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# How much work is required to lift a $1000-\mathrm{kg}$ satellite from the surface of the earth to an altitude of $2 \cdot 10^{6} \mathrm{m} ?$ The gravitational for...

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###### How much work is required to lift a $1000-\mathrm{kg}$ satellite from the surface of the earth to an altitude of $2 \cdot 10^{6} \mathrm{m} ?$ The gravitational force is $F=G M m / r^{2},$ where $M$ is the mass of the earth, $m$ is the mass of the satellite, and $r$ is the distance between them. The radius of the earth is $6.4 \cdot 10^{6} \mathrm{m},$ its mass is $6 \cdot 10^{24} \mathrm{kg},$ and in these units the gravitational constant, $G,$ is $6.67 \cdot 10^{-11}$

How much work is required to lift a $1000-\mathrm{kg}$ satellite from the surface of the earth to an altitude of $2 \cdot 10^{6} \mathrm{m} ?$ The gravitational force is $F=G M m / r^{2},$ where $M$ is the mass of the earth, $m$ is the mass of the satellite, and $r$ is the distance between them. The radius of the earth is $6.4 \cdot 10^{6} \mathrm{m},$ its mass is $6 \cdot 10^{24} \mathrm{kg},$ and in these units the gravitational constant, $G,$ is $6.67 \cdot 10^{-11}$

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