5

A compound microscope is an optical instrument used t0 view very smal objects. Tne simplest compound microscope system consisting Of two lenses The first lens the o...

Question

A compound microscope is an optical instrument used t0 view very smal objects. Tne simplest compound microscope system consisting Of two lenses The first lens the objective must create slighily enlarged inverted real image of a small object The second lens tne eyepiece Ihen takes lhis image and greatly enlarges it Which of the following statements correct about this type of compound microscope?The objective lens may be either concave or convex, but the eyepiece must be concave_ The objective len

A compound microscope is an optical instrument used t0 view very smal objects. Tne simplest compound microscope system consisting Of two lenses The first lens the objective must create slighily enlarged inverted real image of a small object The second lens tne eyepiece Ihen takes lhis image and greatly enlarges it Which of the following statements correct about this type of compound microscope? The objective lens may be either concave or convex, but the eyepiece must be concave_ The objective lens may be either concave Or convex_ but the eyepiece must be convex: The objective lens and the eyepiece are both concave lenses_ The objective lens Is concave lens while the eyepiece is convex lens: The objective lens is convex lens while Ihe eyepiece Is concave lens The objective lens and the eyepiece are both convex lenses_



Answers

A compound microscope is a two-lens system used to look at very small objects. Which of the following statements is correct? A. The objective lens and the eyepiece both have the same focal length, and both serve as magnifying lenses. B. The objective lens is a short focal length, converging lens and the eyepiece functions as a magnifying lens. C. The objective lens is a long focal length, converging lens and the eyepiece functions as a magnifying lens. D. The objective lens is a short focal length, diverging lens and the eyepiece functions as a magnifying lens. E. The objective lens is a long focal length, diverging lens and the eyepiece functions as a magnifying lens. SSM

All right. So the question was asking us what is the image distance for this question? So we know one over half is evil. One over. Reports of all over you use the object distance. Okay. And since you were saying that the I'll just to review is placed two point only made her beyond a focal point. Which means that the object isn't is equal to the focal lands class the beyond distance, which is 10 point on May meter. Last two millimeter, you could trawl name here. Okay. And the focal lens off the objective lamps is 10.0, millimeter. And I'm sorry. Here should be Evel on the wide right. Heavy. So the image distance we can we go to you task fo divide by U minus fo, which is 12 millimeter times time pulling. Oh, you familiar? Over 12 millimeter. Minus 10.0, millimeter. And this will give us 60 millimeter for the image distance. So the object the objective lens will form is first image as 60 millimeter. Okay, So whole question be it was asking us what is the overall magnification. Well, we know the over minus magnification is equal to 250 million mirror Tosti image distance over, uh, the focal lengths off. The objective times the focal lens off the eyepiece. So if we like no value, we'll get em. Is equal to 250 being manner Times 60 millimeters divided by the focal length off the objective lands, which is tempering. Oh, I am here times the focal length off the eyepiece, which is 15.0, millimeter. And this will give us the over magnification is equal to 100. Okay, so these are the solution for the question. Thank you.

