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A 5 m", constant pressure piston-cylinder device filled with 11.23 kg oxygcn whose tcmperature 27 %C This oxygen now heatcd until its volume Is How much Kork p...

Question

A 5 m", constant pressure piston-cylinder device filled with 11.23 kg oxygcn whose tcmperature 27 %C This oxygen now heatcd until its volume Is How much Kork produced by tne Oxygen during this process ~30ORJ 350*J JS0UJ JodkJQuesTion5 m" , constant pressurc piston-cylinder device filled wlth 11.23 kg of oxygen whose tcmpcrature 27 %C. Thls oxygcn nor heatcd until Its Volumc How much heat transferred into the oxygen?M10kJKg M10kJkg 80 kUkG B0 kJkgHoctono MhlrIcSortHehan

A 5 m", constant pressure piston-cylinder device filled with 11.23 kg oxygcn whose tcmperature 27 %C This oxygen now heatcd until its volume Is How much Kork produced by tne Oxygen during this process ~30ORJ 350*J JS0UJ JodkJ QuesTion 5 m" , constant pressurc piston-cylinder device filled wlth 11.23 kg of oxygen whose tcmpcrature 27 %C. Thls oxygcn nor heatcd until Its Volumc How much heat transferred into the oxygen? M10kJKg M10kJkg 80 kUkG B0 kJkg Hoctono MhlrIc Sort He han



Answers

A tank of volume 590 liters contains oxygen at $20^{\circ} \mathrm{C}$ and $5.0$ atm pressure. Calculate the mass of oxygen in the tank. $M=32$ $\mathrm{kg} / \mathrm{kmol}$ for oxygen. Use $P V=(m / M) R T$ to get $$ m=\frac{P V M}{R T}=\frac{\left(5 \times 1.01 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}\right)\left(0.59 \mathrm{~m}^{3}\right)(32 \mathrm{~kg} / \mathrm{kmol})}{(8314 \mathrm{~J} / \mathrm{kmol} \cdot \mathrm{K})(293 \mathrm{~K})}=3.9 \mathrm{~kg} $$

Well, And this problem, we have pure oxygen heated to heated from 77 f thio at one atmosphere to, um 5300 f in a constant volume process. Now, um, and again, we can find the natural log of K for this to be zero uh, minus 3.7 And so now we have because we have constant volume process, not a constant flow study flow process. We have you to equals u one u two minus t. One is now that you transfer, um, and then we can convert, you know, convert you you internal energy into anti peace and pressures and specific volumes. So, um, again using ideal gas to convert these two temperatures. And again, we have to be careful about the mole. Fraction of of the gas is we have and are is constant here because it's, uh per killam. Also, that can be taken out. And then we just have the change in entropy. Um, after perturbation, we have this much we have. Um Well, after perturbation, we have a total of one plus X, um, units of gas. We know the pressure ratio is this. Ah. And so then we can Ah, convert that. Let's see here what we're doing here, then we know the, um, pressure. Is that so? Then then we have we wind up with, um Oh, yeah. I just put plug these into here. That's what I did. Tau e. Guess this should be. Well, p one is peanut, its atmospheric, so we can leave that alone. So here's the mole fraction of oxygen and the mole fraction amount atomic oxygen. And so we can plug into our equilibrium, um, equilibrium equation, and we get Here's the mole fraction of, um, squared of the Mont atomic oxygen and one over the mole fraction of the, uh, oxygen molecules. And then we can instead of having the pressure Asia, which is, uh, raised the first power. We can use this relationship here and get this in terms of temperature. And now, um, we got a Let's see here, we're gonna have a cubic, so we're gonna have to do some route finding and we wind up with X equals 0.3 to 4, which means we have this much oxygen this much amount atomic oxygen on this many total moles of things in the products And now we can again go through and calculate. Go back up to here and look at the heat transfer and we get, um, just these Look up the answer apiece. Calculate those and we wind up getting about 4th 42,000. Speaking of purple, Mom and let's see, here we have a mole fraction of oxygen as 0.937 and of Amman atomic oxygen of 0.6 to 8. So what do we have? We had this problem before, so let's go back here. Before, when it was constant flow process, steady flow process. We had 62,300 and now we have 42,000. So we have If we have to keep a constant volume, we need thio change the put in less heat to get to this temperature.

