5

Question 19Write the equation in standard form and find the center of this conic section: 1Ox? + 4y + 80x + 16y+ 136 = 0.a)(-2,_4)b) 0 (-8,_4)(-4,-2)(8,4)(4,2)f)Non...

Question

Question 19Write the equation in standard form and find the center of this conic section: 1Ox? + 4y + 80x + 16y+ 136 = 0.a)(-2,_4)b) 0 (-8,_4)(-4,-2)(8,4)(4,2)f)None of these.

Question 19 Write the equation in standard form and find the center of this conic section: 1Ox? + 4y + 80x + 16y+ 136 = 0. a) (-2,_4) b) 0 (-8,_4) (-4,-2) (8,4) (4,2) f) None of these.



Answers

(a) find the standard form of the equation of the ellipse, (b) find the center, vertices, foci, and eccentricity of the ellipse, and (c) sketch the ellipse. Use a graphing utility to verify your graph. $$12 x^{2}+20 y^{2}-12 x+40 y-37=0$$

So let's look at a problem again for funding the equation of Ah Hyperba left. Let's say I gave you this information. I tell you that the center of the hyper Gullah is at one negative three now, knowing thesis, enter. I have a lot of information to write the equation for the hyperbole, but I wouldn't know whether this is oriented up, down or left right. So let's say I gave you a couple other pieces of information. I tell you that a squared is four, and I tell you that B squared is 16. Naturally, we know from that that they would be, too, and we would know that B is equal to four. We could use our A squared plus B squared equals C squared to find the location of the folks I. But we want to write the equation for Hyperba from this information in standard form. Now let's look at something if I go to one negative three and I know that that's the center, which again is not actually on the hyper blood, but it's centered at the 0.1 negative three, and if I know A is to and I know B is four. I still don't have enough information to know whether this hyperbole a is gonna open up, down or left right? If someone told me that the transfers access Waas vertical, then I would know that I would go up two units and down two units to get to my Vergis is if someone told me that my transfers access waas horizontal, then I would know that I would move to units to the left and two units to the right of the center. So at this point, I don't know whether I have an equation that's in this form whips. That should be an age. And this one would open. Excuse me, left and right, or whether I have it in this form, I don't know. So with the information that I'm given, I can't tell the orientation of this particular Hyperba. So there's more than one answer. So let's fill in the two possibilities for our set up. Now let's say that the A happened to end up being set up where I had a horizontal transfers access and that I had avert Asi two units to the left and two units to the right, which I just in the opposite order. But if I had a horizontal transfers access, then this would be my equation. And I would write the equation as X minus one quantity squared over, and I'm already given a squared. So I would put the four here minus why minus negative three, which would become plus three over and we were given the B squared to be 16 equals one, So that would be one equation. And again, that would be the equation for the hyperba that would open left and right. However, I don't know that that's what's happening. So the other equation could end up being the Y minus again, the negative threes of plus three over and then the a squared would end up being four minus and then x minus H that's X minus one quantity squared over, and then the B squared was given to us in 16 equals one. And this could also be another alternative for the answer. Now this hyper block, the second one that I just showed would have the up to and down to, and I would have Vergis is here and here, and it would orient it up and down, but from this information, we can't tell which one is true. So both are viable answers for our particular setting. So there are two answers for that.

So our equation we can see is going to end up being a parabola and I'm going to put the hopes and that's why. And I'm going to put the X terms and the constant term on the opposite side. So this is what we would have now. Let's complete the square. So if we take half of that term, Half of that term is four and square, we would like there to be a 16 here, which means we have to add 16 to both sides. So we have why? Plus four quantity squared is equal to and these cancel out is equal to four X. Now that could be and you may even want to avoid it as X parentheses here minus zero all. So some text will have say that's their standard form uh the way I have taught my students is to solve for X. But again, that's going to depend on what your professor is having you do. And so we have this is a problem. And the problem is going to open to the right and it has a senator of vertex, the vertex is at the 0.0 and negative four. So zero and negative four is right here. And it's going to open as I said to the right because of this being a positive coefficient and this coefficient we call a and 1/4 C or C as the distance to the direct tricks. And the focus means that 1/4 is equal to 1/4 C. So C must be one. So to get to the focus, the focus would be right here, one unit over, so that focus would actually be at the 10.1 and negative four. That's for our focus, And our direct tricks is going to be one unit over, and it's going to be this line at X equals negative one, and it's going to open outwards like that. Yeah.

