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Use the graph below (titration of glycine with NaOH) to answer the following questions:glycine 12,010,0200,00 5Complete figure axes Name the X-axis and Y-axis in th...

Question

Use the graph below (titration of glycine with NaOH) to answer the following questions:glycine 12,010,0200,00 5Complete figure axes Name the X-axis and Y-axis in the figure_ How many pKa values does glycine have? Identify the pKa values in the plot by writing the number and identifying them with an arrow: Why does glycine hzve buffering ability? Would glycine be good physiological buffer?

Use the graph below (titration of glycine with NaOH) to answer the following questions: glycine 12,0 10,0 20 0,0 0 5 Complete figure axes Name the X-axis and Y-axis in the figure_ How many pKa values does glycine have? Identify the pKa values in the plot by writing the number and identifying them with an arrow: Why does glycine hzve buffering ability? Would glycine be good physiological buffer?



Answers

Use the following information to answer questions $3-6$ A student titrates some 1.0 $\mathrm{M} \mathrm{HCl}$ into 20.0 $\mathrm{mL}$ of methylamine $\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right),$ a weak base which only accepts a single proton. The following titration curve results: SEE GRAPH The buffer region of this titration is located: (A) Below 3.0 $\mathrm{mL}$ (B) Between 3.0 $\mathrm{mL}$ and 14.0 $\mathrm{mL}$ (C) Between 14.0 $\mathrm{mL}$ and 16.0 $\mathrm{mL}$ (D) Above 16.0 $\mathrm{mL}$

All right when we compare these pH values, but we need to consider, or the type of acid and base present, as well as how they're going to react with each other, Right? So sodium hydroxide is a strong base, strong basis, completely dissociated solution. So because all of those hydroxide ions will be dissociated, that means we're gonna have a more basic or a higher initial pH with sodium hydroxide is our base. Hey, at the equivalence point, if we have strong acid in strong base, we have sodium hydroxide and hydrochloric acid. That means that the pH is gonna be neutral, right? So a neutral ph of seven okay is present at that point because water is the only thing created other than the neutral salt. Right? So that doesn't affect the pH rights. That would be neutral or seven, right? Uh, the ending point, the post equivalence point. The pH is really driven by that excess of hydrogen ion from the hydroxyl, or gas in, so that would not change cry. So compared to our weak acid strong base, I'll be about the same way, because in terms of our strong acid that we have at that point, all of the base will be neutralized. So we'll be completely relying on the