Okay, This question is a little complicated, but in the resume we have a student that What's a lamp that's called the lamp? This error at a distance off 42 ST Emitters from, uh, convex lens or have here called accidents. And we know that with this configuration we have image form here, upside down at a distance off 37 0.5. Same team enters wonderlands. Okay, then the students makes a non under system. This time we maintain the limp at a distance off 42 off the Kovacs Lance. So it's to have same cold excellence, the same dear, since here. But this time we put ah here, and we know that the image now his form upside out again. But this time the images form at a distance off 35 centimeters. Dirty five ST Emitters from the second lens and the separation between the two lenses ar 15. Same team enters. Okay, so the objective off this experiment is to discover the focal length off the second lens, they convict the concave Linse. So let's begin with the first system that this student goes Troy. We know the objective is to discover the focus or cake. So let's look to the first system That's go assistant. One that's called System, too. If we looked a System one, we can discover the focal length off the cove excellence. So we're gonna have using the feelings equation. F one equals one, divided by G 01 plus one divided by Do You. I won distance of the image distance of the object so we have all this is gonna get one divided by 42 plus one divided by 37.5. So we have a focal lens for the convex lens off 19 point eight. State team enters. Good. Now let's move on. Let's calculate the focal length of the 2nd 1 We know that the focal ins, the 2nd 1 is going to be one divided by D 02 Pull us one divided by D I to all to the power off minus one. I forgot to put Minar swung in here. Okay, that is correct. That is correct. So let's move on, then. We have to calculate these to get the second focal lens off there. Concave lens. So, first of all, distance of the image we already have dirty fighting teenagers distance off the object related to the second lens. This would not have yet. So we're gonna have to make the separation off the two lances, which is 15 and subtract the position of the image off the first lens 37.5. So this gonna get us miners 22.5. Finally, we can calculate. So we're gonna get one divided by miners, 22.5 less, one divided by 35 all to the power of minus one. And finally, the focal inch off the second lens is gonna be minus 63. Same team enters. That's the final answer to this problem.

So in this particular case, it is easier to draw the diagram to start with. We have a squadron for a jig objective with, if all equal as 20 centimeter and 25 centimeter away. We have got the eyepiece with F e equals for born 05 centimeters. Now the object distance from the objective he's d O equals 4 25 centimeter and hide off the object he's can centimeter. So first we should find where with a mate people used by just the objective that's for that we will use in the distance equals one over, if my guess one over de um in verse that comes up to be one of our 20 minus 1/4 25 in verse Off that which comes out to be 20 invoice minus for 25 winners indoors, he's 20.98 This call it 21 sandy meter. Best answer off part A. This is, ah, really image and hide of the image with the magnification times, height of the object magnification is given by a mess. Distance over object distance times H o hide of the object image. Distance. He's ready one and up The distance is 4 25 dives. Height up. Docket is Jen Centimeter. So these years, the final height of the enmities do 10 divided by 4 25 it was 0.494 centimeter. So we can see that this 25 centimeters can be split into two parts. This is the initial image distance, which is 21 centimeter, which acts as the object for the eyepiece. So the object distance at the eyepiece becomes for sentimental. Now, for part B, we will once again use the same form with R B. I equals one over. If now I piece minus one over R distance for the obese which will come out to the 1/4 0.5 minus 1/4 in the worse equals negative. 324 centimeter. So this is Ah, I want to one image 324 centimeter under the objective. Now for the 10 and ready for sending your under the eyepiece Now the magnification at the eyepiece. Now we have to fight magnification at the eyepiece Equus Immense distance at the eyepiece divided by object distance at the eyepiece, which is three great before We're taking the absolute value over here. So that's 324 divided by Object District's WAAS, for so that comes out to be 81 which means final size off the image will be 81 times the height of the image after the objective. Waas. Well, is there a part 494 centimeter? So that comes out to be 40 point 014 now for part C. Don't does magnification comes out to be magnification off the at the objective multiplied by magnification at the eyepiece. Oh, this is all right, but we may not do that, and Total can be reading as the final object size final image size divided by the initial objects. Eyes were stand Centimeter 41 sending Me 40 centimeters the world by Ted's inhibitor. So that turns out to be four point 0014 or approximately equals four

Belongs to the chapter. Lengthen optical instruments and says that you have made a simple telescope. A simple telescope from two convex lens and the objective lenses from the one of the two lines that is closer to the object, closer to the object being observed. What kind of images produced by the eyepiece lens? If my PC is closer to the objective lens than the images produced by the objective lens. Okay, so for this question we can see that if objective lens intercepts the converging rays from the objective lines before they are fully converse. They are fully converse. Okay. The that then they will soon they will soon converts and still beyond the eyepiece lens on the same side of the optical axis as the amazing of the objective lens. So we can say that amaze will be the images that will be formed. It will be the real images and inverted images that will be real and inverted images. Okay. And inverted images. Okay, so the nature of the image is real and inverted. Okay, so this is the answer for this question. The the image that is formed by such kind of telescope is real and inverted. Okay, so this is the explanation for this question. Okay.


