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Convert the following into canonical form .F(AB) -A + B AB F(ABC) = AB AC BC B + C F(ABCD) = A + B CD F(ABCD) AB ICD AJBCDConvert the following Boolean Equations in...

Question

Convert the following into canonical form .F(AB) -A + B AB F(ABC) = AB AC BC B + C F(ABCD) = A + B CD F(ABCD) AB ICD AJBCDConvert the following Boolean Equations into NAND FORM and draw the Logical Circuit in NAND Form These example require the use of De-_ Morgans rulesF =A+B+ C + D F =AA + AC + AB BC F = ABIC + IAIBC AIBC F = /(A+B) + IC F = AJB IAB23 24 2526 Example 25 but using only four; 2 input NAND galesFind the DUAL Boolean Equation for the following and simplify.F = AJB BIC F = (IA + B

Convert the following into canonical form . F(AB) -A + B AB F(ABC) = AB AC BC B + C F(ABCD) = A + B CD F(ABCD) AB ICD AJBCD Convert the following Boolean Equations into NAND FORM and draw the Logical Circuit in NAND Form These example require the use of De-_ Morgans rules F =A+B+ C + D F =AA + AC + AB BC F = ABIC + IAIBC AIBC F = /(A+B) + IC F = AJB IAB 23 24 25 26 Example 25 but using only four; 2 input NAND gales Find the DUAL Boolean Equation for the following and simplify. F = AJB BIC F = (IA + BJ(C ID) F = IABC ABIC AIB Apply De-Morgans rule to the results of 27-29 to obtain NAND or NOR (whichever is conrenient).



Answers

Write each of the following expressions in the form a + bi.

And in this question, we're going to talk about conditional statements and by conditional statements. Right now you've been given what's if X then why and if Why? Then X. Thanks. Mhm. To change it into a by conditional instead of two conditional statements, we would want to say X. If and only if. Why? So the statement you would want to write yes. E is between A and C. Yeah. If and only if. Yeah. Okay. Which is often a breathe abbreviated I f f A B plus B C equals act That is your by conditional. That replaces the two conditional.

We need to find two matrices and be such that a B equals B. So out off the two matrices, let a be a unit matrix that is 100 va on Let us consider be Toby Quito. 1234 So the left inside that is a B will become equal toe. 1001 multiplied with one don't 34 which is equal to one. Do three and four on the right. Inside B A will be equal to 1234 multiplied with 1001 which is equal to one YOU'LL three and four. So therefore, a B is equal toe B A If is ones it'll 01 on B is equal to 1234

Hello. So uh this is the solution to uh the question. So this is for the uh a park with N. G. D. B. In 441 respectively respectively sorry. And then for the B. We also have that uh the does the N. G. D. Four B. 652 in the C. Part? We got uh they're supposed to be It's supposed to be a. three. So you got a straight three. Okay. So that is not uh for the scholarship question, hopefully you understand it. Thank you very much.

And we have to write each of the following expression in the form of A plus B. I. So In part a we have given 11 -12 -25. So we know that ι is square is equal to -1 and five square is equal to 25. So we can write 11 minus and the road five into ι Square. So this will be equal to 11 minus five iota. So this is the answer for part eight. Now in part B we have given minus four plus minus And the road -36 divided by two. So again here 36 is equal to six square. So we can write, it is a call to minus four plus minus, it is six into iota Divided by two. So this will be called to -2 Plus -3 ι. So this is in the form of A plus V. A. Now in part C We have given eight plus And road -3 so we can write it eight Plus Route three. There you go. Thank you.


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