In the Adam. There are three subatomic particles. These are going to be the pro Tom's in the nucleus with a positive charge. The neutrons neutrons in the nucleus with the neutral charge and then the electrons, which have a negative charge. The electrons are located in the shells surrounding the nucleus. The outer shell is going to be the Vaillant Shell, which is an important factor to remember. So in the nucleus, the number of protons quick, the number of protons is going to equal the atomic number. Number of protons equals atomic. No. So that's going to be a defining feature of which element it ISS, then the neutrons. You can count those in the nucleus as well to get the mass number, because mass number is equal to the protons plus the neutrons. So the message number can be variable. And this is going to be because the number of protons will stay the same. But the number of neutrons can vary, so you can have the same atomic number, same atomic number. But you can have a different mess number, different mass number. So if you have the same atomic number but different mass numbers, that's going to give you an isotope. Okay, so then we have electrons. I said electrons were in the space surrounding the nucleus at the very energy levels. So we're gonna look at the valence electrons, which are going to determine the types of chemical bonding that it can participate in, determines what's a number of valence Electrons determines types of chemical bonding. Okay, so we're gonna look at thes type two types of chemical bonds. First, we have Ionic bonds and Ionic bonds is are going to It's going to be a transfer of electrons, and I'm gonna use this as a little shorthand for electrons. Okay, so you can see the outer show of sodium does not have. It is not a full show, and neither is chloride in the outer shell. So it would take quite a bit of energy to fill the show of sodium. So it actually be easier to give that electron away and chloride It would take more energy to remove that all of those electrons on the outer shell rather than just taking that one electron from the sodium. So this way, both of the ions sodium in corridor ions are able to have full outer shells by interacting with each other so the sodium giving gives and then the chloride takes Okay, so then Covalin bonds are a little bit different. They're going to be sharing come electrons instead of the transfer of electrons. So oxygen needs eight in this out of show and the hydrogen needs to. So you kind of can see I did green electrons but oxygen and I did orange electrons for the hydrogen. And the hydrogen has the one in the outer shell, and then oxygen has six. So by sharing with two hydrogen, they're both ableto have full Vaillant shells. Oxygen has eight, and then the hydrogen has the to Another thing about water specifically is that, um it's a polar co Vaillant bond. So I'm just gonna write pore over here polar co feeling I don't now it's polar because be no oxygen. Is Electra negative based off of the trends on the periodic table. So since selecting negative, it's going to want to pull electron density towards it. So since electrons are negative, we're going to give oxygen at partial negative charge and since it's pulling that electron density towards itself towards the oxygen it's going to pull away from the hydrogen is their turn. Not very, Electra. Negative. And those were gonna have partial positives. This is creating a die poll moment because the auction is pulling more than density towards itself so that it's a little bit more stable. So we have a polar co Vaillant bond. Whereas if you had a carbon to hydrogen bond, they're both not very Electra Negative. We'll see not much of a difference in electro negativity, so it can't really pull that density. The carbon can't pull that density from the hydrogen electrons towards itself. So that would be a non Popes, a non polar cool Vaillant font. Okay, so if you look at the Polar Co. Vaillant Bonds, we see the partial charges I've put on them. So water is going to want to orient itself because they're gonna be a ton of water molecules, right? So that water molecule will orient itself so that the negative charges can actually be near the positive charges. Sudsy straw. A little molecule right here. Oxygen, hydrogen, nitrogen. Okay, so we said that this was partially positive. Partially positive, partially negative. So the partial positives and the partial negatives will actually be drawn towards each other, forming a hydrogen bond. And these can do this so they're not. It's not the same as a co Vaillant bond, but it's still a type of interaction.

Right, Um, in order to determine the pH at the words are the p K B form Ethel a mean right? We can use the graph because what we know is at the half equivalence point. Okay, which is where the half half the moles of acid are neutralized. Four base. So what we know is that at that point at our half equivalence point, the p k b of the metal mean will be equal to the p o h of the solution because it's a base. Right? So that's in the half. A goal of point. So we're half of that base has been neutralized by the peek a boo, a legal village. Now you do have to be careful because the units on the graph or pH so we're gonna have to do a little bit of math here. But when we look at this so we know the equivalence point was where we added, um, 15 millilitres of base, right. So 15 millilitres of bases the equivalence point divide that by two to get the half equivalence point, which is 7.5 millimeters. So at the half court, one point of 7.5 no leaders. Pray what we see on the graph is that the pH at 7.5 millilitres is equal to about 10.5. Right? So if the pH is 10.5 okay, then that means the P O. H is gonna be 14 minus 10.5, which is 3.5. And at that half equivalence point, the P O. H will be equal to the P K B.

In order to determine wth e concentration. The easiest way to do this is to look at the equivalence point, right? So we know that at the equivalence point, the moles of acid equal the moles of base. Right now for this particular reaction, it is a 1 to 1 ratio of acid to base, so we won't have to worry about any mole ratio. Specifically, we can just do a 1 to 1 calculation right now. We know on the HCL side, when we look at that hydrochloric acid that the polarity is one Moeller and that it's 15 millilitres, so you can keep that as 15 middle letters if you want to, or you can change it to leaders. Doesn't matter as long as you're consistent in the problem. All right. We're trying to determine the polarity of our base Guys, I'm just gonna put the polarity of the base there. And what we can see from the graph is that at the Colin's point, it takes 20 milliliters of base to reach that equivalence point. Right? So we're getting that 20 milliliters from the graph because that's where the graphics most upright, that's the equivalence point, right? So when we do the math here, right, Um, one times 15 divided by the 20 milliliters. Gives us a molar ity of 200.75 Moeller. Um, C h three N h two.


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