5

Using Kirchhoff's rules find the following: (870.8 V, 82 60.6 V, and 83 79.6 V.)4.00 kn3.00kn2.00 kI2(a) the current in each resistor shown in the figure above...

Question

Using Kirchhoff's rules find the following: (870.8 V, 82 60.6 V, and 83 79.6 V.)4.00 kn3.00kn2.00 kI2(a) the current in each resistor shown in the figure above 35400 { Apply Kirchhoff's rules to write set of simultaneous equations that can be solved for the current in each Part of the circuit: mA 2.35e-3 IRz Apply Kirchhoffs rules to write set of simultaneous equations that can be solved for the current in each Part of the circuit: mA 103 mMA(b) the potential difference between points

Using Kirchhoff's rules find the following: (8 70.8 V, 82 60.6 V, and 83 79.6 V.) 4.00 kn 3.00kn 2.00 kI2 (a) the current in each resistor shown in the figure above 35400 { Apply Kirchhoff's rules to write set of simultaneous equations that can be solved for the current in each Part of the circuit: mA 2.35e-3 IRz Apply Kirchhoffs rules to write set of simultaneous equations that can be solved for the current in each Part of the circuit: mA 103 mMA (b) the potential difference between points and magnitude of potential difference point at higher potential Select-



Answers

Using Kirchhoff’s rules, (a) find the current in each resistor shown in Figure P 18.25 and (b) find the potential difference between points $c$ and $f.$

There to nuke equation for the circuits are even minus. I won Obon minus I three R three physical studio and e minus. I don't ar minus. I three are three's equals zero. The junction rule equation is then Ivan is equals toe I took place. I treat This is the Junction Rule Equation Junction decoration to find the current through each branch with substitute by the junction rule equation into the Tokyo to new pick creation as following even it took was to Ivan are one place I minus I do are three physicals to video you do is close to I are to place. I want minus I to are three physical So zero you think given values off the distance and the e m f we can sold for Ivan and I do I went is equal to 0.144 and I do is equals to 0.139 And beer I had three is equals to Ivan minus I if it falls to therefore I trees equals to Ivan minus I to close to zero point Double 05 appeared No the potential difference across our three The potential difference across are three is we are three, which is close to 0.139 multiplied 20 is because 2.78 world

The loop equation for this circuit is here we have the lubrication. Was it first revealed the current in the circuit is movie Clich? Gotta in this or get is I on one place are pointless rt I was renting minus it clouded by 60. This is a little black to empty it now the voltage contribution by each element is adding all these equations together when we get seed overboard, as expected from Kidjo through loop rule which states there the summer off electric potential difference across the we'll also get zero.

Okay, so we have this configuration and we want to know what the current in each resistance is. And what is the potential difference between sea and death? Okay, for this, we're going to use the junction rule on the loop. You so first to know how to use the juncture rule. We have to know how current is flowing through this circuit. Okay, so we're going to see a in one first. We know that a large bar, the notes positive. We know that a small part, you know, it's negative. And we know that generally the current flows from negative coincidence. This is the first current we have. And in the three, we have the same. We have positive and negative, and we know that current lows from negative to positive. Okay. And we have here, I pray we know I want If you see, it's ah, traveling. Let's say just clockwise. And I three is moving counterclockwise until they both meet at point C. Okay, so this is important because you can see that at this point, we have also Hugh positive and negative. Okay, But if current flows in the direction off, negative to positive all the current will meet in point C. Onda. That cannot happen. That has no physical sense. So, actually, the current that flows here, it's, uh, the opposite direction on this I two. Okay, so it's okay if you do this. Uh, Andi, if you may have made a mistake, you can correct it. Always later in the with the direction of the current. Okay, so if we look again and Junction see Okay, way. See that Here. The three currents. Uh, we're like I won last 83 Okay, get together. And for I two. Okay, so this will be the first equation that is form the junction rule. We can use Onda. Then we have We're going to use the loop rule, but we have to choose to different loops. Okay, so the first one, it's going to be this one. It starts at seven votes, and I take it, uh, clerk. Once this is the first loop I choose is the first I'm going thio. So on the second one, I'm going to use light Blue is counterclockwise is going to be this part and is okay. So for the first one that is the purple one you see that at this point, we have seven bones. It's important because I will be moving, uh, clockwise. When I go from negative to positive. I have a positive voltage. So this is just 17 positive. Okay, then I go through the 60 vote source, and you see that, actually, I'm going to measure from positive to negative because I'm maturing. Uh, clockwise. So this is minus 60. Thanks. And then I'm going to pass around. Resistance are too. Okay. So since this is in the same sense as the current, this is negative. And you know that from arm slow. You know, that potential difference equals resistors value, plus the current. So I know the resistor value is three kilometers. Let's not forget we are using killer, um on, uh, the current in this case is I to okay my nose to I want equal zero. So this is the first, uh, more like the second equation I can use to solve this. Find the values of the current. Okay. And then for the other one, that it's the light blue, I will do exactly the same. But on the other. Look and I will start from the 80 votes source. Okay, so since I'm counterclockwise, I'm measuring from negative to positive. So I have a positive voltage. Okay, then I get to the four Killem. My sister, this is remember again using, uh, I'm slow minus four times three. Okay, that is the current I have there. Then I get again to the 60 votes source on again. Since I'm coming from positive to negative. This is negative. Minus 60. Okay, My nose and again, I have the resistor to three times. I Okay, so I have threes. These three equations that needs solving. So actually, it's pretty simple. I think you could do it yourself because you're awesome. But when you solve, you can also use a calculator online that can help you. And when you solve this, don't forget that these values are in killer on. So you have to make the make the units change at the end. But you will find that I want equals zero point 385 million pair. Again. This is Milly. Because we had kill arms. This is the one flowing through our one. I have I to equal toe 3.8 million pair. I missed three here. This is actually flowing through our to okay, this is our to are one. And then I have that I three equals two points. 69 million pair. And it's the one flowing through our three r three. I didn't vote it, but it's actually it is what it started. Okay, so this is the final answer. When you solve that on, did you make the unit change from Killam to him? You will find this and then were asked to find the potential difference between points See using. Now, this are dark between this point. See, on this point f Okay, so I want to find, uh, this what? It's the different potentials from FTC and I. This is pretty easy. Actually, we know that in See, the potential is 60. It's negative because I'm measuring now in the same sense as the current from positive. Positive. Negative. So this is minus 16 minus. And I want to find theme The potential in our to that it will be minus three killer arm times 3.8 million, bird, that it's the current flowing through. Remember, this is our two. Okay? This is values for our two, and this is minus 69.2 volt. So the potential difference is, uh, this value. Okay. I want to know what it's at. The highest potential. You can see that. Since this is negative, it means that the negative value it's higher. Okay, so this BC, it's higher. So Point C is higher in potential. Okay? And this is Thea for these problems.

