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A trigonal bipyramidal geometry exhibits two characteristic bond angles. Which bond angles are these?A.90°B.109.5°C.120°D.180°E.45°...

Question

A trigonal bipyramidal geometry exhibits two characteristic bond angles. Which bond angles are these?A.90°B.109.5°C.120°D.180°E.45°

A trigonal bipyramidal geometry exhibits two characteristic bond angles. Which bond angles are these? A. 90° B. 109.5° C. 120° D. 180° E. 45°



Answers

A trigonal bipyramidal geometry exhibits two characteristic bond angles. Which bond angles are these?

A. 90°

B. 109.5°

C. 120°

D. 180°

E. 45°

So in a tribunal planer molecule, you're going to have 120° bond angles, it's going to be flat in a plane. In a tetra hydro species, you're going to have 109.5° bond angles. Um, In an all cathedral species, you will have 90° between the ones that are sticking out of the plane and the ones that are in the plane, and then within the plane, three that are there going to be 120° apart. And then, um, lastly, for a linear species, everything is in a straight line. So you have 180°.

So now we're going to work on Problem 57 from Chapter five. In this problem, they ask us for four different molecules to determine the Elektronik and molecular geometries as well as the idealized bond angle, and also to disturb in if the bond angle in the molecule would be ideal. So in part, they were given, uh, PF three Foster is trifle ride, and so phosphorus. This compound here will have 26 electrons, five from phosphorus and 21 from the floor. Ian Adams So we can draw phosphorus with three Flory Adam's surrounding it. We can assign, uh, 21 Sorry, 18 electrons as lone pairs to the flooring Adams. So accounting the bonds. That leaves us with, uh, we've used up 24 electrons. So we add two more as a lone player to the phosphorus Adam Center at So now, based on this structure here, we can determine Elektronik geometry, uh, molecular geometry angle, idealized angle and whether it's ideal. So for Elektronik geometry, we have four electron groups surrounding the center Adams so forth. Four electron groups are electron geometry is tetra hydro. So if we had four bonds for bonded Adams, the molecular geometry would be tetra control as well. However, the molecular drop geometry doesn't see the lone pair. So if we take out one electrons from the Tetra usual structure will we get his tribunal tramadol, a triangular pure pyramid. And for Tetra hydro molecules, the idealized angle is 109.5 degrees. However, that's for four bonded Adams. When we have a long pair, it has higher electron density, and so it takes up more space, which pushes the other atoms closer together. So this angle and this molecule would not be ideal. In fact, it would be less than one of 9.5, so in part B were given at Silver BR to Rome in two. We have 14 electrons from bro mean six from Sulphur for a total of 20 electrons. So we have silver as our center Adam, with two broom in Adam's attached. We that uses up for electrons. We had 12 electrons as lone pairs to the to Broome Ian Adams. So we've used up four and 12 eso. We have four electrons left to assign. We assigned them to the, uh, center Adam sulfur, and so this is the correct structure based on the, uh, absence of formal charge, so we can draw the electron geometry, the molecular geometry again, the angle and whether it will be ideal. So once again, we have four electron groups, two broken arms into lone pairs. So our geometry for the Elektronik gentry will once again be Tetra hydro. This time, however, we've removed to Adam's Where's to electron groups, which we don't see in the molecular geometry instead of being tribunal parameter. When we removed one group, it will be bent similar to water. So again, the idealized angle for tension federal compounds is 109.5 degrees. However, because of these lone pairs, especially now that we have two lone pairs we're pushing these bro mean Adam's closer together. And so it will not be the idealized bonding in Part C were given C h. C l three, also known as chloroform. We have 21 elections from chlorine four from carbon one from hydrogen for a total of 26 electrons. We have a carbon atom surrounded by three chlorine in one hydrogen atoms. This takes up for electrons. Four bonds, eight electrons. So we have 18 left to a sign and we can assign six each and as three lone pairs to each chlorine atom, which will take up our electrons and every Adam as a knock tencor doing for hydrogen in no formal truck. So when we look at the Elektronik geometry like a geometry, the angle and whether it's ideal again, so again we have four electron groups. So are Elektronik. Geometry is Tetra hydro. However, this time we also we have four bonded Adams, so our molecular geometry is also Tetra hydro. The bond angle ideal bonding over tetra hydro compounds is one of 9.5 degrees, and even though we have some slight different, slightly different electro negativity between the chlorine and the hydrogen, Um, we do have four Bond and Adams, and the difference between chlorine and hydrant is not his greatest between the lone pairs in any other bonded items. So this bond angle will be very close to ideal. In party, we get carbon die sulfide CS, too. We have four elections from carbon 12 from sulphur, so we have 16 electrons total. We draw carbonized or center item, attach it to two silver atoms, which takes up for electrons So we have six left to assign their 12 left to assign. However, we see that, uh, just from the beginning that we're gonna need to use double bonds because we don't have enough electrons to assign lone pairs everywhere. So instead of adding three lone pairs, we're gonna add a double bond and too long pairs to each sulfur. Adam. So we've used up 16 electrons and oh, our formal charges are zero so we can move on to Elektronik. Geometry are all the geometry that we have to specify. So here we have only two electron groups, so the electron geometry is linear. Both of those are, uh, electron groups. So our molecular geometry are bonded. Adam sort of molecular geometry is linear. For linear molecules, the bond angle is 180 degrees. And here we don't have any deviation from that, since there are no lone pairs. So it is an ideal bombing

It turns out that the doctor he'd roll geometry has a 90 degree bond angles. Therefore, that is going to be the smallest bond angle. Then we go to Tetra. He troll with 100 9.5 and then tribunal plainer, with 120 degrees for its bond angles.

So c f four new structure. Mhm. There are four electron groups on carbon and all of them are occupied, so electronic geometry equals molecular geometry is attached to Eagle N F three. There are also also four electron groups around nitrogen. So electronic geometry is still type of hero. But we have a long pair. So the molecular geometry is tribunal. Your, uh middle Okay, O s, two oh f two too long Pairs on oxygen. So for the central atom also for electron groups, So electronic geometry still test the hero. But since we have two long pairs, we only consider this to for molecular geometry. So the molecular geometry is bent. H two s software is a central atom found with two hydrogen and sulfur has too long pairs. It's the same as O F two. So four electron groups around it. So electronic geometry Takahiro and then molecular geometry bent


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