In this problem we're going to be working with molar ratios were given that we have a substance called hemoglobin which is found in blood is 6% of a substance called him which is 6 34. Sorry, C. 34 age 32 F. E n 44 were given that this can be treated with a few other substances to form a substance called human which is C. 34 age 32 404 F. E C. L. And were given that we have 0.65 g of hemoglobin. We want to find out how many grams of him moles of him and grams of iron that we have and then how many grams of human can be formed. Our first step is finding out how many grams of him we have. This is this can be found by this equation. So our mess is equal to the mass of the sample times the mass of the component over the total mess. And this part here is our 6%. So it's six over 100. We're going to assume that we have six g of him over 100 g of hemoglobin. So when we plug everything in we have 0.65 g of hemoglobin times six g of him over 100 g. And when we multiply all that out, we get our answer which is 0.39 g of him. Our next task is to find out how many moles of him. This is so we just convert, we run a molar mass conversion. So we have 0.39 g of him. Now we don't know the molar mass of this. So we do have to find that out. Which means we have to look at all the elements that we have in him. We have carbon, hydrogen, iron, nitrogen and oxygen. And then we need to see how many of those we have. We have 34 carbon, 32 hydrogen one iron for nitrogen and for oxygen. And then we multiply each of those numbers by their respective atomic masses. So carbons is 12.11 times 34 is 400 an 8.374 hydrogen is 1.8 Multiplied out is 32.256 Irons is 55 0.845 Which isn't going to change nitrogen is is 14.7 times four is 56.28 and oxygen is 15.999 times four is 63.996 When we some all of those together, we get 616.449 g per mole. So we're going to divide our 0.39 Bye. 616.44 nine g. And that's going to give us an extremely small number. So I'm going to write it in scientific notation. 6.3 times 10 to the negative fifth moles of him. Alright, the next thing that we need to do is find out how many is it grams? Yes, grams of iron we have in our sample of him. Well, I'm going to start with this Mueller amount that we just found down here 6.3 times 10 to the negative fifth moles of him. And then I'm going to go back and look at the chemical formula for him. Which is this big long one here. And I can see that if we have one mole of him. The subscript for iron is one. It's one part iron. So that means we only have one mole of iron in one mole of him. That's convenient. So one mole of him contains one mole of iron. And then we need to convert that into grams, which we already know is 55.845 All right. So 6.3 times 10 to the fifth, negative fifth, sorry, times 55.845 is going to equal 3.5 times 10 to the negative third grams of iron. All right. And then finally, we want to know how many grams of human can be formed from this sample. So, the way that we are going to do this is once again, we're going to start with the 6.3 times 10 to the negative fifth molds of him. All right. And then we're going to go look at the chemical formula for human. We're going to notice that human and he um are almost identical. They have all the same things except for human has some chlorine in it. So we can say that one mole of human contains one more of heat. So that gives us our moles of human. But we want this in grams. So we need to know the molar mass of human. However, like I said, they're almost identical. Human. Human are almost identical. And we already know the molar mass of him and we know that the only difference is that there is a chlorine atom in human. So we just need to take our 616.449 that we found and add a chlorine molecule. So that's 616.449 grams per mole plus the atomic mass of one chlorine atom, which is 35 0.45 g. That's going to give us 651 0.94 nine so one mole of human is 651.949 grams. And when we multiply that out 6.3 times 10 to the negative, five times 651.949 Once again in scientific notation, we get 4.1 times 10 to the negative two g of human.