Similar Solved Questions

5 answers
763) ` 1 8how 8 8 Her 91 much E7 H Lu 2 1 1 and. He 7 1 CEnQLA : J07 1 M E chart) fecntste 1 5 1 1 2 higher college enrollment rate. 1 uuden & 1 Strorg ly Sara 1 1 3 pccause 1 accurate 1 5 amuise ding L about 1 H pruditcs celled olc descrpkion 2 8 weeks 1 L topic 1 1 66 1 1 1 colcee Inild 1 1 1 [ Yre 1 1 1 1 possibi 1 by shoa 1 Jetter 1 probubility scerenc 3 ech
763) ` 1 8 how 8 8 Her 91 much E7 H Lu 2 1 1 and. He 7 1 CEnQLA : J07 1 M E chart) fecntste 1 5 1 1 2 higher college enrollment rate. 1 uuden & 1 Strorg ly Sara 1 1 3 pccause 1 accurate 1 5 amuise ding L about 1 H pruditcs celled olc descrpkion 2 8 weeks 1 L topic 1 1 66 1 1 1 colcee Inild 1 1 ...
5 answers
(10 pts) Explain in words and illustrate schematically the trend in carbocation and carbanion stability increasing order:Whatthehybridization ANSWERofcarbocation?What is the hybridization of carbanion? ANSWER
(10 pts) Explain in words and illustrate schematically the trend in carbocation and carbanion stability increasing order: What the hybridization ANSWER of carbocation? What is the hybridization of carbanion? ANSWER...
5 answers
Is there evidence that hisze should be included in the model? What is the optimal school size? What is predicted SAT score for a black female and a black male provided that high school has 1000 students?" Are the variables of interest jointly important in determining the sat score?
Is there evidence that hisze should be included in the model? What is the optimal school size? What is predicted SAT score for a black female and a black male provided that high school has 1000 students?" Are the variables of interest jointly important in determining the sat score?...
5 answers
Calculate the limit for the given function and interval. Verify your answer by using geometry_lin LN, where f(z) = 271 + 4 over the interval [0, 4] N-0
Calculate the limit for the given function and interval. Verify your answer by using geometry_ lin LN, where f(z) = 271 + 4 over the interval [0, 4] N-0...
5 answers
What is the probability that Abby, Barry, and Sylvia win the first, second, and third prizes, respectively, in a drawing if 200 people enter a contest anda) no one can win more than one prize.b) winning more than one prize is allowed.
What is the probability that Abby, Barry, and Sylvia win the first, second, and third prizes, respectively, in a drawing if 200 people enter a contest and a) no one can win more than one prize. b) winning more than one prize is allowed....
1 answers
Why does $\mathrm{H}_{2} \mathrm{~S}$ have a lower boiling point than $\mathrm{H}_{2} \mathrm{Se}$ ? Why does $\mathrm{H}_{2} \mathrm{O}$ have a much higher boiling point than $\mathrm{H}_{2} \mathrm{~S} ?$
Why does $\mathrm{H}_{2} \mathrm{~S}$ have a lower boiling point than $\mathrm{H}_{2} \mathrm{Se}$ ? Why does $\mathrm{H}_{2} \mathrm{O}$ have a much higher boiling point than $\mathrm{H}_{2} \mathrm{~S} ?$...
3 answers
AthleteVertical jump height (beforc using shocs)Vertical jurp heieht (after using shoes)If a t-test is performed on the above dependent data set with an alpha level of 0.10 ad Ihe di fference between paired data iS calculaled as: d Before Alter then d Is equal to:a) 1.75 0) -1.75 c) -1415 d) 1.145
Athlete Vertical jump height (beforc using shocs) Vertical jurp heieht (after using shoes) If a t-test is performed on the above dependent data set with an alpha level of 0.10 ad Ihe di fference between paired data iS calculaled as: d Before Alter then d Is equal to: a) 1.75 0) -1.75 c) -1415 d) 1.1...
