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(-/1 Points]DETAILS0/1 Submnissions UsedConslder the following heat of farmatlon data:FezOg(s) 4i" -822.16 */rol FeCis(s) AHro ~400 Klmol Rcl(o) AFLO Rmol Hza(...

Question

(-/1 Points]DETAILS0/1 Submnissions UsedConslder the following heat of farmatlon data:FezOg(s) 4i" -822.16 */rol FeCis(s) AHro ~400 Klmol Rcl(o) AFLO Rmol Hza(o) 4H" 7245,.82 *molCalculate AHO, for the rcaclon below. Pick thc cholco whlch glvcs this 4n" valugFeCl(s)Hoig)Fon0,(*)Hcl(g)Ahotan 149.5 kAh"T1556.] KJAHO -272.6 kJAnorn 272.6 RJ4he-1556.3 %Subinmanee

(-/1 Points] DETAILS 0/1 Submnissions Used Conslder the following heat of farmatlon data: FezOg(s) 4i" -822.16 */rol FeCis(s) AHro ~400 Klmol Rcl(o) AFLO Rmol Hza(o) 4H" 7245,.82 *mol Calculate AHO, for the rcaclon below. Pick thc cholco whlch glvcs this 4n" valug FeCl(s) Hoig) Fon0,(*) Hcl(g) Ahotan 149.5 k Ah"T 1556.] KJ AHO -272.6 kJ Anorn 272.6 RJ 4he -1556.3 % Subinmanee



Answers

How much heat is required to raise the temperature of $215 \mathrm{g} \mathrm{CH}_{3} \mathrm{OH}(1)$ from 20.0 to $30.0^{\circ} \mathrm{C}$ and then vaporize it at $30.0^{\circ} \mathrm{C}$ ? Use data from Table 12.4 and a molar heat capacity of $\mathrm{CH}_{3} \mathrm{OH}(1)$ of $81.1 \mathrm{J} \mathrm{mol}^{-1} \mathrm{K}^{-1}$.

Using the information given for part A. Where else? To calculate the heat of combustion of benzo, a gas ID using the heat of combustion benzo gas and calculate the heat of combustion per mole of caffeine. So let's calculate the heat capacity of the calorie emitter First. The calorie emitter from the mass of Ben's OIC acid. This would be equal to 0.235 g of the Benzo a kassid over 1.642 degrees Celsius times 26.38 Killer jewels per 1 g of the Benz OIC acid on. We'll find that this is equal to 3775 Kill a Jules per degrees Celsius and then you can calculate the heat of combustion per mole of caffeine, Christian, Permal, caffeine and this would be quote, too. 1.525 degrees Celsius over 0.265 g of caffeine times 3.775 Kill a Jules per degrees Celsius times where Moeller mass here to convert to mold 190 Captain is a molar mass of 190 4.2 grounds in one more, and we find that the heat of combustion is equal to four point 22 times 10 to the third kilo joules per more for part B. Let's calculate the uncertainty in this measurement. They told that the uncertainty in the mouse eyes put 001 grams and our math of Ben Zoellick acid is 0.235 g. So this is equal to, um and we're gonna multiply this by 4220 kg jewels per mole. Okay. And this would be equal to 17 point 95 killer jewels because air uncertainty in that mouse. Second one, this 10.1 g over the mass of the caffeine, which is point 265 g times the combustion. And this was equal to 15 9 to killer jewels and the uncertainty in the temperatures 0.2 degrees Celsius over, uh, 1.642 degrees Celsius. Times feed a combustion, and this is equal to 5.146 kill jewels and second temperature measurement is one point 5 to 5 to be Celsius times for 2 to 0 kg joules per mole. But we find that this is equal to 5.53 killer jewels. So our uncertainty here be equal to 17.95 killer jewels plus 15 92 killer jewels plus 5.146 kill a Jules plus 5.53 Killah jewels. So our total uncertainty works out to, um, 44.55 killer jewels in our measurement, Yeah.

This question. Ask us how much heat is produced by complete combustion off 5.56 kilogram off natural Matthew. First, we need to calculate the how many. Most of natural meeting are there. So many close to am divided by the molar mass off. Natural meeting on With On for this this Q. We have, um this reaction Okay, we have is true to most off Macha meeting. So we need to calculate and over two times, Delta don't. Her age reaction equals to 6.46 times 10 to the power of four killed Jules.

Let's determine the delta H. For the given equation we're going to take Equation two as it is which is p. four solid and 52 was produced E. For oh 10 Solid Delta. Each year is equal to negative. 2967 .3 Killer Jewels. And we'll take equation three. But we're going to multiply it times six. So this will give me six PCL 3 At six cl 2 produce six PCL five. And the delta each here would be six times minus 84 to killer jewels. And then combining these two together we will get okay. Yeah nothing canceling before 52 six pcs three 62 P 40. 10 six PCL five of the H. Would work out to be Negative 3472.5. You know jules. Mhm. Than to this we're gonna add equation for but we're gonna take equation for and multiply it by 10. So this would give me 10 p. l. L. three. Okay I had uh 502 Actually before we do that we're gonna flip this equation around. This would give me he for who? 10 solid six p. 00 five gas P. Four solid liable to. Yeah. Mhm. Six pcs three. Okay. And six l. 2 Delta H. Share is positive. 3,472.5 killer jewels. Now we're going to bring in equation four but times 10. Mhm. And this would give me 10 pcs three. True. And um 52 To 10 Cl 3pio. Mhm. And it's all to each year would be worth 10 times -285.7 killer jewels. Yeah. Yeah. So This would cancel enough with four here. 5.02's would counsel and I am left with P. For full 10 solid at six P. C. L. Five gas Plus four PCL 3 gas P. Four. Okay and succeed too. I had 10 cl three P. O. Gas. Okay. Here is equal to yeah. Really minus 615 5. Mhm. Killer jewels. Mhm. And then we're gonna take this and okay We've got to add # 1 to this. Mhm. Okay. So if I add number one to this we will get T. Four had six l. 2 gas 24 P. C. 03 Good. Yes. And the delta each year is equal to -1 225 6 Killer Jewels. So four PCL three would counsel P forward council successful tool council and looks like I'm left with P. Four oh 10 solid add six PCL five gas producing 10 cl threepio solid delta each year. Finally, here works out to -610.1 killer jewels for here. Yeah. Our final answer.

Just to start off with some contextual information. We can run over the definition off and to be changed first so the end could be changed. Is the name given to the amount of heat that has evolved or absorbed in a reaction carried out at constant pressure. So here we just have a lot of dates to consider in terms off having a lot off equations that are listed on the left as well as associated changing entropy values. You can see that we they are all ex Islamic because there will negative values. So we're able to use those values that are listed above in order to determine that entropy change, which is given the symbol felt h for this reaction, which is p full 0 10 on six PCL. Five generates. 10 c l three p o. So are changing entropy for that reaction is negative. 61.1 kg jewels


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