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Click the "draw structure button (0 lauuch (he drawing utility: Draw the product of the reaction.draw structureBrz...

Question

Click the "draw structure button (0 lauuch (he drawing utility: Draw the product of the reaction.draw structureBrz

Click the "draw structure button (0 lauuch (he drawing utility: Draw the product of the reaction. draw structure Brz



Answers

Draw the structure of compounds A-E in the following reaction scheme.

This question asked us to drop the structures of the products obtained from this reaction. So here we have a tertiary leaving group with iodine right here and a weak base. Weak nuclear file with the method. Also, we're gonna have an S and one or e one reaction eso for sn one products. I'm going to copy the structure. It was really hard to draw. We have two different possibilities here since s and one goes through a cargo cat. I and we can either have the stereo chemistry, stay the same. Which would look like this where we just replaced the the iodine in the same position with the meth Oxy group. Or we have hysteria, chemistry, flip which would look like this so that we have to an anti MERS possible for this s and one product. And then for e one, I'm gonna draw like this cause it's just a little bit more accurate. We also have two possible products for the E one reaction. So we can either have the iodine eliminate this direction or to this direction. Um, either one is going to we'll get we'll get about the same amount for either one because they're both equally substituted. We will not hell over go up onto the method, the muffled group. Because that will not be very substituted. So are medical group is right here on this structure. So we can either have the double bond up here or down here. There are two e one products.

This problem asked us to draw the mechanism of this reaction. So to start off, we'll have our We are Teoh. Um, one of these pi bonds will come and attack the bro. Mean? And then, um, the bombing will also attack one of the carbons and will kick off that second, bro. Mean So we'll have a intermediate that looks like this. And we only have one pibe on there, and then we have the bro mean here, and it's positive. We also have a negative roaming left over the next step. Um, now we're going to attack with a nuclear file. But because we have water in this reaction water, is it better nuclear file than a negative bromide ion? So that's gonna be our nuclear file. Water is gonna come in and attack the more substituted carbon from the opposite side that the, uh, bro mean triangle situation is on, and that will push to blow me off of that one. We will end up with an intermediate that looks like this. We'll have water up here. Um, and it is still positive the bromate will be down here and then we have to take that proton off of the water. That will probably happen from another molecule. Water coming in and taking it like this and we'll get another intermediate. That looks like this. So we have our O h up here in an e in all with the broom ing on it. This is an eternal right here because we have the alcohol on the l Keen. And this will to Tom arise into the key tone that we see in the product. So that is the mechanism.

Yes. Mhm. Yes. We have to draw a structural formula for the activated complex for the given reaction. Mhm. Mhm. Mhm. Nitrogen dioxide, no two reacts with nitrogen dioxide in three to build. Mhm. I wasn't born outside you know and you know to and auto let us first draw yes structural formula of each reactant and product. Yes. So. Yes. Mhm. Yeah. Mhm. Yeah. Mhm. Yes. Sorry. Mhm. Yes. Yeah. Yes. According to our chinese theory above the action can take place only when we attend N. 02 and three collide to form unstable interviewed. Which is called activated complex. So during the collision this you know born and this you know born breaks up and a newborn start forming between these two elements. So structural formula for activated complex. Mhm. Has given. Mhm. Below this a newborn brakes and this in a bond also start to break and a newborn form. Yeah. Between box season. I can't this is the required answer for the given problem. Yes.

Problem. 22 were asked to react this molecule with two pro panel. Okay, so this molecule asked. You could see as a carb oxalic acid. And whenever we, um we are car book Selic acid with an alcohol, we get a nester, Okay. And I want to start with just droving that alcohol group that we're gonna need. Okay, so we have pro panel, meaning we have three carbons, right? And then just two pro panel. So to pro bono, meaning our over each group is on our second carbon. Okay, so this is our old age group right here. And all this love is to fill out those carbons with the missing hydrogen. So Okay, this first carbon could handle three. This middle Carbon could only handle one now. And this terminal carbon could handle three marker. So that's our proposal to a pro panel. And now we have to react these in order to make a nester kit. So what I want to do is, um, convert this molecular model into a condensed structure, okay. And then we go ahead and combine it with the, um, to pro panel that we drew. Okay, So, um, let's count our carbons real quick, too. Three for fun. Okay, so we have five carbons, So wanna go ahead and draw those five carbons? 123 45 And carbon one has three hydrogen sze, right? 123 So I want to go and puts the age three on this 1st 1st carbon. Okay, so she h three and the next we got C h. We'll worry about that ocular group leader Third carbon has one hydrogen and then the fourth carbon has to And finally, our fist carbon here has the oxygen's. Okay, Okay, so now let's go and add our, um, alcohol groups. So there's there's a ch three year with carbon too two each three, and then we have another CH tree right here on carbon three. So I'll just put it up because we're missing. Or were We're running out of space below this carbon. Okay, Okay. So now we have the condensed structure version of our molecular model. And again we are reacting this car book Selic acid with this alcohol. OK, so what's gonna happen here is we're going to lose that hydrogen, so we're gonna lose this harder, Jen, Okay. And we're Also, we're also gonna lose this alcohol, Okay? And then this carbon is going to be connected. Two to this oxygen. Okay, so this this is the carbon that originally had that alcohol group connected. So as you could see, it has ch. Okay. And it has ch three on either side. Okay, so we got ch three on either side. God. See? See, trying to copy the colors as well to make it clear. Okay. All right. So, um ah, So you probably know this because this alcohol group is on top. We had to rotate kind of rotate this molecule to make it sideways, and it's going to connect to this this part of the molecule. Okay, so do you have it? That's that's our, um, product after the reaction.


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