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Whkh products arc expected Iomtollntang (CachonaSv2...

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Whkh products arc expected Iomtollntang (CachonaSv2

Whkh products arc expected Iom tollntang (Cachona Sv2



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What product would you expect to obtain from aldol cyclization of hexanedial, $\mathrm{OHCCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO} ?$

We know that I want to die style banking. 12 die the tile banking on, audio analysis on or you know, lie Season gibbs. Gibbs three different products. Gibbs to the different products. So according to the option in this problem, obstinacy, it's correct answer.

So here we will start out. Um, but that molecule then use age I and she will. And this will produce I It's each to siege to ch two ch 20 h So it essentially open up. Um, this s o this can also look. Hi. We have 1234 She's so one. Do you three foresees there are no wage. So open up the ring and at an eye from the h I and add a ohh in age too low.

Okay, This problem is asking us to perform it. Robinson emulation on two methyl 13 cycle painting down and three butin to own. So this is my two metal 13 cycle painting down in which I have a carbon on the top, carbon on the bottom, and then a missile group attached to a five carbon rings. Okay. And then here's my three boots and to own like that. Okay, So, Robinson ammunition is essentially the base catalyzed de pro nation of the most acidic hydrogen. And then we're going to perform a Michael addition and then eventually and off with a little condensation. Intra molecular. Okay, so what I'm gonna do is I'm going to react this both of these compounds with sodium hydroxide, or at least have them both in the same environment and then have sodium hydroxide react with them. Okay, So, sodium hydroxide, we know the super basic base is going to d. Probably the most aesthetic hydrogen on one of these two molecules. So we have a couple options for the most aesthetic hydrogen. We have the hydrogen here. The hedging is attached to the Alfa carbon of this key tone. So that is an option. We also have one right here on this much school. Carbonell, we have this one, and we also have this one. This hydrogen is that hydrogen, which I just circled. The hydrogen is attached to one the Alfa Carbon, and to it is sandwiched between these two carbon heels. So those two cardinals are pulling electron density away from that carbon through residents and the inductive effects. Okay, so that's why this hydrogen is considered the most acidic hydrogen on both these molecules. So that is the proton that's going to get deeper donated in a solution with sodium hydroxide. So sodium hydroxide de protein ate that base. I'll just demonstrate that were here. That movie electrons onto you, that carbon. And then we should end up with the following compound, make sure has five carbons, okay? And then compares there. Then make sure we have our muffled group there. And then finally, my cover deals. Okay, Now we're going to perform a Michael addition. So my Michael addition attach, Use my nuclear fuel carbon to the beta position of my Alfa Beta on Saturday. Key toad. So when we demonstrate, is this nuclear fell for here? that is a nickel fell because it has low in pairs is considered a nuclear Philip carbon. It's going to attach or attack the beta carbon. And the reason attacks this carbon instead of the basement Carbonell like we might be used to is because obviously, we're used to attacking this Carbonell right there. And usually a key tone or Alba hide. But we have this auction considered Electra negative. The doctrine They're gonna move up to the oxygen if I move the electrons up to the auction. The auction, but considered negatively charged. And they will have a positive charge carbon right there that possibly charged carbon can be, um I guess d localized by the movement of the electrons from this double bond onto that single bond created double bond. Therefore moving the positive charge to this primary carbon carbon. Okay, so that is why we attacked the beta carbon. Okay, so next up, we're going to perform that. So let's just draw that out. Once I moved the electrons onto this carbon, I'm going to have to relieve that that carbon of its of its exceeded octet by the movement of electrodes from this double bond onto this carbon. Okay, so I've stayed in this in some other videos, but we might be used to seeing, at least in other mechanisms, the electrons moving on to the single bond and then the eventual movement of electrons and the auction. What we're going to see is that they eventually cycle back and then move on to the same carbon. Okay, so just the demonstration of one arrow will just do will be fine, OK? Because we're gonna end up with electrons and that carbon, no matter what. Okay, so I'm going to draw out the product of that, which is as follows. I have my car videos which are unaffected, and then on this carbon. I have my method group, and I also have the attachment to my, um my Alpha beta on Saturday key toe. So this carbon here, that carbon is this Carmen and then is attached to there's carbon. So let's try that up. I have attached to this carbon, which is this one is my former double bond to my former double bond, which is now a single bond. That single bond has a lone pairs. At least that carbon does okay. And then is attached to a carbon you like this and then attached. That is my metal group. So what we're gonna do is protein ate that, um that negative charge were inappropriate. That carbon someone to use the water that I had formed by the pro nation of sodium hydroxide in the previous couple steps like that. And then we should end up with this, which I have my Carmelo's unaffected on the top in the bottom, my metal group unaffected. And then we just created a chain like that. Okay, so this is where things get interesting in terms of the whole entire Robinson aviation. Because first off, we've just done Michael addition, but then this but Robinson and Elation ends off with Alba concision. Although, um, intra molecular, although conversation. So what have we just created? We just created a base right by the deep rotation water. We just created a base. So right now we're in technically basic conditions and basic conditions were still gonna We're still going to depopulate the most acidic hydrogen. If we look closely at my molecule, this carbon, which we might have thought would be continued the most instead of hydrogen, has so far four bonds, right? Has the talent to this method all as of the attachment to this carbon chain etcetera? Right there? No, a set of hydrogen there. But we also have an ascetic hydrogen here the hydrogen is attached to and, um, Taquito. It's on the outfit carbon. So it's considered acidic still. So I'm going to deeper Nate that, and then move the electrons onto that carbon. Once I performed that, I should get the same molecule just with deep throat Navy carbon. So let's just highlight that to make things easier and then just draw lone pairs on that central carbon on that carbon. Okay, so what I'm gonna do now is perform in intra molecular Aldo conversation because I have long piers here. There's my lone pairs, and then it's going to attack a Carbonell. So let's see if it is even prone. Teoh attack in a carbonate in the first place. And the way to determine that is to count how many carbons away that Carbonell is. So we have one. I always count my nuclear file as number one. So 1234 five. And then, of course we can. We have a choice. We can choose this one, or this one doesn't matter. Because after that, that molecule symmetrical. So, five. Let's just say this one has six. Okay? So, six, a six member during their You know that because we're attacking my number one on my number six. It's going to make a six member green six member dreams air Super favorable because they have virtually no ankle strain. Right? They have about 109.5 degree theories between their bonds. So that's why it's considered a favorable to make. Okay, so we're going to make that structure, and I'm gonna do so by drawing out what I previously had, which was actually, you know what? Let's just start off with my six member green. So every time I make, um and performing it in trauma molecular ring closure, what I first do is identify what Adams are in my 66 number. Adams. So right here, I have 123456 Those are all carbon. So I know I'm gonna have a six carbon number drain. Okay, so that is 123456 Okay, so at the six. And that's one. So attached to one. I have a carbon eel that Carbonell is attached. Number two. I mean, eso one is attached to two. We have a cardinal coming off. Three. We only have the 100. Jin's for only have Hodgins. Five is where things get interesting because we have a methyl group coming off a five. And then we have Oops. Sorry. And we also have the attachment to the remainder of my reign. So let's just draw that up. So attached to five, we have my painting like that, which is also touched a number six. And then we have, um, attached to five. We have this Carbonell and then attached to number six. We have this auction with which now has a negative charge. We know that because the electrons move up to the auction after this attacks. That Carbonell. Okay, so this is our current structure, and then let's just see Okay, so right now we're at this stage, we need to perform my album conversation. So right now I have my negatively charged auction that needs to be a pro donated. So I'm going to demonstrate that by using water we know we use water because we just had, um We had just pro native my, um, alcohol in the previous steps right there. Okay, so we're gonna use water. Water is going to protein, ate that auction with a negative charge. And then once I do that, I should get the following on. What you have is compound same thing, except it's just pro nated. So duplicate that. Move it over there, and then protein ate that. Okay. And then this is where my album conversation part comes in because condensation is essentially the net loss of water. So I'm at this point, I'm in basic conditions, sodium hydroxide. So my sodium hydroxide, same thing is going to d printed the most aesthetic hydrogen, or in this case, perform an elimination reaction. So I have 100 in here. I have my vulnerable even group. I'm going to perform my lemonade direction in which I use my base to be pro Nate, this hydrogen. And upon that d pronation, I'm going to move the electrons from the single bond onto this. This carbon hydrogen bonds onto this carbon combat carbon bond to create a double bond in the process. When I make that double one, this carbon has exceeded its octet. So I need to move the electrons away from that and onto this oxygen. So that auction that alcohol would be my leaving group. So I should end up with this as my final product in which I have a five member during connected to a six member green with carbon deal on there, a hulking right there and then Carbonell their method group there. Okay, so that should be my final product.

