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How many $y$ intercepts can a function have? What about $x$ intercepts? Explain....

Question

How many $y$ intercepts can a function have? What about $x$ intercepts? Explain.

How many $y$ intercepts can a function have? What about $x$ intercepts? Explain.



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How many $y$ intercepts can a function have? What about $x$ intercepts? Explain.

Problem. 86. Can a graph of polynomial function have no axe Intercept? Yes, you can. Off course you can't. So, like why you goes toe x square plus one So he doesn't have intercepts, right? We can claim that if that degrees are it must force to the left and rights to the right or or writers to the left and force the right. So there has to be a here. The access And there has to be a point between this graphs because it's continuous. Right? There has to be one, at least one. So if a paranormal function doesn't have, ah acts intercepts, it has to be even degree, right?

This question asks us to say without graphing how many ex intercepts this graph will have and we do that. We find that by using the discriminative and the discriminative is B squared minus four a. C and so B squared. So that will be nine minus four times a, which is a negative, too. Times C, which is a negative one. And so here I have a negative times negative, which is positive times and negative, which will be negative. So this will be nine minus and four times two is eight times one is still eight. So this will be one. And so when we have a positive, we're going to have to roots or two ex intercepts.

Let us find discriminative. Look into the formula B squared. Minus four is C so I'm playing in two squared minus four times 40.25 time. See, giving us four minus four equals zero. Giving us discriminative zero. Therefore, there's one ex intersect or yeah?

This question asks us to say how many ex intercepts there are without graphing. So we're gonna use the discriminative, figure that out. And so what we do is we have the discriminative B squared minus for a C and B is nine minus four. B squared is nine. Cosby is three minus four times, one times a positive five. So here we see that we have nine minus 20 which is negative. 11. So this is a negative number. So that means that we're going to have no ex intercepts, because when we have imaginary numbers, we do have two routes, but they're two imaginary roots. So that means that I'm not touching this axe access here.


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