5 answers
Below are data collected for measuring stopping distance in feetas a function of the vehicle weight in poundsVehicleWeight (lbs) (x)Stopping Distance (ft) (y)256013327401363225137261513231101353320136321513635301373600139441514341801404095143Determine the equation of the regression line of theform Use your equation to determine the predicted stopping distancefor a vehicle with a weight of 3000lbs
Below are data collected for measuring stopping distance in feet as a function of the vehicle weight in pounds Vehicle Weight (lbs) (x) Stopping Distance (ft) (y) 2560 133 2740 136 3225 137 2615 132 3110 135 3320 136 3215 136 3530 137 3600 139 4415 143 4180 140 4095 143 Determine the equation of t...
5 answers
Use the Intermediate Value Theorem t0 show that the following equation has solution on the given interval: Use the graphing utility to find all the solutions to the equation on the given interval: Illustrate your answers with an appropriate graph 522 2x = 1; (-1,5)
Use the Intermediate Value Theorem t0 show that the following equation has solution on the given interval: Use the graphing utility to find all the solutions to the equation on the given interval: Illustrate your answers with an appropriate graph 522 2x = 1; (-1,5)...
6 answers
In Exercises 51 - 54, write the polynomial (a) as the product of factors that are irreducible over the rationals, (b) as the product of linear and quadratic factors that are irreducible over the reals, and (c) in completely factored form.$ f(x) = x^4 + 6x^2 - 27 $
In Exercises 51 - 54, write the polynomial (a) as the product of factors that are irreducible over the rationals, (b) as the product of linear and quadratic factors that are irreducible over the reals, and (c) in completely factored form. $ f(x) = x^4 + 6x^2 - 27 $...
5 answers
Question 9: Prove that if C is compact in X and f : X ~ Y is continuous then f(C) is compact in Y .
Question 9: Prove that if C is compact in X and f : X ~ Y is continuous then f(C) is compact in Y ....
1 answers
Let (n be generated unitormiy from the incide o: unit-radiu: crcle tnatI + otherrtaeJsjt")Ezumate the dixrbution ot R :=VITT= approximately 1.0OO ~imulated obzervaton:Monte Cark stuc; wn
Let (n be generated unitormiy from the incide o: unit-radiu: crcle tnat I + otherrtae Jsjt") Ezumate the dixrbution ot R :=VITT= approximately 1.0OO ~imulated obzervaton: Monte Cark stuc; wn...
1 answers
A lab sample of gas is taken through cycle $a b c a$ shown in the $p-V$ diagram of Fig. $18-43 .$ The net work done is $+1.2 \mathrm{J}$ . Along path $a b,$ the change in the internal energy is $+3.0 \mathrm{J}$ and the magnitude of the work done is 5.0 $\mathrm{J}$ . Along path $c a,$ the energy transferred to the gas as heat is $+2.5$ J. How much energy is transferred as heat along (a) path $a b$ and (b) path $b c ?$
A lab sample of gas is taken through cycle $a b c a$ shown in the $p-V$ diagram of Fig. $18-43 .$ The net work done is $+1.2 \mathrm{J}$ . Along path $a b,$ the change in the internal energy is $+3.0 \mathrm{J}$ and the magnitude of the work done is 5.0 $\mathrm{J}$ . Along path $c a,$ the energy tr...
5 answers
The de Broglie wavelength of a 6.0 gram bullet traveling at the speed of sound is sound is 331 mlsec. a. 3.3 * 10-34 m 6.3.35 * 10-33 _ m c2.7* 10-37 m d.6.6 x 10-31 m e. 2.7 * 10-34 mThe speed of
The de Broglie wavelength of a 6.0 gram bullet traveling at the speed of sound is sound is 331 mlsec. a. 3.3 * 10-34 m 6.3.35 * 10-33 _ m c2.7* 10-37 m d.6.6 x 10-31 m e. 2.7 * 10-34 m The speed of...

-- 0.020983--