Let's work on this problem. This problem is from organic chemistry and is based on the systematic maimings of organic compounds. Here we are given some Branch Elkins diesel cases. We will provide the systematic means. So let's start with the first one. This is the first compound. If we count the number of carbon atoms in the parent chain, we can write 12345678 and nine. So there are nine carbon atoms in the parent chain. And at 4th and 5th Carbon atom, there is one metal group. So this compound is named as four. Five. Die me tile. No name. Then we have the next compound where there are seven calculations in the parent chain, this is one, two, 34 567 And at carbon number three and four, there are two metal groups on each carbon atom. So we can write the name of this compound as three, 34 full. A promise style. Have thine. Then we have the next structure which contain eight carbon atoms. In the parent chain. We can number from this side. One, two, three full. Five, 67 and eight. These are the carbon atoms of parents chain and all this parent chain at carbon number three, there is one metal group. Carbon number four has one metal group. Carbon number five has two metal groups. So we can write the name of the compound as three, four, five, five Tetra metal octane than we have The last structure where the parent train contains six carbon atoms. And out of the six carbon atoms carbon number two, three and four each has a metal group connected to this. So this compound can be named systematically as to 34 Try metal eggs in These are the systematic names of the Given Branch Elkins.