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Subtract. $$ 0-8 $$
Okay, So let's hear in our subtraction as ambition. So that's negative. Zero. But we know that negative zero is this, though, so that zero post that number, so we just get that number.
Let's divide 10 and 84 hundreds by eight times. In order to do this, we must first move the decimal point in eight tons To make it a whole number eight, you must do the same thing to our dividend underneath the division symbol. Bring her decimal points straight up. Now this is acting as an 80 is not need it. So eight goes into 10 one time when times eight is eight. Subtract to get it. Bring down our eight. It goes into 28 three times. Three times eight is 24 28 minus 24 is for bring down or for it goes into 44 five times. Five times eight is 40. Subtract 44 minus 40 is for We don't have a remainder of zero, so it must add another zero to the end and bring it down. It goes into 45 times evenly. Five times eight is 40. When we subtract, we get a remainder of zero. Our quotient is equal to 13 and 55 hundreds
Hello and welcome. We're looking at chapter two, Section one, Problem 57. It's were given a continuation off the, uh, Ryker equation problems and were given new initial values. New ah, parameters. So X sub zero equals 0.8 and C equals 10. The instructions are the same. We wantto plot them, uh, kind of eyeball it. See what, um, see what's going on and then move on from there. So first, let's look good. Um, I need a spreadsheet for us, and we can see that. Oh, the values are oscillating. Goes from something close to zero to something close to three. It goes back and forth. They are getting closer together. They aren't getting farther apart, Uh, just constantly bouncing back and forth. Um, so it seems like the top half is converging to something 3.706 and the bottom half is converging to something. The values are getting closer and closer to something around that value. But the sequence as a whole is isn't converging to something together. So, uh, this out of him sequence oscillates. It does not appear to be convergence. All right, so this question, um, asked us, um plot enough terms to see how they behave. Does it appear to be convergent if not described the behaviour of the terms? We describe them as oscillating on, and so we are.
Here we have zero minus 9.9 That means zero is a redwood negative off 9.0 nine. And we know that zero is an additive identity. That means zero plus any number equals through the number itself. Therefore, zero plus negative off 9.9 becomes minus 9.9 That is over, and so