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200Moving Mass 25 gElapsed Time 0.0 s#Washers: 10Click on masking tape to change radius Click on washers to change #washers Each washer has a mass of 10 gramsStart...

Question

200Moving Mass 25 gElapsed Time 0.0 s#Washers: 10Click on masking tape to change radius Click on washers to change #washers Each washer has a mass of 10 gramsStart

200 Moving Mass 25 g Elapsed Time 0.0 s #Washers: 10 Click on masking tape to change radius Click on washers to change #washers Each washer has a mass of 10 grams Start



Answers

The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1200 rpm around a vertical axis. What is the apparent weight of a $1.0 \mathrm{g}$ drop of water?

This exercise. We're going to talk about the uniforms. Circular motion. So let's remember that when we say that a body is under the uniforms Circular motion. We're basically saying that there is a that this body has a radio resident force that is equal to M V squared, divided by R on which EMS, the massive body V is It's tangential velocity squared. Sorry, B squared. It's tangential, velocity squared and our is the radios off the orbit. In this exercise, we're going to analyze the circular motion off a water drop that has a mess off 1 g that is rotating around the center of a clothes washer. We know that the clothes washer is going to make, uh, 1000 and 200 turn rotations per minute. Yes, and and that it has a diameter. So let me put here in red. The diameter off the clothes washer is 45 centimeters, 0.45 eaters. Those are zero point 2 to 5 m. Okay. And the exercise wanted to find what is going to be the apparent weight off this drop of water. Okay, so, um, so to find, um the apparent Wait, we're going to the apparent wait. Sorry. Their parents ways will be equal to M v squared, divided by our. So we have to find what is the velocity off the water drop? In order to calculate the apparent weight to calculate the velocity, we use information about the amount off rotations that the clothes washer make. So we have that feet is going to be equal to, uh, 1000 and 200 rotations per minute knowing that each rotation has a perimeter off two times pi times the radios off the coast washer times. Uh, sorry. Let me race this, um two pi times 0.225 m. Okay, on. By doing this calculation, we're going to find that the velocity of the water drop will be equal to 28 m per second. So we just be stupid. The velocity inside the expression for the appearance. Wait. So we have that is going to be the mass of the water drops of one times 1 to 10, 1 times a 10 to the minus 3 kg times to a near eight squared, divided by 0.225 So we're going to find it. A period weight off the water drop will be just, um, 3.48 Newtons. So

Measuring or counting by mass is a very common technique not just used in chemistry but also used in order to determine the amount of candy that is present. Such a jelly beans has mentioned in the problem or in order to determine the number of washers, nuts or bolts that air found that air purchased at a hardware store. And it often works quite well, assuming that the mass of each of these is relatively constant s. So there's not much difference in Mass between, say, one jelly Bean and the next jelly bean or one washer and the next washer. This question asks if we have 100 washers, what would be the mass of 100 washers, knowing that each washer has a mass of 1000.110 g? Hopefully, you can see that this is a simple conversion where we're simply going to our Multiply 100 washers by the mass of a single washer. To get the total mass of 100 washers, which would be 11 g. The next one is a reverse conversion. We now have measured the mass of the washers. We have 100 g of washers. Can we determine from this mass measurement, The number can we count by mass measurement the number of washers we can. We just use the conversion factor as a reciprocal, and we divide 0.110 into the grams. In order to get the number of washers, we get 909.99 repeating. And it's not gonna be exactly a whole number, because thes washers will likely have slightly different masses. And our ability to measure is going to be limited to three significant figures. So we really should round this to three significant figures. We would say there are 909 washers.

So when we're talking about counting by weighing as opposed Jew, um, you know, counting by number. Ah, lot of times we do this with really small items. So if we know that one washer has the massive 10.110 grams, if we want the mass of ah 100 washers, we just multiply that mass times 100 we get the mass of 11 grams. But if you've not learned about dimensional analysis or factor label method when you have a unit conversion and you're not sure whether to multiply or divide, sometimes it is, um, much easier to use these conversion factors where you always multiply. And we know that if we know that it's 0.110 grams per washer, that can allow the grams to cancel. If I put that there and then one washer is on the top, so 100 grams would divide by 0.110 and we'd have 909 washers

So we first know that I am someone plus M sub two is equaling 5.0 kilograms or we can say M sub too is equaling 5.0 kilograms minus m sub one. And so we can say that the force is gonna be equaling the gravitational constant times. I'm so one time Sam said two divided by our that this are square of the distance between them squared and we know that then, uh, 1.0 times 10 to the negative Eighth Newtons is equaling 6.67 times 10 to the negative 11th and this would be Newtons meters squared per kilogram squared. This would be multiplied Bye m someone multiplied by 5.0 kilograms minus m someone all divided bye 0.200 meters Quantity squared solving for m sub one. We find that then I'm someone is equaling 3.0 kilograms and of course, amps up to is equaling 2.0 kilograms. You can simply plug this into your tea. I 84 85 or 89 saw for m someone. And then, of course, I'm sub two is simply five kilograms minus m someone. So these would be the mass the the two masses that we're trying to look for. That is the end of the solution. Thank you for watching.


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