Okay. So, again, I need to go ahead and set this up for completing the square in order to figure out what shape on dealing with. So I'm gonna go ahead and write it down with my exes together and my wise together, so I'm already ready to do that. So X squared minus two x is gonna be the first part. Uh, plus, I have negative for why Squared minus eight. Why? That'll need something at the end of it, and then that equals seven. Now, I can't have this negative for in here, so I'll go ahead and simplify it a little bit farther. I'll take out a negative four and I've got y squared. Plus two. Why equal seven. All right, So what I need to figure out is how I will complete each square. And as usual, I look at b I half it and square it. So be Haft is negative. One square, that is one. So I'm out on one. I'm also gonna add that on the right to balance the equation here. I'm gonna look at the 2/2 it. That's one. Square it at it. But really what I did is I added negative four. So I'll do that. Over here is well, I factor each side or each try no meals, So X minus one squared, minus four. Why? Plus one squared equals four. And I always want this right side to equal one. So I'll go ahead and divide everything by four. In which case I'm looking at X minus one quantity squared over four minus. Why, plus one quantity squared over one equals one. Okay, so that is my equation. And this tells me it's a hyper Bella. I also know that this value is gonna be a squared. This value is going to be B squared. So I'm gonna go ahead and find the center by looking at the equation. I look for H and K. So H k the center is one negative one because I get that from each part of the equation here, it's always X minus H. Why minus case. So I'm gonna pull those in that way. And then I know that for a hyper Bella, I use the Pythagorean theorem. So a squared plus B squared equals C squared four plus one equals C squared. See will equal Route five and I'm gonna add that route five value onto the center and subtracted from the center in order to find my folks. I Since this hyper Bella is the x shaped hyper Bella, I know that the folks I will go left to right. It's left to right. So I'm gonna go ahead and add it to the ex portion of the center. So folks, I won will be one plus Route five Common negative one. Since it needs to stay at the same height. And folks, I, too will be at one minus Route five. Negative one. So here is my center. And here are my foes I for this hyper Bella equation, Yeah.

We need to complete the square in order to find the equation of the circle in standard form, identify the center and radius. And if we can't we need to explain why. So we move things around so we have four X squared. There is no other x squared. Police in space plus four, Y squared minus 24. Y. Leave some space equals negative 36 because we move it over. So this becomes just four X squared. We pull out of four here, we get y squared minus six. Y Equals -36. So we take the middle term negative six, divided by two square. It put it here, so that's plus nine. But we're really adding 36 because that's getting multiplied to the four on the outside. So plus 36. So this equation becomes four times X squared plus four times. Why minus three squared is equal to zero? And then we divide everything by four. We get X squared plus why minus three squared is equal to zero. This can't be a circle because we have no radius. We can't have a radius of zero and have a circle.


