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TheESeh biltons dolla-s ) ciku Ku mcnlihesl honumnnol ncorc Kaln'puriiuliMIiny @Fania0R4 n = ar0 tandoniky selbdadrenla cuitionikomAile beni4nn dilletnnt noyhl Hamnp ? ion Ihatara Hmplcs Ard odin {7a4e been comb nd ot Oh sempb nobtilty PrentbiuyDaennisamolnq Uisiribulasarinio Mcan In Um Libb_ vakies 0l i(Type vileguts &r Iracbons , cnpal Fe Dopuluhon (o Iw [80n % I moan 0tha tcoulabo " {Aaund olan nlucen Lo Um Hnljci It vnlue CtHiunnnumarTOTIMItFuuTt Mmpn

TheESeh biltons dolla-s ) ciku Ku mcnlihesl honumnnol ncorc Kaln' puriiuli MIiny @ Fania0R 4 n = ar0 tandoniky selbdad renla cuitionikom Aile beni4nn dilletnnt noyhl Hamnp ? ion Ihatara Hmplcs Ard odin {7a4e been comb nd ot Oh sempb nobtilty Prentbiuy Daenni samolnq Uisiribula sarinio Mcan In Um Libb_ vakies 0l i (Type vileguts &r Iracbons , cnpal Fe Dopuluhon (o Iw [80n % I moan 0tha tcoulabo " {Aaund olan nlucen Lo Um Hnljci It vnlue CtHiu nnnumar TOTIMIt FuuTt Mmpn



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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

Okay, so here were given Ah, loss. Transform of t cute Minus t Uh, times e to the power of T plus e to the power of fourty times co Sign of tea says the first thing you can do is just break this up in the three little chunk. So we will evaluate the low cost transform of t cubed. So track that from the transformer tee times e to the power of T now that to the transform for E to the four tee Times Co sign t then to evaluate all of these. We just want to use that table 7.1. Um, that tell us what the u a pause transforms are. So the transform 42 the power end is going to be an factorial. In this case, it's three over s plus and plus one. So again, this case and his three So it's gonna give us two out of four. Okay, then from Atlas attract in this case for the he's out of tee times like t to the power of and we get n factorial of this case is gonna be one over Ah s minus. Whatever each of the team's multiplied by in this case, it's going to be once we get s minus one for the power of and plus once and is what tea is raised to in this case is one us That's just gonna be U to the power of two. And then finally, we'll add that to this last function, which is going to be s minus a being. What he's multiplied by in this e functions has been before over again. That's minus a squares the s minus for it's where 1st 1 um and one being sort of what is multiplied with what to use multiplied by in the coastline function. Um, so if you're looking at table 7.1, that will make sense. And when we violate this will three factorial is going to be a six, and then one factorial is just one. It's worth noting that this is gonna be for s straighter than four. Okay, and then that is our solution

