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(Tkrn from Hughcs-Hallctt, al) A Linne "tldy Ilerr i! ix thrrwn uPin the It , tomalo @el @ heighe of f() ~1.02 +25t mern. What is thc #VITAgc velocity c the to...

Question

(Tkrn from Hughcs-Hallctt, al) A Linne "tldy Ilerr i! ix thrrwn uPin the It , tomalo @el @ heighe of f() ~1.02 +25t mern. What is thc #VITAgc velocity c the tomato during tlu: lint 2 sxxnd? Civa units:() Fincl thc: insEALIIE ATE (lIS vuknity etlu tulu2 (iv uuil ,WhntHax high

(Tkrn from Hughcs-Hallctt, al) A Linne "tldy Ilerr i! ix thrrwn uPin the It , tomalo @el @ heighe of f() ~1.02 +25t mern. What is thc #VITAgc velocity c the tomato during tlu: lint 2 sxxnd? Civa units: () Fincl thc: insEALIIE ATE (lIS vuknity etlu tulu 2 (iv uuil , Whnt Hax high



Answers

The clcctronic configurarions of four clemcnts arc givcn as undcr: (I) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$ (II) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$ (III) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}$ (IV) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6 \mathrm{i}} 3 \mathrm{~s}^{2} 3 \mathrm{p}^{1}$ Which of rhe following arrangemcnts gives thc corrcct ordcr in rerms of increasing clectroncgariviry of the clcments? (a) $\mathrm{III}<\mathrm{II}<\mathrm{IV}<\mathrm{I}$ (b) $\mathrm{II}>\mathrm{III}>\mathrm{I}>\mathrm{TV}$ (c) $\mathrm{IV}<\mathrm{III}<\Pi<\mathrm{I}$ (d) $I<$ II $<I I I<\Pi V$

Well the question is sodium. I drove. I dropped sleep. I think I grow a score pick absorb moisture when exposed to the atmosphere. I student placed a quarter of anyway. On the last a few years later, he noticed that the color was covered. A white solid, identify the white solid. We need to identify, identify divide solid. So sodium hydroxide as we know this is hi gyroscopic material. This is the hydra skah pick compound which absorbs the moisture then exposed to the atmosphere so we can write a. It wasn't to any elect less. C. 02 the atmosphere atmosphere. This will give who Here to see you three less Will not give care to 03 since it is too anyway. So it will give between you U. N. O. H. Plus your two will give an A. To C. +03 which is solid. So this is what which looks like a white solid. Yeah, we can see that. Hobson. She is correct. And to see you.

Mm. Hi, welcome to question number 42. In this question, you want to know if we have 25 micrograms of c. 21 age, 30 oh two, We want to know how many moles that is and then how many molecules that represents. So to do this, we are going to need the molar mass of this substance. So we're going to add 21 carbons to the molar mass of 30 hydrogen to the molar mass of two oxygen and I get 314 0.45 So the Mueller mass 3 14 0.45 Of course that would be grams per mole. Right, So I'm going to use this information set up a little bit of dimensional analysis here. First thing I need to do is to get my micrograms two g. So I know that there are one times 10 to the sixth micrograms of anything in one g. Now I can use my molar mass. So there are 314.45 g of C. 21. Age 30 oh two in every mole of the substance. Mhm. Notice I put the grams in the denominator so that they will cancel. So the only unit I have remaining now is moles. So I can go ahead and calculate my answer here. And I'm going to round it to two significant figures since 25 only had two and I get eight point oh times 10 to the negative eighth of the C. 21. Age 30 oh two. Okay, the next thing I want to do then, so let me circle that. That is our first answer. That is the number of moles. Eight times 10 to the negative eight moles. Next thing we want to do is figure out how many molecules this is. So starting with my number of moles eight times 10 to the negative eight moles of C. 21 H 30 02 We need to use of God Rose number because we know there are avocados number of particles in one mole of anything. So six point oh 22 times 10 to the 23rd. That is avocados number. Okay, molecules of the C 21 H 30 02 in every mole of the C 21 H 30 02 What? All right, so mobile cancel and I get a number in number of molecules again rounding the two significant figures. I get 4.8 times 10 to the 16th molecules of C 21 age 30 oh two. So that is the answer to the second part of this question. Thank you so much for joining me.

The yellow frittered. The yellow, for return contains sodium roommate sodium chrome eight, obtained by up and by the oxidation obtained by the oxidation of cl teddy iron with sodium peroxide with sodium peroxide. So, according to the option of this problem, obstinacy each correct. Here. It is because the brown residue is of basic ferric sulfate, which is obtained by the oxidation of weather salted with sodium peroxide. So he had obstinacy each correct.

I'm writing the reaction which is really event to the micro's cosmic salt bead aged. So just look at it carefully and I think that taste the relieving reaction, then see, oh, we'll react with anne B or three, then the product form it. Any issue, be all four. And according to the problem, this is the answer. So option B is only got it answer for this problem.


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