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Totl blood volumc (1 ml) pcr body "cizhr (1 kg) Inlponant M nicdical [cicarch For ncurhy aduirs Inc Icd blocd cchl volunkc mcal aoouT ( Rogg haenidEten Hood nd...

Question

Totl blood volumc (1 ml) pcr body "cizhr (1 kg) Inlponant M nicdical [cicarch For ncurhy aduirs Inc Icd blocd cchl volunkc mcal aoouT ( Rogg haenidEten Hood ndetnc TEo bloo4 ceoumeuen tollor 32,26 43,38,29 40,rsmir Rcd blood ccll rolumc thar i5rcothighindicarc mceicdl Mccica Juccosc TharThc smpla mcan % 1 3nli Lotk pcom vanable that [cpTescnrs Rotet # Iid Nlood cllrolumc Aeeiymc tKrKhi: ammal duanhurion and € 2 miFO; 0.008 krcl of slgaificancc4,75 Do thc data ulicata that Rozs , clblocdcc

Totl blood volumc (1 ml) pcr body "cizhr (1 kg) Inlponant M nicdical [cicarch For ncurhy aduirs Inc Icd blocd cchl volunkc mcal aoouT ( Rogg haenidEten Hood ndetnc TEo bloo4 ceoumeuen tollor 32,26 43,38,29 40, rsmir Rcd blood ccll rolumc thar i5 rcothigh indicarc mceicdl Mccica Juccosc Thar Thc smpla mcan % 1 3nli Lotk pcom vanable that [cpTescnrs Rotet # Iid Nlood cllrolumc Aeeiymc tKrKhi: ammal duanhurion and € 2 miFO; 0.008 krcl of slgaificancc 4,75 Do thc data ulicata that Rozs , clblocdcclltluma diferenr (cathar uzy) trom



Answers

Hemoglobin is 6.0$\%$ heme $\left(\mathrm{C}_{34} \mathrm{H}_{32} \mathrm{FeN}_{4} \mathrm{O}_{4}\right)$ by mass. To remove the heme, hemoglobin is treated with acetic acid and
$\mathrm{NaCl},$ which forms hemin $\left(\mathrm{C}_{34} \mathrm{H}_{32} \mathrm{O}_{4} \mathrm{O}_{4} \mathrm{FeCl}\right) . \mathrm{A}$ blood sample from a crime scene contains 0.65 $\mathrm{g}$ of hemoglobin. (a) How many grams of heme are in the sample? (b) How many moles of heme?
(c) How many grams of Fe? (d) How many grams of hemin could be formed for a forensic chemist to measure?

In this problem we're going to be working with molar ratios were given that we have a substance called hemoglobin which is found in blood is 6% of a substance called him which is 6 34. Sorry, C. 34 age 32 F. E n 44 were given that this can be treated with a few other substances to form a substance called human which is C. 34 age 32 404 F. E C. L. And were given that we have 0.65 g of hemoglobin. We want to find out how many grams of him moles of him and grams of iron that we have and then how many grams of human can be formed. Our first step is finding out how many grams of him we have. This is this can be found by this equation. So our mess is equal to the mass of the sample times the mass of the component over the total mess. And this part here is our 6%. So it's six over 100. We're going to assume that we have six g of him over 100 g of hemoglobin. So when we plug everything in we have 0.65 g of hemoglobin times six g of him over 100 g. And when we multiply all that out, we get our answer which is 0.39 g of him. Our next task is to find out how many moles of him. This is so we just convert, we run a molar mass conversion. So we have 0.39 g of him. Now we don't know the molar mass of this. So we do have to find that out. Which means we have to look at all the elements that we have in him. We have carbon, hydrogen, iron, nitrogen and oxygen. And then we need to see how many of those we have. We have 34 carbon, 32 hydrogen one iron for nitrogen and for oxygen. And then we multiply each of those numbers by their respective atomic masses. So carbons is 12.11 times 34 is 400 an 8.374 hydrogen is 1.8 Multiplied out is 32.256 Irons is 55 0.845 Which isn't going to change nitrogen is is 14.7 times four is 56.28 and oxygen is 15.999 times four is 63.996 When we some all of those together, we get 616.449 g per mole. So we're going to divide our 0.39 Bye. 616.44 nine g. And that's going to give us an extremely small number. So I'm going to write it in scientific notation. 6.3 times 10 to the negative fifth moles of him. Alright, the next thing that we need to do is find out how many is it grams? Yes, grams of iron we have in our sample of him. Well, I'm going to start with this Mueller amount that we just found down here 6.3 times 10 to the negative fifth moles of him. And then I'm going to go back and look at the chemical formula for him. Which is this big long one here. And I can see that if we have one mole of him. The subscript for iron is one. It's one part iron. So that means we only have one mole of iron in one mole of him. That's convenient. So one mole of him contains one mole of iron. And then we need to convert that into grams, which we already know is 55.845 All right. So 6.3 times 10 to the fifth, negative fifth, sorry, times 55.845 is going to equal 3.5 times 10 to the negative third grams of iron. All right. And then finally, we want to know how many grams of human can be formed from this sample. So, the way that we are going to do this is once again, we're going to start with the 6.3 times 10 to the negative fifth molds of him. All right. And then we're going to go look at the chemical formula for human. We're going to notice that human and he um are almost identical. They have all the same things except for human has some chlorine in it. So we can say that one mole of human contains one more of heat. So that gives us our moles of human. But we want this in grams. So we need to know the molar mass of human. However, like I said, they're almost identical. Human. Human are almost identical. And we already know the molar mass of him and we know that the only difference is that there is a chlorine atom in human. So we just need to take our 616.449 that we found and add a chlorine molecule. So that's 616.449 grams per mole plus the atomic mass of one chlorine atom, which is 35 0.45 g. That's going to give us 651 0.94 nine so one mole of human is 651.949 grams. And when we multiply that out 6.3 times 10 to the negative, five times 651.949 Once again in scientific notation, we get 4.1 times 10 to the negative two g of human.