In this question were given that we have one mole of oxygen gas. The initial temperature of the gas is 17° years. Yes, This gas is added vertically compressed so that its final pressure becomes 10 times the initial pressure. So we have to calculate what is the temperature of this gas system After the compression in second part, where to calculate what is the work done on the gas due to this compression? So let's no doubt the given data. First the initial temperature of the system that I'm writing is T. I. That is given to us 17° integrated In Kelvin. That will be equal to 2 90 Kelvin. The if initial pressure they didn't say Be in the final pressure of the system becomes 10 times B. We have to find the final temperature T. F equals how much in first part. So to answer the first part, we use uh the equation, the ideal gas situation basically. As the gas is accomplished, add A. Politically. So we can just write that B to the power one minus gamma into T. To the power gamma is constant because this is following the diabetic uh process of a gas. This is the equation of state. We can right so now from here we can just write that T. To the power gamma is equal to some constant by P to the power one minus gamma. We can also be written has some constant times P to the power gamma minus one. So then we can just write from here, the T to the power gamma is going to be called to P to the power gamma minus one by gamma. Sorry this is equal to T. Are then this multiple away some constant. Now from this equation, you can just write that T. One by A T. I by T. F. Is equal to B. I by B F. Or to the power gamma minus one by gamma. So from here we can also write that the final temperature of the gas system is going to be called initial temperature times P. F by P. I hold to depart gamma minus one day grandma. Now let's put the values of these datas. So TF it we call to the I the initial temperature is 2 90 k to 90 kelvin multiplied where you find the pressure is 10 times initial process while I think this is N. P by P. All to the bar gamma. Now as oxygen is a diatonic molecule, so four or two for oxygen gamma is equal to 1.4 that we already know. So this will be 1.4 -1 by 1.4. So Simplifying this, we will get the final temperature of the gas as 560 Kelvin which will be 5.6 into 10 for two Kelvin. This is the record answer for the first part of the question. Now for the second part of this question, we have to find the work done on the gas in this, a diabetic compression process. So we can just right for and diabetic compression process. We can just write that. The work done is equal to our by gamma minus one times T I t. Uh T I minus t F. There's a formula for world learning the identity process. Now let's put the values of this constant. So our is 8.3. Uh S a unit developed by gamma is 1.4 minus one minus one. Multiplied by the initial temperature is 2 90 Calvin minus final the british 5 60 K 11. So by simplifying this, we will be getting the work done as minus 5.6 into 10 power three Joel. So if this is the work done and we can see that this Walden is negative. So about these negatives and I'll write one statement on one sentence that uh the negatives and indicates the negative sign indicates that the work is getting done on this system on the system. So this is the answer for this question.

So we have oxygen gas which has an initial volume off helps. And Centimeter Cube. I can't picture off 40 degree Celsius. His pull 73. It's party, Kevin, which is 313. Okay, No, we hospital that the pressure was 1.1 times 10 part of baskets This expanded too. Volume off 1500. Let me take you pressure. She and the pressure changed to one point. There was six times five askance. We want to find the temperature. No, Obviously we'll use our ideal gas formula. E v equals no notice that it is a constant always on the end. Here is a constant because it's the same oxygen gas that has changed its volume on pressure. But the constant you and cast that is the number of molecules. The amount of gas hasn't changed, which means any is a constant. So in our as a whole is a constant. So rearranging this formula, we can see that an arc is PB biking. No, because an ID is a constant pp by tease a constant. So even we won by t one that is pee pee by tea. For this is the first case is equal to P V by key for the second case. Do we do by? He do and that's it. Using this, we confined our TV so we can re arranging this formula. We can see that Tito is equal to do we do by people. Everyone times people. I'm busy. It's not your numbers, no PTO. There's 1.6 times. Mito is 1500 centimeter cube people is one points. It'll untie skin off our passports. Way we want is 1000 centimeter. You and Cuba is 313. Okay, that's it. Noticed that Haskell's cancel the unit on the sentiment. A Cuban. It's cancel giving us himself Kelvin, which is exactly what we need for our temperature on Tito. When you plant these next calculator, don't talk to me. 493. That is a Remember that 4 93 Calloway is 4 93 minus 2 73 Big researches. What's Constable? 220 Bigness? Socialise. It's simple as that

Fold that initially your oxygen gas has a volume off thousands of David Q. A pressure off 1.1 times 10 part of five Paschal, a temperature of 40 degrees Celsius, which is 40 sports on TV. So that's 313.15 him. We want to find the number off morals in this guess. So use that question. PV called you and Artie. They simply need to find him. So n is PV by party on that is it. He is 1.1 in a fight. We is 1000 times a centimeter, Cuba's and our minus three meter cube. I'm just gonna put in my six me take you. So that's £10 minus six you wanted by R. R is 8.31 for Joe Lieberman. Kellman Remember that the year itself pressure is Paschal, which is Newton per meter square. And then it's a volume is meter Cuban now and and the temperature is 313.15 Kelvin so we can cancel Kelvin's. We can cancel meter square with me to Cuba to give us a meter. And remember that Newton meter is a Jules, so we can cancel you. And we're left with a mole, which is exactly the unity. And until the end is 3.88 I'm Stan Bar minus two. Moles be will use this information to find out the temperature. Not again using peopIe Quito. Addie, we know that the pressure is 1.6 times in butter. I ask us, huh, Temperature? I'm sorry. While you miss 1500 centimeter cubes. Unless 1500 perhaps 10 5 minus six MIT acute. So rearranging this formula, you can see the tea is PV by an r. So that's 1.6 times to clarify Paschal's, which is Newton permitted. Square. We is 1 1500 times. Tend bar six, temper minus six. Meet a cube and is 3.88 times tends bar temper minus two Moles value off. Our is 8.314 Julie, our mole Kill him so we can cancel more meter, square and meter cube canceled. Gives a meter. A neutral meter is a jewel, so we have left with the inns of killing. So this uses 4 93 Kelvin, is it notice that I have three significant digits because all of our numbers have it most. Three significant agents


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