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(c) Use the F test to test for a significant relationship. Use0.05_State the null and alternative hypotheses_ Ho: B1 = 0 Ha: B1 #0 Ho: B1 2 0 Ha: B1 _ < 0 Ho: Bo...

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(c) Use the F test to test for a significant relationship. Use0.05_State the null and alternative hypotheses_ Ho: B1 = 0 Ha: B1 #0 Ho: B1 2 0 Ha: B1 _ < 0 Ho: Bo # 0 Ha: Bo = 0 Ho: Bo = 0 Ha: Bo # 0 Ho: B1 #0 Ha: 81 = 0Find the value of the test statistic. (Round your answer to two decimal places_Find the p-value. (Round your answer to three decimal places ) p-value

(c) Use the F test to test for a significant relationship. Use 0.05_ State the null and alternative hypotheses_ Ho: B1 = 0 Ha: B1 #0 Ho: B1 2 0 Ha: B1 _ < 0 Ho: Bo # 0 Ha: Bo = 0 Ho: Bo = 0 Ha: Bo # 0 Ho: B1 #0 Ha: 81 = 0 Find the value of the test statistic. (Round your answer to two decimal places_ Find the p-value. (Round your answer to three decimal places ) p-value



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Conduct each test at the $\alpha=0.05$ level of significance by determining (a) the null and alternative hypotheses, (b) the test statistic, (c) the critical value, and (d) the P-value. Assume the samples were obtained independently using simple random sampling. Test whether $p_{1} \neq p_{2} .$ Sample data: $x_{1}=28, n_{1}=254, x_{2}=36, n_{2}=301$

We want to conduct the following hypothesis test at alpha equals 0.5 minutes. We want to test whether P one does not equal pizza for example, data X one and one X two M two as follows, this question is testing an understanding of how to conduct a hypothesis test. Population proportion difference namely the difference population proportions between P. One and pizza. So we proceeded to a through the list below A. Is already listed here. So we state the null and alternative hypotheses. These are H R P one, P two, H A P one does not equal B two and B. We can take the test at as P at one P two P hat where we had a pool that's Penelope. So using a given numbers here we have Xena equals given formula people think 2.18 at 5% significance are critical value is zero over to question minus 1.6. The p value similarly is P equals dividends equals 0.0 to 92. Thus we can conclude since P is less than or equal to outfit and zero is in a critical region that we reject. H one

We want to conduct the following test at alpha equals 0.5 significance. We want to test whether or not the one is ready than P. To the sample data explaining close to 68 1.5 41 X 251 and two the five men 18. This is a hypothesis test to population proportions namely the difference of population proportions. We appreciate the steps A through E to solve first in a we say you know an alternative hypotheses. This is H R proportion of equal H a P one is greater than pizza and beer. The catholic test that so first we obtained P hot one X one over N one P had two X two over into and are proved estimated P hat X one plus X over N 1% too much are as follows. Thus we have zero because he had 11 if you had to over the denominator which is 3.8 next week at the critical value. So critical values in the table is 0 to 1.645 But we always protected testified percent confidence. R p value is pZ greater than 0.9 vulnerable proved. Thus we can conclude this lesson, ALfa or Anonima Critical Region we reject each month.

Uh huh. We want to conduct the following test that alpha equals 0.5 significance. We want to test whether P one was less than P two or is proportion for one is less than proportion for two. For sample data. X one and one X two and 2000 by this question. Is testing your understanding of how to conduct a hypothesis test and population proportions. So I appreciate the steps A through you here to solve first and a We state our hypotheses Rh not is that the proportions are equal the population one and two are H P one is less than B. Two and B. Because the test that so P at one is X one over N. One. He had to use extreme other end to our approval. S. P. Hot is excellent for 60 over N plus one attend to as is listed here. Thus we have Zeno as follows. Which is maybe +345 Critical value for 5% significance is from a Z. Tables over 2.645 Equivalently we confronted the P value as for a normal third, P z greater than natural values are not equal 3.65 Thus we see that since P is greater than alpha, angina is not the critical region, we fail to reject HR.

Yeah, we are conducting a hypothesis test and we have P values 0.6 for each of the alpha or significant values below. We want to decide whether or not our P value enables us to reject are null hypothesis H not before getting started. Let's remember a critical definition. You can reject H not when P is less than or equal to alpha. So in your P value is less than or equal to your significance level. You were allowed to reject the null hypothesis. So first starting off with part A alpha equals 0.50 point 06 is greater than 0.5 which means our P value is greater than our alpha value. And in this problem we do not reject the null hypothesis. Next part B 0.6 is less than or equal to alpha equals 0.1, so P is less than or equal to alpha here, which means that we can reject are no hypothesis. Finally, in part C alpha equals 0.6 0.06 is less than or equal to itself, so P is less than or equal to alpha. And again we can reject this no hypothesis.


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