas, eliminate and then we will get this type of this is called us building to building. Is that sen Jeff? Okay. In that seat because that city, Al Qaeda, I mean that will give Elimination of one reaction. OCOCS three will not give Elkins. So correct option will be the Bc. We are the introduction. Okay, thank you.

The question is which of the following reactions will give normal profile bending as the major product smoke in the fast reaction. This the available gets eliminate positives. I will come here but this is inevitable. So it will rearrange and comes to this carbon. So this carbon will attack on the engineering and we will get this hey, in the second reaction there will be second degree car broke down so we will get the same product. In the 3rd reaction Double one will break all the time will come here and attack on this side. But in the form of the Ariza psychlo cycling green and in this reaction car book and will not rearrange. So this by one will this bible will break and this will attack on the engine And by one will attack. So here we will get normal profile. Mm hmm. Benji.

We're taking a look at the major and minor products that we may fall. So in the first part we see that our kids can undergo electrical like edition reactions with H B R on what we form is the following. So we have to products here, and these are and equal populations in our reaction mixture. When products are forming in the second part that we have here, Ah, major product is as follows. So by Major, I mean that this product will be greater in concentration than any other structures that may be present. So in Thesafeside example, what we generate is another major product that is Burma. Nated, that is three Bruno to three. Damn Ethel Hexen. In the final example, what we form is one Bruno Bonney thaw cycle repenting.


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