The equivalent resistance off the circuit is given by 40 and 20 are in city, so that becomes 60. So one of US 60 thus sounded last 20 is 90 in verse off that last 50. That's 20 and this comes out to be 106 home. So the simplest archetype them will be. I'm just six home connected by 120 volt battery. Now, if we want to find the current, we have to do current equals. Water your resistance. It was 1 20 village divided by one of six home. So that comes out to be 1.1 ampere. The potential difference between point A and B with the the current must abide by the agree with and resistant redoing the point A and B which, with the 106 door doesn't minus 50 minus 20. So that would be 1.1. Ampere must abide by 36 Oh, so that comes out to be 41 vote


Similar Solved Questions

5 answers
PelntzProidvsAteIGT SCncCCi49024RotiJek Your ToncharFind( "(t)6 Sin(0) =(() =(t) = 8e' 6sin(t)8e" + 8+ 2
pelntz ProidvsAteIGT SCncCCi49024 Roti Jek Your Tonchar Find ( "(t) 6 Sin (0) = (() = (t) = 8e' 6sin(t)8e" + 8+ 2...
5 answers
How many nucleophilic sites does this molecule have? OH G e) HzN- BrWhich of the following cyclohexane molecules has the best leaving group?H3C_ CH3OMeSHSort the alkyi halides shown below from reacting fastest to slowest in an Sw2 reaction; all other reaction conditions are the same_ 2-Bromopentane b) Bromobenzene Bromomethane 1-Bromopentane 1-bromo-2-penteneCH3CH3
How many nucleophilic sites does this molecule have? OH G e) HzN- Br Which of the following cyclohexane molecules has the best leaving group? H3C_ CH3 OMe SH Sort the alkyi halides shown below from reacting fastest to slowest in an Sw2 reaction; all other reaction conditions are the same_ 2-Bromopen...
5 answers
Write the expression for the equilibrium constant for the following reaction.Enclose pressures parentheses and do NOT write the chemical fomula as subscript For cxample, enter (PvH;)" as (P NH;)? If cithcr the numerator or denominator is please entcrMnOz(s)MnO(s)Oxe)
Write the expression for the equilibrium constant for the following reaction. Enclose pressures parentheses and do NOT write the chemical fomula as subscript For cxample, enter (PvH;)" as (P NH;)? If cithcr the numerator or denominator is please entcr MnOz(s) MnO(s) Oxe)...
5 answers
Acety] coenzyme A (acetyl CaA) is the key intermediate in food metabolism. What sugar is present in acetyl CoA?
Acety] coenzyme A (acetyl CaA) is the key intermediate in food metabolism. What sugar is present in acetyl CoA?...
5 answers
Part BVnal peicent 0Kielic engln uoe; U puilexr Jvcpulle)AeuiCoctuamttu~cneIncolcl Innrain;Hmomoae relimu
Part B Vnal peicent 0 Kielic engln uoe; U puilexr Jvc pulle) Aeui Coctuamttu ~cne Incolcl Innrain; Hmomoae relimu...
5 answers
2 8 2 22 3 ! 2 [ 3 & I Z 2 2 ii! 2 Z 2 8 J 5 2 1 5 2 2 i 1 HF { { 31 H 1 { 0 Fle I [ N ! ! 1 1 2 € 1 [ 1 1 } 3 L I L 3 H 7 M { 7 0 LL 6 [E #T [
2 8 2 22 3 ! 2 [ 3 & I Z 2 2 ii! 2 Z 2 8 J 5 2 1 5 2 2 i 1 HF { { 31 H 1 { 0 Fle I [ N ! ! 1 1 2 € 1 [ 1 1 } 3 L I L 3 H 7 M { 7 0 LL 6 [E #T [...
1 answers