This question now you just It says if one off the test subjects is randomly selected, find the probability that the subject did not use marijuana. Find the probability of the subject that he did not use marijuana. These are the total subjects who did not actually use marijuana. These are truly negative. These are the ones who are negative and who have also tested negative. But these are the ones who are negative but who have falsely been tested positive. So 24 plus 1 54 is 1 78 1 78 by 300. This is the probability that we want. And do we think the result affect the general population rate off subjects who do not use marijuana? I think the result is somewhat low for people who do not use marijuana. By the way, this value turns out to be 0.59 something zero point Faith Night. And this is my answer

Explanation for the question here. Answer for party. Yeah. The locus. Yes. Hamas, I guess. Right? Only one big build up your Yeah, I answer for what we suspect. Three. So here, comparing Mhm the specimen. Right space, Eamon. Blood stand. All right. And of the no suspect tree, the elites and height all week are the same. Yeah, and answer for Parsi. It will be difficult. 200 person. Sure, if only when locus is used and usage of three lucky eliminates the concept of chance being the result of being pointing. Suspect tree the tree. Look. I made sure they damage between the sample and suspect. Torri is to make sure no other suspect makes the same simple. So here in past day, Big height. Those in red are lower. Mm. And suspect mhm then in suspect. For that And the gates, less DNA was taken from suspect one. Four p. C. R. And vilification

So this problem deals with hemoglobin and for part A. You want to find its molar mass. So you know that the chemical formula for human woman c 2952 h 4000 664 and 812 oh 832 if eight and F E for so. First, we have 2000 952 carbon atoms, each of which are 12 point no. One ground from all 4664 hydrogen atoms, each of which 1.8 graphs from Rome, 812 Nigerian Adams, 14.1 grams from all 832 auction Adams, each of which are 16 grumps more eight sulphur atoms, its atomic mass of 32 point 07 And then finally four iron atoms such as an atomic mass of 55 0.85 So when you add all these together, we get that are mullah mass of hemoglobin 6.5 32 times 10 to the four grams Promote now for part B For part B. We want to find the mass of hemoglobin and every human adult, and so were given a couple of youthful numbers for to solving this problem. So we know that every human has five point of leaders of blood and that in every mill later blood, we have 5.4 times 10 to the nine red blood cells. So permanent leader, and then finally, we have two point eight times tend to the eight hemoglobin molecules, chemo molecules for every one red blood cell. So those are gonna be are useful conversions when we're gonna find the final answer. So we know that every human that we're gonna start with has five point leaders of blood and you're to convert this to middle leaders, so we just multiply by 1000. This is where our first number comes because we know that for every middle leader blood But there are 5.0, terms tend to the nine red blood cells. And then our second conversion comes in, you know, they're 2.8 times 10 38 hemoglobin molecules for everyone. Red blood cell. The next up we need to do is we convert this two moles of hemoglobin because right now we have molecules of human woman so well, just divide by Abu Godric's number, just six point over two times 10 to 23. You know that that's how many molecules you are in one more of any substance, and I would get moles of hemoglobin. And finally we just multiply by the more massive hemoglobin that we calculated per a just 6.532 times 10 to the four grams for every one more. I'm hemoglobin and in the most play all that out. You will get that the molar mass or not, the molar mass, but the total mass of hemoglobin and every human adult. There's 7.6 times intentionally two grams. That is a final answer.


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