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Nonci^ Toa6RFJG| AIJ| K...

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Nonci^ Toa6RFJG| AIJ| K

Nonci^ Toa 6 R FJG| AIJ| K



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$\mathrm{K}_{4}\left[\mathrm{Fc}(\mathrm{CN})_{6}\right]$ rcacrs wirh oronc to give (a) $\mathrm{KNO}_{3}$ (b) $\mathrm{K}_{3}\left[\mathrm{Fc}(\mathrm{CN})_{C}\right]$ (c) $\mathrm{F} \mathrm{c}_{2} \mathrm{O}_{3}$ (d) $\mathrm{Ec}(\mathrm{O} \|)_{2}$

So here we have the equation. Five over six R is equal to one. Minus are over six. Norman six. The third thing we'll do is get rid of these two nominators with ours and the, um So I am going to multiply both by the common. At least coming multiple, which will be six are times six R minus six. You ended that both sides six hour time sticks ar minus six. So that gives us, um six are times six R minus six. Um, times five. So, actually this week 30. No, I won't do that yet. Times five by six are these will cancel. And then on this side, we have six our time. Six are minus six. Um, so distributed. That's the one. And now I have minus our times six. R six R minus six, all over six. R six and said these were careful. So that's really what we have now. So we have distribute this five, So I have 30. AR minus 30 is equal to, um 36 R squared minus 36. Are I distributed here and then all electric is minus six R squared. Okay, let's get over ours combined on the same side. So I have some, like terms my r squared. So I get 30 R minus 30 is equal to 30 r squared minus 36 are all right. Okay. And then I'll subtract 30 from both 30 are from both sides and add 30. I want to get everything on the same side. Time zero is equal to 30 r squared. Minus 66 are, um lust 30. So here I can see I can divide everything by three. And that will make all my numbers a little smaller. I will divide everything by three, not both sides. So I get zero is equal to 10 r squared minus 22 are plus 10. So I can actually divide by two. Here was well, so to on both sides. I'm just trying to simplify this down a little bit before I potentially use the quadratic formula. So my numbers are a little easier to work with, So I zero equals five r squared minus 11 are plus five. Yeah. Okay. So here and when he was the quadratic formula to solve this, um, I'm not gonna try to factor because that seems like it might not be successful, and I know the quadratic we will. It will be so in the eye and quite a pregnant. I have a values that's coefficient of r squared B with the cooperation of our and see, which is my constant and so my are will be equal to plus no r equals negative B so 11 plus or minus the square root of B squared bit of 11 squared minus for a see all over two A. So that gives us our sequel to 11 plus or minus 11. Square doesn't 121 um, minus four times five. Let's see, four times five is 20 times five again will be 100 divided by 10. And so we have our is equal to 11 plus or minus square 21/10 and I can't simplify the square of 21. Um, that has no perfect scraps. I can pull out gifts will be our final answer

So in this problem we are dividing, we are dividing very bulls with expose and so remember that we have. We have this rule that if we have a variable that is raised to a power of A and another variable that is raised to a power of B, remember, we have to have the same base. So this X has to be the same. And so if we divide that, we get something that looks like X to the A minus bi. So in this case, we have a variable K that's raised to the six power divided by another variable K racist experience will get six minus six is equal to zero. And so okay is raised to the zero power, which is one anything raised to zero power is one.

Okay, To get the least common denominator of these two fractions, I'm gonna look at the denominators. So here I have 15 K and four K. So if I look at or try defying the least common multiple between 15 K and four k, So first, like I'd want to look at 15 4 So the L C M, or the least common multiple of 15 and four is actually going to be 60. So with this, our denominator is gonna be 60 k so that's gonna be our least common denominator.

In this problem, we're being asked to identify any pairs of like terms. Well, let's start by talking about what late terms our life terms have to be two terms to have the same variable along with the same experiment. So for example, nine A and A squared would not be considered like terms because a square has an explanation too. And for this 98 term, the A's exponent is one. So because they are not the same exponent, those are not like terms. So let's see if we can identify any pairs of lake terms. Well nine a doesn't have a late term because no upper term has just in a for variable a square doesn't have a late term because no other term has a squared. Now let's look at 16, it doesn't have a variable. We'll discover term four doesn't have a variable as well. So those who are considered like terms so 16 and four next 16 B squared. Well, it's like term would be nine B squared because they hope that the variable B squared, so 16 B squared and nine B squared. And now we've identified all are pairs of like terms. Okay,


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