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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

We have Carson people is It's too give and it would. So here, too, is used for oxygenating in submarine. Who is used or oxygenating in submarine? We need to identify P and Q. Two. We need to identify P and you No peace. I need to. And who is two or two? Mhm. You can say up. Sunday is correct.

As we know that Edge Plus has Mhm great there mobility then and Plus any plus be cowed of its is smaller side as compared with as compared with any therefore, therefore electric potential. Therefore, electorate potential of add plus, it is greater than that of and a plus so X plus is reduced in per in preference to any plus. So option seats correct here.

Okay, so we have several solutions, and we have to rank then in decreasing prison point. Okay. Um, the important thing about this question is to consider the dissociation pattern and this substance. Okay, so the Friesen point change. Okay, follows this former. It's a constant. Okay, that depends on the substance. It depends on to solvent. There's a negative sign just to remind you that this is going down. So the freezing point goes down as you increase the concentration off the particles. Then you have the morality off the solution. Okay? And there's one extra piece que auction we we can represent as an I that I is used to taken account of dissociation What that means. Well, it really the collective properties, they depend on the number of particles in the solution. Not really. Then the number of molecules just started because molecules, you may have a big molecule, but when you put that in solution, that breaks into smaller particles. Okay, so the number off these smaller particles is what matters. So this I exist to take in account this association. So for example, in this case, I would be three, right? Because this big molecule here or Crystal or whatever is not. He broke into three pieces. Okay, so for each spaces, we have to consider whether or not there would be the association. Okay, so first, let's look at sugar. So the sea, Uh, let's see. Six age, 22. 06 actually, sugar. It's a molecule. Um, and there's no significant dissociation when you put that in water. So it's solid is right. A complete reaction. When he goes through the solution, it won't change the structure. It would just be solve aided by water. So I would be just one because one particle became one particle. Um, the tricky one among the list. And the question is C age three c o. Because this one actually establishes an EC equilibrium. Okay, so once it's dissolved in water, you can he can associates because it's an acid. It's an organic acid, so this hydrogen here can pop out. Okay, Uh, if you don't remember organic chemist er deaths here, C o h. That's an organic acid that's characteristic over an organic acid. Okay, so what can we say about I? We can really say the eyes equals one, because that would say that would be implying that the association here is complete, which is not the case. This association actually is quite small because organic assets are which, in a sense, that their dissociation is to his mo extend. So all we can say is that I is greater than one, but likely it's also smaller than, say to it would never get to being a weak acid. Okay, so let's quickly go through the orders. The under three are actually salt, so it's easier. So I'm going to write this in a simplified way. So, for example, if you have the they saw the salt, the sodium phosphate and it will pretty much completely the associate and to three. So Deion's and a false wait. Okay, so I, in this case, will be or all right for make news in chloride, Same thing that will break into magnesium two plus and to chloride. Okay, so I equals three. And finally we have sodium chloride that would associate into sodium and chloride. So I equals two. Well, so now what we have to do is trying to create a little table and put the I into consideration. So let's say let's see if we can do that. So we have the sugar first we have the organic acid. We have sodium phosphate, magnesium chloride, sodium chloride. Okay, we have the concentration. So point this is in more. That's more the morality. Uh, same thing here. Here we have 0.10. Here we have from 20. Here we have 35. So we have ice. This is one. All we know here is the greater than one hair. It will be for three and to So let's multiply across. So this one 0.15 this one we don't know, but we know it's greater than 0.15. It was certainly be smaller than points through three. Remember? Because I said that it won't get to it won't get to be too. This one will be point for this one will be 10.6. And this one will be 27. So I actually organized that already in order here because now you see that the freezing point would go down in this way because of these values here

Well the question is sodium. I drove. I dropped sleep. I think I grow a score pick absorb moisture when exposed to the atmosphere. I student placed a quarter of anyway. On the last a few years later, he noticed that the color was covered. A white solid, identify the white solid. We need to identify, identify divide solid. So sodium hydroxide as we know this is hi gyroscopic material. This is the hydra skah pick compound which absorbs the moisture then exposed to the atmosphere so we can write a. It wasn't to any elect less. C. 02 the atmosphere atmosphere. This will give who Here to see you three less Will not give care to 03 since it is too anyway. So it will give between you U. N. O. H. Plus your two will give an A. To C. +03 which is solid. So this is what which looks like a white solid. Yeah, we can see that. Hobson. She is correct. And to see you.


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