Not yet answeredMarked out of 5.00Flag questionProvide an appropriate response.The mean age of bus drivers in Chicago is 50.6 years. If a hypothesis test is perform...

Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section. A random sample of 860 births in New York State included 426 boys. Use a 0.05 significance level to test the claim that $51.2 \%$ of newborn babies are boys. Do the results support the belief that $51.2 \%$ of newborn babies are boys?

Now what is this statement? A researcher claims that the standard deviation off the life off a certain type of lawn mower is at most 2.8 years. So the standard deviation is at most two point ideas. So which means this is less than or equal to two point. This is going to be my null hypothesis. See, I have unequal to sign. So this will go into the hypothesis and my alternative hypothesis will be that my sigma or my sanity vision is greater than 2.8 years now. If I had object minor like this is what did I see? I will say that I have enough statistical evidence to say that the standard deviation is more than 2.8 years. Andi. If I failed to reject final hypothesis, I will say that I do not have enough statistical evidence to say that the standard deviation off the life of a certain type of lawn mower is more than 2.8 years. All right, this will be my answer

Properly. 23. Good. Today it's note new. It's smaller battery quickly. 45 and alternative than you. It's bigger than do you mind that having t is equal to X bar minus you note over s over square root off at which is equal to 48 minus 45/5 480.4 over a square root off 25 which is equal to 2.778 for could should be the The value is a number off or interval in the column of title table five containing the T value is in the row off the F equal toe number off size when this one is 20 five minus one, which is 24 so that we value his between oh point over five and a four point or one. So if they devalue smaller than significantly developing, the non hypothesis is rejected and they be value here is smaller than a 0.1. So we reject then on high processes. So we can say that there is sufficient evidence to support Beckley

In this exercise, we're going to be testing the hypotheses. The passenger car owners were late License plate lose at a higher rate than owners of commercial trucks. So we have data concerning two samples. One sample is, uh, off the passenger cars on another sample is for commercial tracks. So we're told that out of the 2049 passenger cars, 239 cars were elated the license plate laws, while out of 334 commercial trucks 45 violated the license plate laws. So we're going to test this hypothesis at the 0.5 significance level. Andi, uh, this being a one tailed test, the critical value is going to be 1.1 point 65 one 0.645 And our another hypothesis is going to be P one equals p two. Which is to say that the proportions are the same. Vous is the alternative report. This is P one is greater than p two, which means that there is a higher proportion for the passenger cars violating the license plate lose. So for us to get the test statistic, we need to substitute the values into the formula to get set. And in our case, P one heart is obtained from uh X one, which is 239 who have violated the laws divided by 2049. And for P two hot. We're going to halve the proportion 45 those who violated divided by the total sample size, which is 334. And when we substitute these values into the that statistic, this is what we have. So for P one hut, we have zero 0.117 minus p too hot, which is 0.135 And so that Z supposed to be minus zero. Then you divide that by the square root off PBA. When you walk out the value P bite 0.119 multiplied by Cuba, which is zero 0.88 one. And we need to divide that by, uh, n one, which is 2049. And after that we added to 0.11 90 speedball time 0.8 81 Cuba divide by end two, which is 300 that you for, And when you simplify, you get the value off that the completed values that is negative 0.942 So the critical value here is going to be the negative critical value. And in this case, when you compare there using this craft, you'll see that we come. The critic The rejection that's the critical region is at negative 1.645 When we shared this region, we'll be able to see the rejection region. So when we place the calculated the test statistic in this carve, it will be before the critical value that is negative 0.942 And for that we make the conclusion to feel to reject denial hypothesis because the test statistic is not within the critical region. Yeah, so this claim is so there is not sufficient evidence to support the claim that the car owners were lit license plate lose at higher it than owners off the commercial trucks. Now we need to create a 95 a confidence interval for this, And to do that, we need to get imagine off era E by substituting the values into the formula here and e his zero point 03 29 and when we substitute the values will get that they call confidence Interval will be. Uh huh. Negative 0.509 It's less than P one, minus P. Two. She's less than zero 0.1 49 and you can notice that zero is within the confidence interval. In other words, zero they enter. The confidence interval contains zero. And because the confidence interval contain zero, there is not significant is not there is a significant difference between there is not a significant difference between the two proportions. In other words, there is not enough evidence to support the claim that the car owners of they're left license plate lose at a hair. Written the owners off commercial tracks. So both the hypothesis test on the confidence interval. I agree that there is not sufficient evidence to support the claim that car owners valued lesson tracks. Leave clues, uh, at a higher rate

In this question, we're asked to state the no and alternative hypotheses that would be used for the following claims. So in a the claim is there is a difference in mean age of employees at two companies. So the no hypothesis is the state of of no difference. So and say the mean age of employees at company A minus the mean age of employees. The company B is zero. So the alternative hypothesis is that there is a difference in ages, which is the same as saying difference between the means is not equal to zero for be the mean of population. One is greater than the mean of population to So the no hypothesis would be that the mean of population one minus mean of population to is equal to zero. And the alternative hypothesis is the claim that the mean of population one is greater than that of to which is, I mean one minus mean of to is greater than zero. The part see the mean yield of sunflower seeds in North Dakota is less than the mean yield in South Dakota. So the no hypothesis is that they're the same, which is the mean in south minus the mean in north is equal to zero. The alternative hypothesis is that the mean in South Dakota is greater than the mean in North Dakota means that this would be greater than zero for party. The claim is there is no difference in the mean number of hours spent studying between male and female students. So the no hypothesis is by convention, no difference between two populations. So we'll state that clean as the no hypothesis that is, there is no difference in the mean number of hours. So we can state that as the mean number of hours female study minus the number of hours that male study is equal to zero. There is no difference. So an alternative hypothesis to that would be that I mean hours spent by female studying, minus the mean our spent by mail. Studying is not equal to zero.