Similar Solved Questions

5 answers
SCrcltb 4Touui 5400 Erand Tntn Lta toccd al ZoaNVI 503tIcoelin (Houn] Yola to"ooiaintmltuleeeJonNood Help?Subm Anaas4r ProzutRecoe Acthd VezorBEAcETe4ToDunnaLummer Tontti Ter Mjlei Trjcl neciLe Juerugr detteae [a 09 Pfr Duy detan Intion (pice Ir3n'neclates 'orrtateincrrated thabyaWilumingricilor' nenulacSukNeod Help?HeanUnctun6 D0 %4Lemaleta
SCrcltb 4Touui 5400 Erand Tntn Lta toccd al ZoaNVI 503tIcoelin (Houn] Yola to" ooiaint mltule eeJon Nood Help? Subm Anaa s4r Prozut Recoe Acthd Vezor BEAcETe4To Dunna Lummer Tontti Ter Mjlei Trjcl neciLe Juerugr detteae [a 09 Pfr Duy detan Intion (pice Ir3n 'neclates 'or rtate incrrat...
4 answers
Sir? Kre Iimnic, 1? I: eulabs _ X . 1+ X2 . 6x+ 5Doai not exIstDI -
sir? Kre Iimnic, 1? I: eulabs _ X . 1+ X2 . 6x+ 5 Doai not exIst DI -...
5 answers
Please draw the Lews structures for the fallowing molecules 4s well As answer G lna the rnissing inforination the Poxes Below (Opbs/bpts exch)SO;.Electronic Shape Mokcula Shap: Polar Ot Non-= -pohar Rssonance PossibleIfyss show [Sonancc structurXeF _
Please draw the Lews structures for the fallowing molecules 4s well As answer G lna the rnissing inforination the Poxes Below (Opbs/bpts exch) SO;. Electronic Shape Mokcula Shap: Polar Ot Non-= -pohar Rssonance Possible Ifyss show [Sonancc structur XeF _...
5 answers
9.U.w' ` (2wp dnm+m2.e(4+2e(4) Sdue 4he Jiffecential equaion U ! Onaki detei (
9.U.w' ` (2 wp dn m+m2.e(4+2e(4) Sdue 4he Jiffecential equaion U ! Onaki detei (...
5 answers
Using the following balanced equation: 3A AzB44BCalculate how many moles of AzB4 can be formed from 76.7 moles of A
Using the following balanced equation: 3A AzB4 4B Calculate how many moles of AzB4 can be formed from 76.7 moles of A...
5 answers
An oscillator with period 2.6 ms passes through equilibrium at t = 16.6 ms with velocity V = -3.4 m/s. The equation of the oscillator's motion is xlt) cm cos ( Is ) t
An oscillator with period 2.6 ms passes through equilibrium at t = 16.6 ms with velocity V = -3.4 m/s. The equation of the oscillator's motion is xlt) cm cos ( Is ) t...
5 answers
Maoh 2Ha (29)OCH;HoOCH;OCH,OCH}
Maoh 2Ha (29) OCH; Ho OCH; OCH, OCH}...
5 answers
Also find the positive root, using a=5,b-6, es = 0.5% (2 sig fig accuracy):
Also find the positive root, using a=5,b-6, es = 0.5% (2 sig fig accuracy):...
5 answers
(a) Find the total transition rate associated with the decay of a harmonic oscillator, of charge $q$ and mass $m$, from the $n$ th excited state to the state just below.
(a) Find the total transition rate associated with the decay of a harmonic oscillator, of charge $q$ and mass $m$, from the $n$ th excited state to the state just below....
5 answers
MYNOIESASkYOuR TEACHERetnedon Vyeu sell € number of coquodeJullrool Fato}UCI TCTAnrufit
MYNOIES ASkYOuR TEACHER etne don Vyeu sell € number of coquode Jullrool Fato} UCI TCTA nrufit...
5 answers
A gene in a malignant cell is expressedA gene in a normal cell directs the synthesis of growth-promoting protein.A gene in a normal cell begins to overexpress protein.A gene in a normal cell becomes capable of causing cancer:Agene in # malignant cell overexpresses & protcinIDON'TKNOW YET
A gene in a malignant cell is expressed A gene in a normal cell directs the synthesis of growth-promoting protein. A gene in a normal cell begins to overexpress protein. A gene in a normal cell becomes capable of causing cancer: Agene in # malignant cell overexpresses & protcin IDON'TKNOW Y...
5 answers
FerteneanuntinsLd Dois uceyrtMajootnNrupJut eridk tbk Ind Up4tdTelgiiilecioeeSalctune opijn Irom balow Vheranahororpleedmali on guch It of tht stornKthteronMocthin Og Veci Eitini Faecere Jojco Kom DatuhirRnuning Lconipuired:
Ferten eanuntins Ld Dois uceyrt Majootn Nrup Jut eridk tbk Ind Up4td Telgiiilecioee Salctune opijn Irom balow Vheran ahoror pleed mali on guch It of tht storn Kthteron Mocthin Og Veci Eitini Faecere Jojco Kom Datuhir Rnuning Lconi puired:...
5 answers
Emoticons The website www.gamefaqs.com asked, as their question of the day to which visitors to the site were invited to respond, “Do you ever use emoticons when you type online?” Of the 87,262 respondents, 27% said that they did not use emoticons. ;-(a) What kind of sample was this?b) How much confidence would you place in using 27% as an estimate of the fraction of people who useemoticons?
Emoticons The website www.gamefaqs.com asked, as their question of the day to which visitors to the site were invited to respond, “Do you ever use emoticons when you type online?” Of the 87,262 respondents, 27% said that they did not use emoticons. ;-( a) What kind of sample was this? b) How m...
5 answers
KyuhlhlphmisuDieMAISIIPREMICIUS ANSWERSSCAFind the area of the shaded regioni 3 sin(0)|411 8
Kyuhlhlphmisu DieMAISI IPREMICIUS ANSWERS SCA Find the area of the shaded regioni 3 sin(0)| 411 8...
5 answers
Wich of tle mnetal lithium. hf; = 23eV silver. hf; = A7eV cesium hft = 2M4eV will exhibit the photoelectric effect whcu light with frequency o 6.3 10" 'Hz quency 15 shone on it? Plauck' Constant 6.63 10-* J -s ,None of theselit hiumesiumlit hium auc] silversilver
Wich of tle mnetal lithium. hf; = 23eV silver. hf; = A7eV cesium hft = 2M4eV will exhibit the photoelectric effect whcu light with frequency o 6.3 10" 'Hz quency 15 shone on it? Plauck' Constant 6.63 10-* J -s , None of these lit hium esium lit hium auc] silver silver...
5 answers
21 If there is & current in the loop in the direction shown, the loop will:move downboth rotate and movemove Uprotate counterclockwiiserotatc clockwisc
21 If there is & current in the loop in the direction shown, the loop will: move down both rotate and move move Up rotate counterclockwiise rotatc clockwisc...
5 answers
Pints) Calculate AH? for the following reaction given the following AH?; values:2 NHs(g) 45.93 Oz(g)2 CHA(g) ~74.872 HCN(g) 1356 HO(g) 241826AH' (kmol)
pints) Calculate AH? for the following reaction given the following AH?; values: 2 NHs(g) 45.9 3 Oz(g) 2 CHA(g) ~74.87 2 HCN(g) 135 6 HO(g) 241826 AH' (kmol)...
5 answers
Use the method of variation of parameters t0 determine particular solution to the given equation:400y" tan (20x), 0<x< 40Yp (x) = Simplify your answer: Use parentheses to clearly denote the argument of each function )
Use the method of variation of parameters t0 determine particular solution to the given equation: 400y" tan (20x), 0<x< 40 Yp (x) = Simplify your answer: Use parentheses to clearly denote the argument of each function )...

-- 0.066073--