Number 21. The sentence here is Ah, popular modern belief that Robin was of the time over to the first probably stems from the anti query Richard Stew, please. Fabrication of a pedigree. What we're messing with is Does Stoop Leah's in Richard's Duke. We need to be possessive by using a comma. Excuse me by using on an apostrophe and might we need toe Atacama there? So first, let's start with the possession issue. Um, we have to look at the context of the sentence, the popular modern belief that Robin was of the time of Richard the first. So the belief probably stems from the antiquity. Richard Stew, please. Fabrication of a pedigree. So ask yourself, does the beliefs stem from Richard stupidly himself? Or does it stem from his fabrication of a pedigree? Yeah, The sentence is making it clear that fabrication is very important, meaning that it doesn't stem from the man Richards do Klay. It stems from his fabrication. His notice that I'm using the possessive there shows us that we're looking for the possessive, the apostrophe s so I can get rid of answer choices B and C that don't do that for us, then the only other question is, Should I put a comment here? Do I need to pause? Richards Do please fabrication of a pedigree or just get on with it. Richards Do please fabrication of a pedigree. Notice that you probably won't want to pause when you say that out loud. That's because the possessive Richard stew, please and what he is possessing the fabrication. Those are inextricable. They absolutely go together. So if you pause, you get in the middle of that, which does not help us understand the flow of the sentence. So for that reason will get rid of D and just stick with the no change version, gets the possession right and doesn't add any unnecessary pauses.


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