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Let Iwo cards be dealt successively; without = replacement (rom standard 52-card deck Find the probability of the The Iirst card event a jack and the second queen: ...

Question

Let Iwo cards be dealt successively; without = replacement (rom standard 52-card deck Find the probability of the The Iirst card event a jack and the second queen: The probability that Ihe first card jack and the second queen (Simplify your answer: Type an integer or fraction )

Let Iwo cards be dealt successively; without = replacement (rom standard 52-card deck Find the probability of the The Iirst card event a jack and the second queen: The probability that Ihe first card jack and the second queen (Simplify your answer: Type an integer or fraction )



Answers

Determine the probability. Write each probability in simplest form. What is the probability of selecting a Queen or a Jack in a standard deck of cards?

In question. 16. They want a queen or Jack. Remember, we have four suits. That was bad. Let's try that again. Hearts, diamonds, clubs and spades. Well, each one of them is gonna have a queen. So that means we have four queens. They're each gonna have a jack. So we actually have four jacks as well. And then there are 52 cards in this deck. And so if we have four queens and four jacks, we have eight possible cards out of the total of 52 dividing by four. To simplify, we get two out of 13 as the probability that we will choose either a queen or a jack from that deck of cards.

So now we're gonna look at the probability of drawing to face cards when we draw two cars from a deck and without replacement. So here face cards means Jack, Queen and King. And there are 12 face cards in a deck and a standard deck of cars comprises 52 cards. Cantonal, um, I'm so now the probability of trying to face cards equals the number of favorable outcomes mhm divided by the number off the total number of outcomes. So, um, in our problem, the number of favorable outcomes is, um, 12. Choose to because, um, there is no order and no replacement, and the total number of outcomes is 52. Choose to on. If you use a calculator for this, you'll get the result, which is 0.498 Um, and there's equals 4.98 percent

All right now, I have to find the probability of drawing a queen from standard deck of cards, given that one card that is a queen has already been drawn and not been replaced. Which means Now in the deck there are only three Queens left, and there are only 51 cards left. So this is going to be my probability that I will draw a queen, given that I already have a queen, right? So this is my answer in this case.

Question 15. What is the probability of selecting an ace or a king and extender deck of cards? Well, there are four aces was four kings? Ah, that standard deck of the teaching cards. So that means I have eight cards that I can choose out of 52 simplifying. We can divide those both by four. So we have a two out of 13 chance getting an ace or a team in a standard dead guards.


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