In this video, we're gonna go through the answer to question number 19 from chapter 9.3 to rush to find the inverse matrix off F S R E O X, which is a matrix as a function of time given here. First, let's recall that inverse off a product major sees a B is equal to the inverse off B plans by the invested a sharing all of the investors exists. So let's think about how we can write this in a slightly different way. So we kind of want toe, not have to worry about all the u to the t You need to mine it easy to tease. So let's just write the coefficients first 14 and then you see that all the first row almost quite by eating Timmy on the second row E to the minus t you know, 30 points to t so we can turns up by e to the t zeroes ever in the second row zero e to the minus t zero and 3rd 1 00 each of the two teams. Okay, let's call this one a on. Let's call, this one will be, Then we can use this formula to find the total invest. Okay, so first up, let's find inverse off, eh? Let's do it in the usual reduction way. So what we got 111 one minus one. See? You want one? Combine that with the identity. 100010 There. Is there a woman? Okay, we're reducing. Let's subtract the first row from the bottom room. That gives us 00 three minus 101 less. Attract the first road from the second road zero minus 21 Uh, then screw reminds 110 leave in the first row is it is one warning zeros era. Okay, so try it times in the bottom row by 1/3. We got 001 minus 1/3 zero 1/3. Get me. Okay, then this new bomb row, we can subtract that from the 1st 2nd most. So from the first room gonna be 10 because I want one. That one minus one is zero. It's gonna be one minus a bird. Sorry. One minus minus. A bird, which is one plus a bird, which is 4/3 zero minus 00 zero minus 1/3 as much bird. Then subtract the new bottom row from the middle road is your, uh, minus two zero minus one minus minus 30 miles. Off course, a bird which is minus two birds one minus zero is just 10 minus. The third is my herd. Okay, so bottom row stays the same. 001 Mines third, zero third. Let's multiply the middle Robot minds heart to get 010 Ah, my hard times minus 2/3 is 1/3 then one times minus half is mine minus half minus. 1/3 is 16 Then let's do the top road minus this new middle road. Then we're gonna get the matrix on at the identity matrix on the left for the 4/3 minus. Good. This one zero minus 1/2. It's okay. Zero minus minus 1/2. It's 1/2 on minus. 1/3 minus suit is minus 36 Which is my heart. Okay, so this is our inverse off the function called a Now it's fine. In burst off. I actually called bay. So be waas. Eat the tea. 00 zero. It's the minus t zero. Is there? Uh, zero. He said to take the inverse of this. This is really easy. Um, because when you got a non zero elements in the leading diagonal on and it's just the reciprocal off those beating darknet values on the rest is all zero. So eat the minus t 000 e to the T they were zero zero. Eat some honesty. Sorry. He's the mind to t expended in verse off X, which is inverse off. Maybe. Which is? They invest a inverse, which is, if the modesty 00 zero e to the T 000 into my studio tea. That's our invested. Be invested a waas one, huh? Minus off that, But it's hot. Six minds of the zero Third. Then when we we'll find them together, it's question, but we got E to the minus. See, huh? Modesty minus ah, the money's team. Bird eats the tea. Mine's 1/2. It's the mind. Yeah, it's the team. Six. It's the team, but Murray get minus. 1/3 eats the minus Tootie zero on the third eats the mind stated, and that's I invest

Really asking us to do is to calculate the universe transform of the rational function escape plus full of the s squared plus X minus six s lead plus X Now the first step to performing the transformers to obtain the partial fraction to composition which will start by breaking the denominator in too linear terms. Since all the linear terms of distinct we can actually write this as some number over s minus two plus some number of s plus three plus some number over S plus five plus some number over s. To obtain each of these numbers, we plug in the value which would cause this to be equal to zero, um into this equation, ignoring the problematic terms where you will get an infinity in the denominator. For instance, to get this constant, we plug in X equal to two into this equation, ignoring this term here. If we do that, we'll get the particle a fraction decomposition forever. This Dean native 13 over 30 negative. Two of the three and five of the six. If we now take the inverse transform of this, then we'll get for over 15 times e to the two t minus 13 over 30 times E to the negative three T minus two over three times E to the negative five t plus five of the six times a constant.

In this video, we're gonna go through the answers question of a 17 from chapter 9.3. So we're given a Matrix. X is a function of team getting by eat 30 even 40 e to the t 48 40 so as to find the inverse off this matrix 40. So let's do that here it's two by two matrix. So let's just first figure out whether we could do it using the Formula one of the a D minus BC, so ah, don't be won over a d, which is for e to the 40 times e to the t to eat the five teen minus E to the 40 times e to the t, which is e to the five. See that looks OK. That can never be zero. Uh, then this is gonna be the bomb, right? For is the 40 that's going minus E to 40 minus e to the t on dhe. Eat that C. Okay, so one over four eat the fight humanity to fighting. This one over three eats the five team so that most play not in. It's gonna be four over 3 40 times. One of these invitees as e to the T. Then we're gonna have minus one of three. It's the team minus one over three. Then it's east. The tea provided by five t. That's easy. That one of the key to the 40 on DDE done. It's gonna be one of the three eats the 40 which stuff?


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