Okay, so I bring all the information given us for this problem in black. So the first thing that we should do is we should calculate decay for this reaction at equilibrium. So in order to calculate K, we need the concentration of all of you reacted to the products. So you must do that first, right? Concentration is concentration is most divided by leaders, right? We have leaders, but we don't have most. Let's calculate most. So we see that mo's of PCL five is equal to 3.12 gram. Just how much we have divided by the molar mass. Right? So I've figured out the molar mass off all of these, and I've ruined them and read here. So we see that PCL five is to wait grams from Oh, all right, So we do that, we get point 015 most and Alice do most of PCL three. Tomoe of PCL three is equal to 3.845 grams, divided by the molar mass, which is 1 37 and we get plant 0 to 8 and then we go to most of of C L to get 1.787 divided by 71 which is 710.25 Most of those. So we figure out the most now we just got to find the concentration and we So we divide all of these most by the 10 leaders. Right here. We have concentration of PCL fa. Let me do you listen in different color, actually, you have concentration of p C. L five is equal to 0.15 moles divided by 10 leaders. We get playing 015 I m so m is my clarity. It's most of out of my leaders now we have concentration of PCL three is 0.28 most wanted by 10 liters Get put 028 now for C l two. We have 20.25 moles divided by 10 years and we get 100.25 and right, So we figure out all the concentration at equilibrium so we can use these concentrations are equally well to figure out Ok, right, so okay is equal to the concentration of the products over the concentration of the reactant. Right? So we have PCL agree times it by CEO too, over concentration of PCL five. All right, so we modified this the concentration on the same side. But we divide by the other side. So we plug in the concentrations that we found from the low. You see that PCL three is point 0 to 8. Really? That c l two is 20.25 and we see that P C 05 is 0.15 All right, put that into the calculator. Would get K two b go two point. 0 4/7 Now this K we can use to find the answer. So they tell us that we're adding 1.418 grams of seal, too into this equilibrium. So how would the eagle even be affected? Right. Well, if we were to add, we were increased CEO, too. Then the equilibrium was shift to the left. These will have more co two. So this more co two Well, uh, react with PCL dory to form or PCL five. Right? So the equilibrium was shift to the left. So, uh, they said that we add 1.418 grams of C l two and they want us to find the equilibrium concentration after we add it. So what we can do is figure out how many. What is the concentration of 1.418 grams of co? Two were much the same thing that we did in green and blue here. All right, so we have long points for 18 grams. We know that one mole of CO two is 71 grams Pramono, I'm gonna put ad right, and we get the answer as 0.0, to move. Now, let's calculate concentration. Well, we know that concentration. We have add concentration seal to to go to a 0.2 moles over the volume, which is 10 years, and we get 100.2 Right? So what is the total number of C l two? We have Well, we have, actually, I don't need this. Okay, so we add this concentration of C 02 to the already existing concentration. Right? So we know that at equilibrium making me a second I feel like So now we do do This is okay, So I c E o k. So we have 00.2 plus the concentration that we have right here just 0.25 and we get plenty 00 before five. So that is the concentration of CO two in our reaction. All right, so we have total concentration of co two. So we go up, we have we have points. Oh, for five for C E 03 We have 30.28 And for PCL five, we have 50.15 Right. So these are initial concentrations now. We gotta find the change in concentration. Well, we know that as your reaction proceeds, there will be so we know that the reaction shifts toe left. This means that Mawr PCL five will be forms we put plus X. We would from minus expert bolted these since all of these are 1 to 1 ratio in most. Right, So we have 111 Now we write the equilibrium expressions, we have 0.15 plus x, the plane. 0 to 8 minus X. And we have 0.0 for five minus x. This is a five here. Okay, so now we have decay that we calculated, right? And then we have these so we can use eso weaken, stop for accident. So we have from what we have 0.47 which is K. We have the same equally room expression, right? Well, we just have different values for concentration. Yes, we have t 0.0 to H minus X times it by 0.0 for five point. It's x 0.15 plus x eso. When we saw for X, we should get X to be equal 2.0, for eight. Now we use the X and the equilibrium expressions right here to find the equilibrium. Concentration. Right. So we have Let's see, for concentration of PCL five is equal to point a 15 plus X right. We know that X is equal 2.0 for eight. All right, so we get 0.198 as the concentration for PCL five PCL three We get 0.0 to H minus X. We know exes minus X. We know access 0.0 for eight, and we get 0.2 threes and then for CEO too. We have 0.0, 45 minutes X 450.0 for five minus 50.0! Four, eight Oh, it's playing 00 for eight for all of these. But the answers are correct. I 80.0 for eight, and we get point. Oh! 0402 Okay, Yeah. Okay, so these these are answers to this question.