Well, And this problem, we have pure oxygen heated to heated from 77 f thio at one atmosphere to, um 5300 f in a constant volume process. Now, um, and again, we can find the natural log of K for this to be zero uh, minus 3.7 And so now we have because we have constant volume process, not a constant flow study flow process. We have you to equals u one u two minus t. One is now that you transfer, um, and then we can convert, you know, convert you you internal energy into anti peace and pressures and specific volumes. So, um, again using ideal gas to convert these two temperatures. And again, we have to be careful about the mole. Fraction of of the gas is we have and are is constant here because it's, uh per killam. Also, that can be taken out. And then we just have the change in entropy. Um, after perturbation, we have this much we have. Um Well, after perturbation, we have a total of one plus X, um, units of gas. We know the pressure ratio is this. Ah. And so then we can Ah, convert that. Let's see here what we're doing here, then we know the, um, pressure. Is that so? Then then we have we wind up with, um Oh, yeah. I just put plug these into here. That's what I did. Tau e. Guess this should be. Well, p one is peanut, its atmospheric, so we can leave that alone. So here's the mole fraction of oxygen and the mole fraction amount atomic oxygen. And so we can plug into our equilibrium, um, equilibrium equation, and we get Here's the mole fraction of, um, squared of the Mont atomic oxygen and one over the mole fraction of the, uh, oxygen molecules. And then we can instead of having the pressure Asia, which is, uh, raised the first power. We can use this relationship here and get this in terms of temperature. And now, um, we got a Let's see here, we're gonna have a cubic, so we're gonna have to do some route finding and we wind up with X equals 0.3 to 4, which means we have this much oxygen this much amount atomic oxygen on this many total moles of things in the products And now we can again go through and calculate. Go back up to here and look at the heat transfer and we get, um, just these Look up the answer apiece. Calculate those and we wind up getting about 4th 42,000. Speaking of purple, Mom and let's see, here we have a mole fraction of oxygen as 0.937 and of Amman atomic oxygen of 0.6 to 8. So what do we have? We had this problem before, so let's go back here. Before, when it was constant flow process, steady flow process. We had 62,300 and now we have 42,000. So we have If we have to keep a constant volume, we need thio change the put in less heat to get to this temperature.