Determine the appropriate functions. The capacities (in L) of two oil-storage tanks are $x$ and $y .$ The tanks are initially full; $1200 \mathrm{L}$ is removed from them by taking $10 \%$ of the contents of the first tank and $40 \%$ of the contents of the second tank. (a) Express $y$ as a function of $x .$ (b) Find $f(400)$
Determine the appropriate functions. The capacities (in L) of two oil-storage tanks are $x$ and $y .$ The tanks are initially full; $1200 \mathrm{L}$ is removed from them by taking $10 \%$ of the contents of the first tank and $40 \%$ of the contents of the second tank. (a) Express $y$ as a function...
5 answers
Question 7Troni Mos ridt C t0 Ieast acidic Rank thc (elloutng anolcuz:
Question 7 Troni Mos ridt C t0 Ieast acidic Rank thc (elloutng anolcuz:...
5 answers
Find the following integral using the given substitution14dx x =2tant - 6 x2 + 12x + 4014dx= x2 + 12x +40+CEdit
Find the following integral using the given substitution 14 dx x =2tant - 6 x2 + 12x + 40 14 dx= x2 + 12x +40 +C Edit...
5 answers
BusinessLiberal Arts 563 572 586 570 567 574 577Sciences 601 601 582 594 599 593 589 593 610 580 614 591 597 613 588 615 588 587573 586 586 589 581 593 571 561 598 607 588 574 585
Business Liberal Arts 563 572 586 570 567 574 577 Sciences 601 601 582 594 599 593 589 593 610 580 614 591 597 613 588 615 588 587 573 586 586 589 581 593 571 561 598 607 588 574 585...
5 answers
Please explain me those concepts.1. Molecular basis of insulin secretion in beta cells.2. Insulin signaling in skeletal muscle, adipose tissue, andliver (Akt targets and consequences)3. General effects of insulin and glucagon on adipocytes,muscle, liver, brain.
Please explain me those concepts. 1. Molecular basis of insulin secretion in beta cells. 2. Insulin signaling in skeletal muscle, adipose tissue, and liver (Akt targets and consequences) 3. General effects of insulin and glucagon on adipocytes, muscle, liver, brain....
5 answers
Character table for Td point group linear; Elsc3/3C2/6S4 60d quadratic rotationsA1| 1| 1 | 1 |1Az| 1| 1 | 1 -1-1E /2 -1 222,x2-y2)T1/3 0 -1 | -1 (Rx, - Ry? Rz) T2| 3 | 0 -1 /-1a 1 (x,Y, 2)(xy, XZ, yz)
Character table for Td point group linear; Elsc3/3C2/6S4 60d quadratic rotations A1| 1| 1 | 1 | 1 Az| 1| 1 | 1 -1 -1 E /2 -1 2 22 ,x2-y2) T1/3 0 -1 | -1 (Rx, - Ry? Rz) T2| 3 | 0 -1 /-1a 1 (x,Y, 2) (xy, XZ, yz)...
5 answers
Problem 11. (3 points) Suppose A € Msxz_ Which of the following statements is TRUE?If p € R: such thatP = ^ [2 and A' p = 0 then must be zero vector in R?_If AT Ax = 0, then Ax = 0.(III) If A' Ax = 0. then X = u.only (B) I, II only (C) I, III only (D) II and III only (E) I, II, and III
Problem 11. (3 points) Suppose A € Msxz_ Which of the following statements is TRUE? If p € R: such that P = ^ [2 and A' p = 0 then must be zero vector in R?_ If AT Ax = 0, then Ax = 0. (III) If A' Ax = 0. then X = u. only (B) I, II only (C) I, III only (D) II and III only (E) I...
5 answers
Suppose the graph is planar but not connected, and has 2 components: Derivve a variant of Euler's formula for this case_V -e+f =
Suppose the graph is planar but not connected, and has 2 components: Derivve a variant of Euler's formula for this case_ V -e+f =...
5 answers
CHsCHzHScCFsAC-HC-Ch?Chig"Cha~CHa CH3
CHs CHz HSc CFs AC- HC- Ch? Chig "Cha ~CHa CH3...

-- 0.020605--